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diff --git a/sample_notebooks/kotaDinesh Babu/kotaDinesh Babu_version_backup/samplebook(process_heat.ipynb b/sample_notebooks/kotaDinesh Babu/kotaDinesh Babu_version_backup/samplebook(process_heat.ipynb new file mode 100755 index 00000000..b114e915 --- /dev/null +++ b/sample_notebooks/kotaDinesh Babu/kotaDinesh Babu_version_backup/samplebook(process_heat.ipynb @@ -0,0 +1,278 @@ +{
+ "cells": [
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "#Chapter:2 CONDUCTION"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "##Example2.1"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 1,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ " heat is Btu/hr 69120.0\n",
+ "\t approximate values are mentioned in the book \n",
+ "\n"
+ ]
+ }
+ ],
+ "source": [
+ "#given\n",
+ "Tavg=900; # average temperature of the wall,F\n",
+ "k=0.15; # Thermal conductivity at 932 F,Btu/(hr)(ft^2)(F/ft)\n",
+ "T1=1500; # hot side temperature,F\n",
+ "T2=300; # cold side temperature,F\n",
+ "A=192; # surface area,ft^2\n",
+ "L=0.5; # thickness,ft\n",
+ "#solution\n",
+ "Q=(k)*(A)*(T1-T2)/L; # formula for heat,Btu/hr\n",
+ "print \" heat is Btu/hr \",Q\n",
+ "print\"\\t approximate values are mentioned in the book \\n\"\n",
+ "#end\n",
+ "\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example2.2"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 3,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "\t resistance offered by firebrick : (hr)*(F)/Btu 0.97\n",
+ "\t resistance offered by insulating brick : (hr)*(F)/Btu 2.2\n",
+ "\t resistance offered by buildingbrick : (hr)*(F)/Btu 1.25\n",
+ "\t total resistance offered by three walls : (hr)*(F)/Btu 4.42\n",
+ "\t heat loss/ft^2 : Btu/hr 331.0\n",
+ "\t delta is : F 322.0\n",
+ "\t temperature at interface of firebrick and insulating brick F 1278.0\n",
+ "\t deltb is : F 729.0\n",
+ "\t temperature at interface of insulating brick and building brick F 549.0\n",
+ "\t approximate values are mentioned in the book \n",
+ "\n"
+ ]
+ }
+ ],
+ "source": [
+ "#given\n",
+ "La=0.66; # Thickness of firebrick wall,ft\n",
+ "Lb=0.33; # Thickness of insulating brick wall,ft\n",
+ "Lc=0.5; # Thickness of building brick wall,ft\n",
+ "Ka=0.68; # themal conductivity of firebrick,Btu/(hr)*(ft^2)*(F/ft)\n",
+ "Kb=0.15; # themal conductivity of insulating brick,Btu/(hr)*(ft^2)*(F/ft)\n",
+ "Kc=0.40; # themal conductivity of building brick,Btu/(hr)*(ft^2)*(F/ft)\n",
+ "A=1.; # surface area,ft^2\n",
+ "Ta=1600.; # temperature of inner wall,F\n",
+ "Tb=125.; # temperature of outer wall.F\n",
+ "#solution\n",
+ "Ra=La/(Ka)*(A); # formula for resistance,(hr)*(F)/Btu\n",
+ "print\"\\t resistance offered by firebrick : (hr)*(F)/Btu \",round(Ra,2)\n",
+ "Rb=Lb/(Kb)*(A); # formula for resistance,(hr)*(F)/Btu\n",
+ "print\"\\t resistance offered by insulating brick : (hr)*(F)/Btu \",round(Rb,2)\n",
+ "Rc=Lc/(Kc)*(A); # formula for resistance,(hr)*(F)/Btu\n",
+ "print\"\\t resistance offered by buildingbrick : (hr)*(F)/Btu \",round(Rc,2)\n",
+ "R=Ra+Rb+Rc; # total resistance offered by three walls,(hr)*(F)/Btu\n",
+ "print\"\\t total resistance offered by three walls : (hr)*(F)/Btu \",round(R,2)\n",
+ "Q=(1600-125)/4.45; # using formula for heat loss/ft^2,Btu/hr\n",
+ "print\"\\t heat loss/ft^2 : Btu/hr \",round(Q,0)\n",
+ "# T1,T2 are temperatures at interface of firebrick and insulating brick, and insulating brick and building brick respectively,F\n",
+ "delta=(Q)*(Ra); # formula for temperature difference,F\n",
+ "print\"\\t delta is : F \",round(delta,0)\n",
+ "T1=Ta-((Q)*(Ra)); # temperature at interface of firebrick and insulating brick,F\n",
+ "print\"\\t temperature at interface of firebrick and insulating brick F \",round(T1,0)\n",
+ "deltb=Q*(Rb);\n",
+ "print\"\\t deltb is : F \",round(deltb,0)\n",
+ "T2=T1-((Q)*(Rb)); #temperature at interface of insulating brick and building brick,F\n",
