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diff --git a/testing_by_test/vivek.ipynb b/testing_by_test/vivek.ipynb deleted file mode 100644 index 27d3c041..00000000 --- a/testing_by_test/vivek.ipynb +++ /dev/null @@ -1,618 +0,0 @@ -{ - "cells": [ - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "# Chapter No.3 : The cellular concept system design fundamentals" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 3.1 Page No.61" - ] - }, - { - "cell_type": "code", - "execution_count": 14, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - "\n", - " The number of channels available per cell for 4-cell reuse system = 165 channels\n", - "\n", - " One control channel and 160 voice channels would be assigned to each cell.\n", - "\n", - " \n", - " The number of channels available per cell for 7-cell reuse system = 95 channels\n", - "\n", - " Each cell would have one control channel, four cells would have 90 voice channels and three cells would have 91 voice channels.\n", - "\n", - " \n", - " The number of channels available per cell for 12-cell reuse system = 55 channels\n", - "\n", - " Each cell would have one control channel, eight cells would have 53 voice channels and four cells would have 54 voice channels.\n" - ] - } - ], - "source": [ - "from math import ceil\n", - "# To compute the number of channels available per cell for a)four-cell reuse system a)seven-cell reuse system a)12-cell reuse system\n", - "\n", - "# Given data\n", - "B=33*10**6# # Total bandwidth allocated to particular FDD system in Hz\n", - "Bc=25*10**3# # Bandwidth per channel in Hz\n", - "Nc=2# # Number of simplex channels\n", - "Bc=Bc*Nc# # Channel bandwidth in Hz\n", - "\n", - "Ntotal=B/Bc# # Total number of channels\n", - "\n", - "#a) To compute the number of channels available per cell for four-cell reuse system\n", - "N=4# # frequency reuse factor\n", - "chpercell=Ntotal/N# # number of channels available per cell for four-cell reuse system\n", - "\n", - "# Displaying the result in command window\n", - "print \"\\n The number of channels available per cell for 4-cell reuse system = %0.0f channels\"%(chpercell)\n", - "print \"\\n One control channel and 160 voice channels would be assigned to each cell.\"\n", - "\n", - "# b) To compute the number of channels available per cell for seven-cell reuse system\n", - "N=7# # frequency reuse factor\n", - "chpercell=ceil(Ntotal/N)# # number of channels available per cell for seven-cell reuse system\n", - "\n", - "# Answer is varrying due to round-off error\n", - "\n", - "# Displaying the result in command window\n", - "print \"\\n \\n The number of channels available per cell for 7-cell reuse system = %0.0f channels\"%(chpercell)\n", - "print \"\\n Each cell would have one control channel, four cells would have 90 voice channels and three cells would have 91 voice channels.\"\n", - "\n", - "# c) To compute the number of channels available per cell for 12-cell reuse system\n", - "N=12# # frequency reuse factor\n", - "chpercell=Ntotal/N# # number of channels available per cell for seven-cell reuse system\n", - "\n", - "# Displaying the result in command window\n", - "print \"\\n \\n The number of channels available per cell for 12-cell reuse system = %0.0f channels\"%(chpercell)\n", - "print \"\\n Each cell would have one control channel, eight cells would have 53 voice channels and four cells would have 54 voice channels.\"" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 3.2 Page No.72" - ] - }, - { - "cell_type": "code", - "execution_count": 1, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - "\n", - " Signal to noise ratio for n=4 with frequency reuse factor N=7 = 18.66 dB\n", - "\n", - " Signal to noise ratio for n=3 with frequency reuse factor N=7 = 12.05 dB\n", - "\n", - " Signal to noise ratio for n=3 with frequency reuse factor N=12 = 15.56 dB\n", - "\n", - " Since SIR is for n=3 with frequency reuse factor N=7 greater than the minimum required, so N=12 is used.