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-rw-r--r--sample_notebooks/ChandraShiva/CHAPTER09.ipynb325
-rw-r--r--sample_notebooks/Jaya PratyushaKothuri/Chapter2.ipynb231
-rw-r--r--sample_notebooks/TarunikaBoyapati/CHAPTER02.ipynb419
3 files changed, 975 insertions, 0 deletions
diff --git a/sample_notebooks/ChandraShiva/CHAPTER09.ipynb b/sample_notebooks/ChandraShiva/CHAPTER09.ipynb
new file mode 100644
index 00000000..6549f9c6
--- /dev/null
+++ b/sample_notebooks/ChandraShiva/CHAPTER09.ipynb
@@ -0,0 +1,325 @@
+{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:2fe5d303c17886b921f7fce80c636f86023d9235c3c8b0a7cac768a73d655baa"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "CHAPTER09 : NETWORK FUNCTION"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example E24 - Pg 608"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ " # EXAMPLE 9-24 PG NO-608-609\n",
+ "import math \n",
+ "L=20.; # INDUCTANCE\n",
+ "R=2.*L; # RESISTANCE\n",
+ "print '%s %.2f %s' %('i) Resistance (R) is =',R,'ohm');\n",
+ "Wo=math.sqrt(101.);\n",
+ "print '%s %.2f %s' %('ii) Wo (Wo) is =',Wo,'rad/sec');\n",
+ "Q=(Wo*L)/R;\n",
+ "print '%s %.2f' %('iii) Q is = ',Q);\n",
+ "BW=Wo/Q;\n",
+ "print '%s %.2f %s' %('iv) BANDWIDTH (BW) is = ',BW,' rad/sec ');\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "i) Resistance (R) is = 40.00 ohm\n",
+ "ii) Wo (Wo) is = 10.05 rad/sec\n",
+ "iii) Q is = 5.02\n",
+ "iv) BANDWIDTH (BW) is = 2.00 rad/sec \n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example E26 - Pg 609"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ " # EXAMPLE 9-26 PG NO-609-610\n",
+ "C=10.** -6.;\n",
+ "X=5.*10.** 6.;\n",
+ "L=1./(C*X);\n",
+ "print '%s %.2f %s' %('i) INDUCTAR (L) is =',L,' H ');\n",
+ "R=10.*L;\n",
+ "print '%s %.2f %s' %('ii) Resistance (R) is =',R,' ohm ');\n",
+ "W=2.236*10.** 3.;\n",
+ "Q=(W*L)/R;\n",
+ "print '%s %.2f' %('iii) (Q) is = ',Q);\n",
+ "BW=W/Q;\n",
+ "print '%s %.2f %s' %('iv) Band Width (BW) is =',BW,' rad/sec ');\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "i) INDUCTAR (L) is = 0.20 H \n",
+ "ii) Resistance (R) is = 2.00 ohm \n",
+ "iii) (Q) is = 223.60\n",
+ "iv) Band Width (BW) is = 10.00 rad/sec \n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example E32 - Pg 618"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ " # Example 9-32 PG NO 618-619\n",
+ "import math, cmath\n",
+ "P1=1-1j*50;\n",
+ "P2=1+1j*150;\n",
+ "Z1=0+0j*50;\n",
+ "I=(0.2*Z1)/(P1*P2);\n",
+ "print 'i) Current (I) is = ',I,'A'\n",
+ "L=5.; \n",
+ "R=10.;\n",
+ "C=2.*10.** -5.;\n",
+ "Wo=1/math.sqrt(L*C);\n",
+ "print 'ii) Wo (Wo) is = ',Wo,' rad/sec '\n",
+ "Q=(Wo*L)/R;\n",
+ "print 'iii) Q (Q) is = ',Q;\n",
+ "BW=Wo/Q;\n",
+ "print 'ii) Band Width (BW) is = ',BW,' rad/sec '\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "i) Current (I) is = 0j A\n",
+ "ii) Wo (Wo) is = 100.0 rad/sec \n",
+ "iii) Q (Q) is = 50.0\n",
+ "ii) Band Width (BW) is = 2.0 rad/sec \n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example E37 - Pg 623"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ " # EXAMPLE 9-37 PG NO 623-624\n",
+ "C=1./8.5; # Capacitor\n",
+ "L=1./(17.*C); # Inductar\n",
+ "print '%s %.2f %s' %('ii) Inductar (L) is = ',L,'H');\n",
+ "R=2.*L; # Resistance\n",
+ "print '%s %.2f %s' %('ii) Resistance (R) is = ',R,' ohm ');\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "ii) Inductar (L) is = 0.50 H\n",
