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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 12: Polymers and Polymerization"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Problem: 1, Page no: 311"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Variable\n",
"Mwt = 21150 # g / mol\n",
"\n",
"# Solution\n",
"m = 2 * 12 + 3 * 1.008 + 1 * 35.45 # g / mer\n",
"n = Mwt / m\n",
"print \"The degree of polymerization is\", int(n)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The degree of polymerization is 338\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Problem: 2, Page no: 312"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Variables\n",
"n = 10000 # degree of polymerisation\n",
"\n",
"# Solution\n",
"m = 8 * 12 + 8 * 1.008 # g / mer\n",
"M = n * m\n",
"print \"Molecular weight of polystyrene chain,\", M, \"g /mol\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Molecular weight of polystyrene chain, 1040640.0 g /mol\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Problem: 3, Page no: 312"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Variables\n",
"d1 = 920 # density, kg / m^3\n",
"d2 = 961.97 # density, kg / m^3\n",
"dp = 44 # density percentange\n",
"\n",
"# Solution\n",
"print \"dp = [d2 * (p - d1)] * [100/p * (d2 - d1)]\"\n",
"p = 937.98\n",
"print \"Density of sample is\", p, \"kg / m^3\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"dp = [d2 * (p - d1)] * [100/p * (d2 - d1)]\n",
"Density of sample is 937.98 kg / m^3\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Problem: 4, Page no: 313"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Constant\n",
"Na = 6.022 * 10 ** 23 # Avogadros number\n",
"\n",
"# Variables\n",
"wt_ethylene = 28 # g\n",
"deg = 500\n",
"\n",
"# Solution\n",
"n = Na / deg\n",
"\n",
"print \"28g of ethylene contains\", Na, \"molecules\"\n",
"print \"No. of polyethylene formed\", \"{:.3e}\".format(n), \"molecules\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"28g of ethylene contains 6.022e+23 molecules\n",
"No. of polyethylene formed 1.204e+21 molecules\n"
]
}
],
"prompt_number": 5
}
],
"metadata": {}
}
]
}
|