\n" - ] - } - ], - "source": [ - "from math import sqrt, log10\n", - "from __future__ import division\n", - "# To find frequency reuse factor for path loss exponent (n) a)n=4 b)n=3\n", - "\n", - "# Given data\n", - "SIdB=15# # Signal to interference(dB)\n", - "io=6# # Number of cochannel cell\n", - "\n", - "# For n=4\n", - "n1=4# # Path loss exponent\n", - "N1=7# # First consideration: frequency reuse factor N=7\n", - "DR1=sqrt(3*N1)# # Co-channel reuse ratio\n", - "si1=(1/io)*(DR1)**n1# # Signal to interference\n", - "sidB1=10*log10(si1)# # Signal to interference(dB)\n", - "\n", - "# For n=3\n", - "n2=3# # Path loss exmponent\n", - "si=(1/io)*(DR1)**n2# # Signal to interference for first consideration: frequency reuse factor N=7\n", - "sidB=10*log10(si)# # Signal to interference(dB)\n", - "\n", - "N2=12# # second consideration : frequency reuse factor N=12 since sidB<SIdB \n", - "DR2=sqrt(3*N2)# # Co-channel reuse ratio\n", - "si2=(1/io)*(DR2)**n2# # Signal to interference\n", - "sidB2=10*log10(si2)# # Signal to interference(dB)\n", - "\n", - "# Displaying the result in command window\n", - "print \"\\n Signal to noise ratio for n=4 with frequency reuse factor N=7 = %0.2f dB\"%(sidB1)\n", - "print \"\\n Signal to noise ratio for n=3 with frequency reuse factor N=7 = %0.2f dB\"%(sidB)\n", - "print \"\\n Signal to noise ratio for n=3 with frequency reuse factor N=12 = %0.2f dB\"%(sidB2)\n", - "print \"\\n Since SIR is for n=3 with frequency reuse factor N=7 greater than the minimum required, so N=12 is used.\"" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 3.4 Page No.80" - ] - }, - { - "cell_type": "code", - "execution_count": 16, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - "\n", - " Total number of users for 1 channel = 1\n", - "\n", - " Total number of users for 5 channel = 11\n", - "\n", - " Total number of users for 10 channel = 40\n", - "\n", - " Total number of users for 20 channel = 111\n", - "\n", - " Total number of users for 100 channel = 809\n" - ] - } - ], - "source": [ - "# To find number of users for Number of channels (C) a)C=1 b)C=5 c)C=10 d)C=20 e)C=100\n", - "\n", - "# Given data\n", - "GOS=0.005# #G rade of Service\n", - "Au=0.1# # Traffic intensity per user\n", - "\n", - "# a)To find number of users for C=1\n", - "C1=1# # Number of channels\n", - "A1=0.005# # Total traffic intensity from Erlangs B chart\n", - "U1=(A1/Au)# # Number of users\n", - "U1=1# # Since one user could be supported on one channel\n", - "\n", - "# b)To find number of users for C=5\n", - "C2=5# # Number of channels\n", - "A2=1.13# # Total traffic intensity from Erlangs B chart\n", - "U2=round(A2/Au)# # Number of users\n", - "\n", - "# c)To find number of users for C=10\n", - "C3=10# # Number of channels\n", - "A3=3.96# # Total traffic intensity from Erlangs B chart\n", - "U3=round(A3/Au)# # Number of users\n", - "\n", - "# Answer is varrying due to round off error\n", - "\n", - "# d)To find number of users for C=20\n", - "C4=20# # Number of channels\n", - "A4=11.10# # Total traffic intensity from Erlangs B chart\n", - "U4=round(A4/Au)# # Number of users\n", - "\n", - "# Answer is varrying due to round off error\n", - "\n", - "# e)To find number of users for C=100\n", - "C5=100# # Number of channels\n", - "A5=80.9# # Total traffic intensity from Erlangs B chart\n", - "U5=round(A5/Au)# # Number of users\n", - "\n", - "# Displaying the result in command window\n", - "print \"\\n Total number of users for 1 channel = %0.0f\"%(U1)\n", - "print \"\\n Total number of users for 5 channel = %0.0f\"%(U2)\n", - "print \"\\n Total number of users for 10 channel = %0.0f\"%(U3)\n", - "print \"\\n Total number of users for 20 channel = %0.0f\"%(U4)\n", - "print \"\\n Total number of users for 100 channel = %0.0f\"%(U5)" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 3.5 Page No.83" - ] - }, - { - "cell_type": "code", - "execution_count": 2, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - "\n", - " Total number of users in system A = 47280\n", - "\n", - " The percentage market penetration of system A = 2.36\n", - "\n", - " \n", - " Total number of users in system B = 44100\n", - "\n", - " The percentage market penetration of system B = 2.205\n", - "\n", - " \n", - " Total number of users in system C = 43120\n", - "\n", - " The