+ "ii) Resistance (R) is = 1.00 ohm \n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example E38 - Pg 624"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ " # EXAMPLE 9-38 PG NO=624-625\n",
+ "C=1./9.; # CAPACITOR\n",
+ "X=2.; # R/L=X\n",
+ "Y=6-X; # G/C\n",
+ "G=4.*C;\n",
+ "print '%s %.2f %s' %('i) G (G) = ',G,' ohm')\n",
+ "L=0.9;\n",
+ "R=1.8;\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "i) G (G) = 0.44 ohm\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example E46 - Pg 630"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ " # EXAMPLE 9-46 PG NO 630-631\n",
+ "import cmath\n",
+ "ZA=5+1j*3;\n",
+ "YA=1./ZA;\n",
+ "print 'i) Admittance (YA) is = ',YA,' siemens ';\n",
+ "V=100.; # VOLTAGE\n",
+ "IA=V*YA;\n",
+ "print 'ii) Current (IA) is = ',IA,' A ';\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "i) Admittance (YA) is = (0.147058823529-0.0882352941176j) siemens \n",
+ "ii) Current (IA) is = (14.7058823529-8.82352941176j) A \n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example E50 - Pg 632"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ " # EXAMPLE 9-50 PG NO-632\n",
+ "I1=17.39-1j*4.66; # CURRENT\n",
+ "I2=9+1j*15.68; # CURRENT\n",
+ "I3=-1j*10.95; # CURRENT\n",
+ "I=I1+I2+I3;\n",
+ "print 'i)CURRENT (I) = ',I,' A'\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "i)CURRENT (I) = (26.39+0.07j) A\n"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example E56 - Pg 636"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ " # example 9-56 pg no-636\n",
+ "Z1=8.05+1j*2.156; # IMPEDANCE\n",
+ "XL=2.155;\n",
+ "W=5000;\n",
+ "L=XL/W;\n",
+ "print 'i)INDUCTANCE (L) = ',L,' H'\n",
+ "Z2=4.166-1j*7.216; # IMPEDANCE\n",
+ "Xc=7.216;\n",
+ "C=1/(W*Xc);\n",
+ "print 'ii)CAPACITOR (C) = ',C,' F'\n",
+ "D=11.708; # DIAMETER\n",
+ "XL1=12.81;\n",
+ "L1=XL1/W;\n",
+ "print 'i) INDUCTANCE (L1) = ',L1,' H'\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "i)INDUCTANCE (L) = 0.000431 H\n",
+ "ii)CAPACITOR (C) = 2.77161862528e-05 F\n",
+ "i) INDUCTANCE (L1) = 0.002562 H\n"
+ ]
+ }
+ ],
+ "prompt_number": 8
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+} \ No newline at end of file
diff --git a/sample_notebooks/Jaya PratyushaKothuri/Chapter2.ipynb b/sample_notebooks/Jaya PratyushaKothuri/Chapter2.ipynb
new file mode 100644
index 00000000..7b0498ca
--- /dev/null
+++ b/sample_notebooks/Jaya PratyushaKothuri/Chapter2.ipynb
@@ -0,0 +1,231 @@
+{
+ "cells": [
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "# Chapter 2 - Ionization"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 1: pg 22"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 1,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "the breakdown strength of air for 0.1mm air gap is (kV/cm.) = 43.447\n",
+ "\n",
+ "the breakdown strength of air for 20 cm air gap is (kV/cm.) = 25.58\n"
+ ]
+ }
+ ],
+ "source": [
+ "#example 2.1\n",
+ "#calculation of breakdown strength of air\n",
+ "\n",
+ "#given data\n",
+ "d1=0.1#length(in cm) of the gap\n",
+ "d2=20#length(in cm) of the gap\n",
+ "\n",
+ "#calculation\n",
+ "#from equation of breakdown strength\n",
+ "E1=24.22+(6.08/(d1**(1./2)))#for gap d1\n",
+ "E2=24.22+(6.08/(d2**(1./2)))#for gap d2\n",
+ "#results\n",
+ "print 'the breakdown strength of air for 0.1mm air gap is (kV/cm.) = ',round(E1,3)\n",
