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{
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"name": "",
"signature": "sha256:63d249c5c7d8f61cc0f4f00c6cd8c5c2324721f135176069c7c632118f5681cc"
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"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 05: Energy methods"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.1 Pg.No.116"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"from __future__ import division\n",
"import math\n",
"\n",
"A=1800 # cross sectional area (mm^2)\n",
"E=200000 #youngs modulus (N/mm^2)\n",
"sum_FLdFdP_B=1268*10**6 #(N.mm^2)\n",
"sum_FLdFdP_D=880*10**6 #(N.mm^2)\n",
"\n",
"del_Bv=sum_FLdFdP_B/A/E\n",
"del_Dh=sum_FLdFdP_D/A/E\n",
"\n",
"print \"\\ndeflection at point B =%2.2f mm\\n\"%(del_Bv)\n",
"print \"deflection at point D =%2.2f mm\\n\"%(del_Dh)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"\n",
"deflection at point B =3.52 mm\n",
"\n",
"deflection at point D =2.44 mm\n",
"\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.9 Pg.No.142"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"from __future__ import division\n",
"import math\n",
"import numpy as np\n",
"\n",
"a=np.array([[4.32,2.7],[2.7,11.62]])\n",
"b=np.array([27.1,48.11])\n",
"x=np.linalg.solve(a,b)\n",
"print \"\\nX1 = %1.2f kN & R2 = %1.2f kN\\n\"%(x[0],x[1]) "
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"\n",
"X1 = 4.31 kN & R2 = 3.14 kN\n",
"\n"
]
}
],
"prompt_number": 8
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.10 Pg.No.144"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"from __future__ import division\n",
"import math\n",
"\n",
"E=200000 #youngs modulus (N/mm^2)\n",
"A=200 #cross sectional area of each member (mm^2)\n",
"a=7*10**-6 #linear coefficient of heating (/C)\n",
"L=3*10**3 #length of BC (mm)\n",
"T=30 #temperature of truss (C)\n",
"sum_f2L=48000\n",
"\n",
"expansion=L*T*a\n",
"a11=sum_f2L/A/E\n",
"X1=-0.63/a11 #compatibility condition\n",
"print \"\\nX1 = %5.0f N\\n\"%(X1)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"\n",
"X1 = -525 N\n",
"\n"
]
}
],
"prompt_number": 14
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.12 Pg.No.151"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"from __future__ import division\n",
"import math\n",
"\n",
"def_C=-1.05-.6 #deflection at C (mm)\n",
"L=300 #length of cantilever (mm)\n",
"\n",
"theta_B=math.atan(def_C/L)\n",
"print \"\\ndeflection at C = %2.3f degree\\n\"%(theta_B*180/math.pi) "
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"\n",
"deflection at C = -0.315 degree\n",
"\n"
]
}
],
"prompt_number": 16
},
{
"cell_type": "code",
"collapsed": false,
"input": [],
"language": "python",
"metadata": {},
"outputs": []
}
],
"metadata": {}
}
]
}
|