percentage market penetration of system C = 2.156\n", - "\n", - " \n", - " Total number of users in all 3 systems = 134500\n", - "\n", - " The combined Market penetration percentage of all systems = 6.725\n" - ] - } - ], - "source": [ - "from __future__ import division\n", - "# To find number of users for a)system A b)system B c)system C\n", - "\n", - "# Given data\n", - "GOS=0.02# # Grade of Service (Probability of bloacking)\n", - "lamda=2# # Average calls per hour\n", - "H=(3/60)# # Call duration in seconds\n", - "\n", - "Au=lamda*H# # Traffic intensity per user\n", - "\n", - "# a)To find number of users for System A\n", - "C1=19# # Number of channels used\n", - "A1=12# # Traffic intensity from Erlang B chart\n", - "U1=round(A1/Au)# # Number of users per cell\n", - "cells1=394\n", - "TU1=U1*cells1# # Total number of users\n", - "MP1=TU1/(2*10**6)*100# # Market penetration percentage\n", - "\n", - "# b)To find number of users for System B\n", - "C2=57# # No. of channels used\n", - "A2=45# # Traffic intensity from Erlang B chart\n", - "U2=round(A2/Au)# # Number of users per cell\n", - "cells2=98\n", - "TU2=U2*cells2# # Total no. of users\n", - "MP2=TU2/(2*10**6)*100# # Market penetration percentage\n", - "\n", - "# c)To find number of users for System C\n", - "C3=100# # Number of channels used\n", - "A3=88# # traffic intensity from Erlang B chart\n", - "U3=round(A3/Au)# # Number of users per cell\n", - "cells3=49\n", - "TU3=U3*cells3# # Total no. of users\n", - "MP3=TU3/(2*10**6)*100# # Market penetration percentage\n", - "\n", - "TU=TU1+TU2+TU3# # Total number of users in all 3 systems\n", - "MP=TU/(2*10**6)*100# # Combined Market penetration percentage\n", - "\n", - "# Displaying the result in command window\n", - "print \"\\n Total number of users in system A = %0.0f\"%(TU1)\n", - "print \"\\n The percentage market penetration of system A = %0.2f\"%(MP1)\n", - "print \"\\n \\n Total number of users in system B = %0.0f\"%(TU2)\n", - "print \"\\n The percentage market penetration of system B = %0.3f\"%(MP2)\n", - "print \"\\n \\n Total number of users in system C = %0.0f\"%(TU3)\n", - "print \"\\n The percentage market penetration of system C = %0.3f\"%(MP3)\n", - "print \"\\n \\n Total number of users in all 3 systems = %0.0f\"%(TU)\n", - "print \"\\n The combined Market penetration percentage of all systems = %0.3f\"%(MP)" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 3.6 Page No.84" - ] - }, - { - "cell_type": "code", - "execution_count": 2, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - "\n", - " Number of cells in given system = 31 cells\n", - "\n", - " \n", - " Number of channels per cell in given system = 95 channels/cell\n", - "\n", - " \n", - " Traffic intensity in given system = 84 Erlangs/cell\n", - "\n", - " \n", - " Maximum carried traffic in given system = 2604 Erlangs\n", - "\n", - " \n", - " Total number of users = 86800 users\n", - "\n", - " \n", - " Number of mobiles per unique channel = 130 mobiles/channel\n", - "\n", - " \n", - " Theoretically maximum number of served mobiles is the number of available channels in the system.\n", - "\n", - " Theoretical Maximum number of users could be served at one time = 2945 users\n", - "It is 3.4% of customer base.\n" - ] - } - ], - "source": [ - "# To find a)Number of cells in given area b)Number of channels/cell c)Traffic intensity per cell d)Maximum carried traffic e)Total number of users for 2% GOS f) Number of mobiles per unique channel g)Maximum number of users could be served at one time\n", - "\n", - "# Given data\n", - "Area=1300# # Total coverage area in m**2\n", - "R=4# # Radius of cell in m\n", - "N=7# # Frequecy reuse factor\n", - "S=40*10**6# # Allocated spectrum in Hz\n", - "Ch=60*10**3# # Channel width in Hz\n", - "\n", - "# a)Number of cells\n", - "CA=2.5981*R**2# # Area of hexagonal cell in m**2\n", - "Nc=round(Area/CA)# # Number of cells\n", - "\n", - "# Displaying the result in command window\n", - "print \"\\n Number of cells in given system = %0.0f cells\"%(Nc)\n", - "\n", - "# b)Number of channels/cell\n", - "C1=round(S/(Ch*N))# # Number of channels\n", - "\n", - "# Displaying