+ "print '\\nthe breakdown strength of air for 20 cm air gap is (kV/cm.) = ',round(E2,3)\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 2: pg 23"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 2,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "Townsend primary ioniztion coefficient is (/cm torr) = 7.675\n"
+ ]
+ }
+ ],
+ "source": [
+ "#example 2.2\n",
+ "#calculation of Townsend primary ionization coefficient\n",
+ "from math import log\n",
+ "#given data\n",
+ "d1=0.4#gap distance(in cm)\n",
+ "d2=0.1#gap distance(in cm)\n",
+ "I1=5.5*10**-8#value of current(in A)\n",
+ "I2=5.5*10**-9#value of current(in A)\n",
+ "\n",
+ "#calculation\n",
+ "#from equation of current at anode I=I0*exp(alpha*d)\n",
+ "alpha=(log(I1/I2))*(1/(d1-d2))\n",
+ "#results\n",
+ "print 'Townsend primary ioniztion coefficient is (/cm torr) = ',round(alpha,3)\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 3: pg 25"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 3,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "the value of Townsend secondary ionization coefficient is 9.994e-04\n"
+ ]
+ }
+ ],
+ "source": [
+ "#example 2.3\n",
+ "#calculation of Townsend secondary ionization coefficient\n",
+ "from math import exp\n",
+ "#given data\n",
+ "d=0.9#gap distance(in cm)\n",
+ "alpha=7.676#value of alpha\n",
+ "\n",
+ "#calculation\n",
+ "#from condition of breakdown.....gama*exp(alpha*d)=1\n",
+ "gama=1/(exp(d*alpha))\n",
+ "#results\n",
+ "print '%s %.3e' %('the value of Townsend secondary ionization coefficient is ',gama)\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 4: pg 26"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 4,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "the value of breakdown voltage of the spark gap is (V) = 5626.0\n",
+ "The answer is a bit different due to rounding off error in textbook\n"
+ ]
+ }
+ ],
+ "source": [
+ "#example 2.4\n",
+ "#calculation of breakdown voltage of a spark gap\n",
+ "from math import log\n",
+ "#given data\n",
+ "A=15#value of A(in per cm)\n",
+ "B=360#value of B(in per cm)\n",
+ "d=0.1#spark gap(in cm)\n",
+ "gama=1.5*10**-4#value of gama\n",
+ "p=760#value of pressure of gas(in torr)\n",
+ "\n",
+ "#calculation\n",
+ "#from equation of breakdown voltage\n",
+ "V=(B*p*d)/(log((A*p*d)/(log(1+(1/gama)))))\n",
+ "\n",
+ "#results\n",
+ "print 'the value of breakdown voltage of the spark gap is (V) = ',round(V)\n",
+ "print 'The answer is a bit different due to rounding off error in textbook'\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 5: pg 26"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 5,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "the value of minimum spark over voltage is (V) = 481.0\n"
+ ]
+ }
+ ],
+ "source": [
+ "#example 2.5\n",
+ "#calculation of minimum spark over voltage\n",
+ "from math import log\n",
+ "#given data\n",
+ "A=15#value of A(in per cm)\n",
+ "B=360#value of B(in per cm)\n",
+ "gama=10**-4#value of gama\n",
+ "e=2.178#value of constant\n",
+ "\n",
+ "#calculation\n",
+ "Vbmin=(B*e/A)*(log(1+(1/gama)))\n",
+ "\n",
+ "#results\n",
+ "print 'the value of minimum spark over voltage is (V) = ',round(Vbmin)\n"
+ ]
+ }
+ ],
+ "metadata": {
+ "kernelspec": {
+ "display_name": "Python 2",
+ "language": "python",
+ "name": "python2"
+ },
+ "language_info": {
+ "codemirror_mode": {
+ "name": "ipython",
+ "version": 2
+ },
+ "file_extension": ".py",
+ "mimetype": "text/x-python",
+ "name": "python",
+ "nbconvert_exporter": "python",
+ "pygments_lexer": "ipython2",
