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{
"metadata": {
"name": "",
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"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter12-Plastic Behaviour of Solids"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex1-pg345"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#calculate plastic yeilding and max allowable stress and axial stress and transverse stress and total elonganation for stability in meter\n",
"alpha=45.\n",
"sigmayp=35.*10**6 ##Pa\n",
"k=840.##MPa\n",
"n=0.2\n",
"L0=3 ##m\n",
"Aad=10.*10**-5 ##m**2\n",
"Acd=10.*10**-5 ##m**2\n",
"Abd=15.*10**-5 ##m**2\n",
"\n",
"P=sigmayp*Abd+2.*sigmayp*Aad*math.cos(45/57.3)\n",
"print'%s %.2f %s'%(\"plastic yeilding in N is= \",P,\"\")\n",
"sigma=k*n**n\n",
"print'%s %.2f %s'%(\"maxi allowable stress in MPa is= \",sigma,\"\")\n",
"epsilon1=n\n",
"print'%s %.2f %s'%(\"axial stress is= \",epsilon1,\"\")\n",
"epsilon2=-0.1\n",
"print'%s %.2f %s'%(\"transverse stress is= \",epsilon2,\"\")\n",
"epsilon3=-0.1\n",
"print'%s %.2f %s'%(\"transverse stress is= \",epsilon3,\"\")\n",
"z=3*n\n",
"print'%s %.2f %s'%(\"total elongation for stability in meter is= \",z,\"\")\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"plastic yeilding in N is= 10200.03 \n",
"maxi allowable stress in MPa is= 608.81 \n",
"axial stress is= 0.20 \n",
"transverse stress is= -0.10 \n",
"transverse stress is= -0.10 \n",
"total elongation for stability in meter is= 0.60 \n"
]
}
],
"prompt_number": 1
}
],
"metadata": {}
}
]
}
|