the result in command window\n", - "print \"\\n \\n Number of channels per cell in given system = %0.0f channels/cell\"%(C1)\n", - "\n", - "# c) Traffic intensity per cell\n", - "C1=95# # Number of channels from b)\n", - "GOS=0.02# # Grade of service\n", - "A=84# # Traffic intensity from Erlang B chart\n", - "\n", - "# Displaying the result in command window\n", - "print \"\\n \\n Traffic intensity in given system = %0.0f Erlangs/cell\"%(A)\n", - "\n", - "# d)Maximum carried traffic\n", - "traffic=Nc*A# # Maximum carried traffic\n", - "\n", - "# Displaying the result in command window\n", - "print \"\\n \\n Maximum carried traffic in given system = %0.0f Erlangs\"%(traffic)\n", - "\n", - "# e)Total number of users for 2% GOS \n", - "trafficperuser=0.03# # Given traffic per user\n", - "U=traffic/trafficperuser# # Total number of users\n", - "\n", - "# Displaying the result in command window\n", - "print \"\\n \\n Total number of users = %0.0f users\"%(U)\n", - "\n", - "# f) Number of mobiles per unique channel\n", - "C=666# # Number of channels\n", - "mobilesperchannel=round(U/C)# # Number of mobiles per unique channel\n", - "\n", - "# Displaying the result in command window\n", - "print \"\\n \\n Number of mobiles per unique channel = %0.0f mobiles/channel\"%(mobilesperchannel)\n", - "\n", - "# g)Maximum number of users could be served at one time\n", - "print \"\\n \\n Theoretically maximum number of served mobiles is the number of available channels in the system.\"\n", - "C=C1*Nc# # Maximum number of users could be served at one time\n", - "\n", - "# Displaying the result in command window\n", - "print \"\\n Theoretical Maximum number of users could be served at one time = %0.0f users\"%(C)\n", - "print \"It is 3.4% of customer base.\"" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 3.7 Page 85" - ] - }, - { - "cell_type": "code", - "execution_count": 2, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - "\n", - " Number of users per square km in given system = 62 users/sq km\n", - "\n", - " \n", - " Percentage of probability that delayed call have to wait longer than t=10 sec = 56.29 percent\n", - "\n", - " \n", - " Percentage of probability that call is delayed more than 10 sec = 2.81 percent\n" - ] - } - ], - "source": [ - "from math import exp\n", - "# To find a)number of users per square km b)probability that delayed call have to wait longer than t=10sec c)probability that call is delayed more than 10 sec\n", - "\n", - "# Given data\n", - "R=1.387# # Radius of cell in m\n", - "Area=2.598*R**2# # Area of hexagonal cell in m**2\n", - "cellpercluster=4# # Number of cells/cluster\n", - "channels=60# # Number of channels\n", - "\n", - "channelspercell=channels/cellpercluster# # Number of channels per cell\n", - "\n", - "# a)To find number of users per square km\n", - "A=0.029# # Traffic intensity per user\n", - "delayprob=0.05# # Grade of service\n", - "traffic=9# # Traffic intensity from Erlang chart C\n", - "U1=traffic/A# # Total number of users in 5sq.km.\n", - "U=round(U1/Area)# # Number of users per square km\n", - "\n", - "# Displaying the result in command window\n", - "print \"\\n Number of users per square km in given system = %0.0f users/sq km\"%(U)\n", - "\n", - "# b)To find the probability that delayed call have to wait longer than t=10sec\n", - "lamda=1# # Holding time\n", - "H1=A/lamda# # Duration of call\n", - "H=H1*3600# # Duration of call in second\n", - "t=10\n", - "Pr=exp(-(channelspercell-traffic)*t/H)*100# # probability that delayed call have to wait longer than t=10sec.