+ "version": "2.7.11"
+ }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 0
+}
diff --git a/sample_notebooks/TarunikaBoyapati/CHAPTER02.ipynb b/sample_notebooks/TarunikaBoyapati/CHAPTER02.ipynb
new file mode 100644
index 00000000..809dc7f6
--- /dev/null
+++ b/sample_notebooks/TarunikaBoyapati/CHAPTER02.ipynb
@@ -0,0 +1,419 @@
+{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:896619f98735f380fd7764ca92373e979d96248275ce12cd21f86086d05b2351"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "CHAPTER02 : THE CIRCUIT ELEMENTS"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example E1a - Pg 21"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#1a\n",
+ "V = 1.; # voltage supply \n",
+ "R = 10.; # resistance in ohms \n",
+ "I = V/R # current flowing through R\n",
+ "print '%s' %(\"a)\")\n",
+ "print '%s %.f' %(\"voltage across the resistor (in volts)=\",V)\n",
+ "print '%s %.2f' %(\"current flowing through the resistor (in amps) =\",I)\n",
+ "\n",
+ "#1b\n",
+ "V = 1.; # voltage supply \n",
+ "R1 = 10.; # first resistance in ohms \n",
+ "R2 = 5.; # resistance of the second resistor \n",
+ "Vr1 = V * (R1/(R1 + R2)); # voltage across R1\n",
+ "Vr2 = V - Vr1; # voltage across R2\n",
+ "Ir = Vr1/R1; # current flowing through R\n",
+ "print '%s' %(\"b)\")\n",
+ "print '%s %.2f' %(\"voltage across the first resistor (in volts)=\",Vr1)\n",
+ "print '%s %.2f' %(\"voltage across the second resistor (in volts)=\",Vr2)\n",
+ "print '%s %.2f' %(\"current flowing through the resistor (in amps) =\",Ir)\n",
+ "\n",
+ "#1c\n",
+ "# c - a\n",
+ "R1 = 10.; # first resistance in ohms\n",
+ "R2 = 10.;\n",
+ "I = 1.; # current source \n",
+ "V = I*R1; # voltage across R\n",
+ "print '%s' %(\"c - a)\")\n",
+ "print '%s %.f' %(\"voltage across the resistor (in volts)=\",V)\n",
+ "print '%s %.f' %(\"current flowing through the resistor (in amps) =\",I)\n",
+ "# c - b\n",
+ "Vr1 = I*R1; # voltage across R1\n",
+ "Vr2 = I*R2; # voltage across R2\n",
+ "Vr=Vr1+Vr2;\n",
+ "print '%s' %(\"c - b)\")\n",
+ "print '%s %.f' %(\"voltage across the resistor (in volts)=\",Vr)\n",
+ "print '%s %.f' %(\"current flowing through the resistor (in amps) =\",I)\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "a)\n",
+ "voltage across the resistor (in volts)= 1\n",
+ "current flowing through the resistor (in amps) = 0.10\n",
+ "b)\n",
+ "voltage across the first resistor (in volts)= 0.67\n",
+ "voltage across the second resistor (in volts)= 0.33\n",
+ "current flowing through the resistor (in amps) = 0.07\n",
+ "c - a)\n",
+ "voltage across the resistor (in volts)= 10\n",
+ "current flowing through the resistor (in amps) = 1\n",
+ "c - b)\n",
+ "voltage across the resistor (in volts)= 20\n",
+ "current flowing through the resistor (in amps) = 1\n"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example E2 - Pg 25"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "R = 100.; # resistance in ohms\n",
+ "I = 0.3; # current in amps \n",
+ "P = I**2 * R; # power \n",
+ "# power specification of the resistors available in the stock \n",
+ "Pa = 5.;\n",
+ "Pb = 7.5;\n",
+ "Pc = 10.;\n",
+ "\n",
+ "if Pa > P :\n",
+ " print '%s' %(\"we should select resistor a\")\n",
+ "if Pb > P :\n",
+ " print '%s' %(\"we should select resistor b\")\n",
+ "if Pc > P :\n",
+ " print '%s' %(\"we should select resistor c\")"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "we should select resistor c\n"
+ ]
+ }
+ ],
+ "prompt_number": 8
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example E3 - Pg 26"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "L = 1.; # length of the copper wire in meters\n",
+ "A = 1. * 10.**-4.; # cross sectional area of the wire in meter square \n",
+ "rho = 1.724 * 10.**-8.; # resistivity of copper in ohm meter\n",
+ "R = rho*L / A; # resistance of the wire in ohm \n",
+ "\n",
+ "print '%s %.2e' %(\"resistance of the wire (in ohms)=\",R) "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "resistance of the wire (in ohms)= 1.72e-04\n"
+ ]
+ }
+ ],
+ "prompt_number": 9
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example E4 - Pg 27"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# 1 inches = 0.0254meters\n",
+ "# 1 foot = 0.3048 meters\n",
+ "import math \n",
+ "d = 0.1*0.0254; # diameter of the wire in meters\n",
+ "L = 10.*0.3048; # length of the wire in meters \n",
+ "rho = 1.724*10.**-8.; # resistivity of the wire in ohm-meter\n",
+ "A = math.pi*(d/2.)**2.; # cross sectional area of the wire \n",
+ "R = rho*L/A; # resistance of the wire in ohm \n",
+ "print '%s %.2f' %(\"resistance of the wire (in ohm)=\",R)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "resistance of the wire (in ohm)= 0.01\n"
+ ]
+ }
+ ],
+ "prompt_number": 10
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example E5 - Pg 29"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "%matplotlib inline\n",
+ "import math\n",
+ "import numpy as np\n",
+ "from matplotlib import pyplot\n",
+ "L = 0.1; # inductance of the coil in henry \n",
+ "t1= np.linspace(0,0.1, num=101)\n",
+ "t2= np.linspace(0.101,0.3, num=201)\n",
+ "t3= np.linspace(0.301,0.6,num=301)\n",
+ "t4= np.linspace(0.601,0.7,num=101)\n",
+ "t5= np.linspace(0.701,0.9,num=201)\n",
+ "# current variation as a function of time \n",
+ "i1 = 100.*t1;\n",
+ "i2 = (-50.*t2) + 15.;\n",
+ "i3 = np.zeros(301)\n",
+ "for i in range(0,301):\n",
+ "\ti3[i] = -100.*math.sin(math.pi*(t3[i]-0.3)/0.3);\n",
+ "\n",
+ "i4 = (100.*t4) - 60.;\n",
+ "i5 = (-50.*t5) + 45.;\n",
+ "\n",
+ "t = ([t1,t2,t3,t4,t5]);\n",
+ "i = ([i1,i2,i3,i4,i5]);\n",
+ "pyplot.plot(t1, i1);\n",
+ "pyplot.plot(t2, i2);\n",
+ "pyplot.plot(t3, i3);\n",
+ "pyplot.plot(t4, i4);\n",
+ "pyplot.plot(t5, i5);\n",
+ "\n",
+ "dt = 0.001;\n",
+ "di1 = np.diff(i1);\n",
+ "di2 = np.diff(i2);\n",
+ "di3 = np.diff(i3);\n",
+ "di4 = np.diff(i4);\n",
+ "di5 = np.diff(i5);\n",
+ "V1 =np.array((L/dt)*di1); # voltage drop appearing across the inductor terminals\n",
+ "V2 =np.array((L/dt)*di2); # voltage drop appearing across the inductor terminals\n",
+ "V3 =np.array((L/dt)*di3); # voltage drop appearing across the inductor terminals\n",
+ "V4 = np.array((L/dt)*di4); # voltage drop appearing across the inductor terminals\n",
+ "V5 = np.array((L/dt)*di5); # voltage drop appearing across the inductor terminals\n",
+ "print(V2)\n",
+ "Tv = np.linspace(0,0.899,num=900);\n",
+ "V = []\n",
+ "V.extend(V1)\n",
+ "V.extend(V2)\n",
+ "V.extend(V3)\n",
+ "V.extend(V4)\n",
+ "V.extend(V5)\n",
+ "print(len(V))\n",
+ "pyplot.plot(Tv, V)\n",
+ "pyplot.show();"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "[-4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975\n",
+ " -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975\n",
+ " -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975\n",
+ " -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975\n",