\n", - "\n", - "# Displaying the result in command window\n", - "print \"\\n \\n Percentage of probability that delayed call have to wait longer than t=10 sec = %0.2f percent\"%(Pr)\n", - "\n", - "# c)To find the probability that call is delayed more than 10 sec\n", - "Pr10=delayprob*Pr# # probability that call is delayed more than 10 sec\n", - "\n", - "# Displaying the result in command window\n", - "print \"\\n \\n Percentage of probability that call is delayed more than 10 sec = %0.2f percent\"%(Pr10)" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 3.8 Page 89" - ] - }, - { - "cell_type": "code", - "execution_count": 3, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - "\n", - " Number of channels without use of microcell = 300 channels\n", - "\n", - " \n", - " Number of channels with the use of lettered microcells = 660 channels\n", - "\n", - " \n", - " Number of channels if all base stations are replaced by microcells = 1020 channels\n" - ] - } - ], - "source": [ - "# To find number of channels in 3 km by 3 km square centered around A in Figure 3.9 for a)without use of microcell b)with the use of lettered microcells c)all base stations are replaced by microcells\n", - "\n", - "# Given data\n", - "R=1# # Cell radius in km\n", - "r=0.5# # Micro-cell radius in km\n", - "Nc=60# # Number of channels in base station\n", - "\n", - "# a)To find number of channels without use of microcell\n", - "Nb1=5# # Number of base stations in given area\n", - "N1=Nb1*Nc# # Number of channels without use of microcell\n", - "\n", - "# b)To find number of channels with the use of lettered microcells\n", - "Nb2=6# # Number of lettered microcells\n", - "Nb2=Nb1+Nb2# # Total number of base stations in given area\n", - "N2=Nb2*Nc# # Number of channels with the use of lettered microcells\n", - "\n", - "# c)To find number of channels if all base stations are replaced by microcells\n", - "Nb3=12# # Number of all the microcells\n", - "Nb3=Nb1+Nb3# # Total number of base stations in given area\n", - "N3=Nb3*Nc# # Number of channels if all base stations are replaced by microcells\n", - "\n", - "# Displaying the result in command window\n", - "print \"\\n Number of channels without use of microcell = %0.0f channels\"%(N1)\n", - "print \"\\n \\n Number of channels with the use of lettered microcells = %0.0f channels\"%(N2)\n", - "print \"\\n \\n Number of channels if all base stations are replaced by microcells = %0.0f channels\"%(N3)" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 3.9 Page 92" - ] - }, - { - "cell_type": "code", - "execution_count": 4, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - "\n", - " Cell capacity of unsectored system = 1326 calls/hour\n", - "\n", - " \n", - " Cell capacity of 120 degree sectored system = 1008 calls/hour\n", - "\n", - " \n", - " Decrease in cell capacity in 120 degree sectored system = 0 percent\n" - ] - } - ], - "source": [ - "# To analyze trunking efficiency capacity of sectoring and unsectoring\n", - "\n", - "# Given data\n", - "H=2/60# # Average call duration in hour\n", - "GOS=0.01# # Probability of blocking\n", - "\n", - "# Unsectored system\n", - "C1=57# # Number of traffic channels per cell in unsectored system\n", - "A=44.2# # Carried traffic in unsectored system\n", - "calls1=1326# # Number of calls per hour in unsectored system from Erlangs B table\n", - "\n", - "# 120 degree sectored system\n", - "C2=C1/3# # Number of traffic channels per antenna sector in 120 degree sectored system\n", - "calls2=336# # Number of calls per hour in 120 degree sectored system from Erlangs B table\n", - "Ns1=3# # Number of sectors\n", - "capacity=Ns1*calls2# # Cell capacity or number of calls handled by system per hour\n", - "\n", - "dif=calls1-capacity# # decrease in cell capacity in 120 degree sectored system\n", - "percentdif=(dif/calls1)*100# # decrease in cell capacity in 120 degree sectored system in percentage\n", - "\n", - "# Displaying the result in command window\n", - "print \"\\n Cell capacity of unsectored system = %0.0f calls/hour\"%(calls1)\n", - "print \"\\n \\n Cell capacity of 120 degree sectored system = %0.0f calls/hour\"%(capacity)\n", - "print \"\\n \\n Decrease in cell capacity in 120 degree sectored system = %0.0f percent\"%(percentdif)" - ] - } - ], - "metadata": { - "kernelspec": { - "display_name": "Python 2", - "language": "python", - "name": "python2" - }, - "language_info": { - "codemirror_mode": { - "name": "ipython", - "version": 2 - }, - "file_extension": ".py", - "mimetype": "text/x-python", - "name": "python", - "nbconvert_exporter": "python", - "pygments_lexer": "ipython2", - "version": "2.7.6" - } - }, - "nbformat": 4, - "nbformat_minor": 0 -} |