+ " -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975\n",
+ " -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975\n",
+ " -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975\n",
+ " -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975\n",
+ " -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975\n",
+ " -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975\n",
+ " -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975\n",
+ " -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975\n",
+ " -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975\n",
+ " -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975\n",
+ " -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975\n",
+ " -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975\n",
+ " -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975\n",
+ " -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975\n",
+ " -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975\n",
+ " -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975 -4.975]\n",
+ "900\n"
+ ]
+ },
+ {
+ "metadata": {},
+ "output_type": "display_data",
+ "png": 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+ "text": [
+ "<matplotlib.figure.Figure at 0x5cdc0b0>"
+ ]
+ }
+ ],
+ "prompt_number": 11
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example E7 - Pg 31"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# a\n",
+ "Ri = 1.; \n",
+ "Rf = 39.;\n",
+ "A = 10.**5.; # open loop gain of the op-amp\n",
+ "G = A/(1. + (A*Ri/(Ri+Rf))); # actual voltage gain of the circuit \n",
+ "print '%s' %(\"a\")\n",
+ "print '%s %.2f' %(\"actual voltage of the circuit =\",G)\n",
+ "\n",
+ "# b\n",
+ "G1 = 1 + (Rf/Ri); # voltage gain of the circuit with infinite open loop gain\n",
+ "print '%s' %(\"b\")\n",
+ "print '%s %.f' %(\"for ideal case the voltage gain =\",G1)\n",
+ "\n",
+ "# c\n",
+ "er = ((G1 - G)/G)*100.; # percent error \n",
+ "print '%s' %(\"c\")\n",
+ "print '%s %.2f' %(\"percent error of the ideal value compared to the actual value=\",er)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "a\n",
+ "actual voltage of the circuit = 39.98\n",
+ "b\n",
+ "for ideal case the voltage gain = 40\n",
+ "c\n",
+ "percent error of the ideal value compared to the actual value= 0.04\n"
+ ]
+ }
+ ],
+ "prompt_number": 12
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example E8 - Pg 33"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "G = 4.; # voltage gain of the circuit \n",
+ "r = G -1.; # ratio of the resistances in the non-inverting op-amp circuit\n",
+ "print '%s %.2f' %(\"Rf/Ri =\",r)\n",
+ "# Result:\n",
+ "# A suitable choice for R1 is 10K, Hence Rf = 30K\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Rf/Ri = 3.00\n"
+ ]
+ }
+ ],
+ "prompt_number": 15
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example E9 - Pg 34"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "G = 4.;\n",
+ "r = G; # ratio of the resistances in the inverting op-amp circuit\n",
+ "print '%s %.f' %(\"Rf/Ri\",r)\n",
+ "# Result;\n",
+ "# A suitable choice for Rf=30K and R1=7.5K\n",
+ "# therefore input resistance R1 = 7.5K\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Rf/Ri 4\n"
+ ]
+ }
+ ],
+ "prompt_number": 14
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+} \ No newline at end of file
generated by cgit (git 2.34.1) at 2024-12-20 14:17:25 +0000