+ "print\"\\t temperature at interface of insulating brick and building brick F \",round(T2,0)\n",
+ "print\"\\t approximate values are mentioned in the book \\n\"\n",
+ "#end\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "##Example2.3"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 4,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "\t approximate values are mentioned in the book \n",
+ "\n",
+ "\t resistance offered by air film (hr)(F)/Btu 0.79\n",
+ "\t total resistance (hr)(F)/Btu 5.24\n",
+ "\t heat loss Btu/hr 282.0\n"
+ ]
+ }
+ ],
+ "source": [
+ "\n",
+ "print\"\\t approximate values are mentioned in the book \\n\"\n",
+ "#given\n",
+ "Lair=0.25/12; # thickness of air film,ft\n",
+ "Kair=0.0265; # thermal conductivity of air at 572F,Btu/(hr)*(ft^2)(F/ft)\n",
+ "A=1; # surface area,ft^2\n",
+ "#solution\n",
+ "Rair=Lair/(Kair*(A)); # resistance offered by air film, (hr)(F)/Btu\n",
+ "print\"\\t resistance offered by air film (hr)(F)/Btu \",round(Rair,2)\n",
+ "R=4.45; # resistance from previous example 2.2,(hr)(F)/Btu\n",
+ "Rt=(R)+Rair; # total resistance,(hr)(F)/Btu\n",
+ "print\"\\t total resistance (hr)(F)/Btu \",round(Rt,2)\n",
+ "Ta=1600; # temperature of inner wall,F\n",
+ "Tb=125; # temperature of outer wall,F\n",
+ "Q=(1600-125)/Rt; # heat loss, Btu/hr\n",
+ "print\"\\t heat loss Btu/hr \",round(Q,0)\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "##Example2.4"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": null,
+ "metadata": {
+ "collapsed": true
+ },
+ "outputs": [],
+ "source": [
+ "#given\n",
+ "k=0.63; # thermal conductivity of pipe, Btu/(hr)*(ft^2)*(F/ft)\n",
+ "Do=6. # in\n",
+ "Di=5. # in\n",
+ "Ti=200.;# inner side temperature,F\n",
+ "To=175.; # outer side temperature,F\n",
+ "#solution\n",
+ "import math\n",
+ "from math import log\n",
+ "q=(2*(3.14)*(k)*(Ti-To))/(log (Do/Di)); # formula for heat flow,Btu/(hr)*(ft)\n",
+ "print\"\\t heat flow is : Btu/(hr)*(ft) \",round(q,0)\n",
+ "print\"\\t approximate values are mentioned in the book \\n\"\n",
+ "# caculation mistake in book\n",
+ "# end\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "##Example2.5"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 6,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "\t approximate values are mentioned in the book \n",
+ "\n",
+ "\t heat loss for linear foot is : Btu/(hr)*(lin ft) 104.4\n",
+ "\t Check between ts and t1, since delt/R = deltc/Rc \n",
+ "\t t1 is : F 122.300238658\n",
+ "\t heat loss for linear foot is : Btu/(hr)*(lin ft) 102.9\n",
+ "\t Check between ts and t1, since delt/R = deltc/Rc \n",
+ "\t t1 is : F \n",
+ "125.4\n"
+ ]
+ }
+ ],
+ "source": [
+ "print\"\\t approximate values are mentioned in the book \\n\"\n",
+ "#given\n",
+ "t1=150; # assume temperature of outer surface of rockwool,F\n",
+ "ta=70; # temperature of surrounding air,F\n",
+ "ha=2.23; # surface coefficient,Btu/(hr)*(ft^2)*(F)\n",
+ "#solution\n",
+ "import math\n",
+ "from math import log\n",
+ "q=(3.14)*(300-70)/(((1/(2*0.033))*log(3.375/2.375))+(1/((2.23)*(3.375/12)))); # using formula for heat loss,Btu/(hr)*(lin ft), calculation mistake\n",
+ "print\"\\t heat loss for linear foot is : Btu/(hr)*(lin ft) \",round(q,1)\n",
+ "print\"\\t Check between ts and t1, since delt/R = deltc/Rc \"\n",
+ "t1=300-(((104.8)*((1)*(log(3.375/2.375))))/((2)*(3.14)*(.033))); # using eq 2.31,F\n",
+ "print\"\\t t1 is : F \",t1\n",
+ "t1=125; # assume temperature of outer surface of rockwool,F\n",
+ "ha=2.10; # surface coefficient,Btu/(hr)*(ft^2)*(F)\n",
+ "q=((3.14)*(300-70))/(((1/(2*0.033))*log(3.375/2.375))+(1/((2.10)*(3.375/12)))); # using formula for heat loss,Btu/(hr)*(lin ft)\n",
+ "print\"\\t heat loss for linear foot is : Btu/(hr)*(lin ft)\",round(q,1)\n",
+ "print\"\\t Check between ts and t1, since delt/R = deltc/Rc \"\n",
+ "t1=300-(((103)*((1)*(log(3.375/2.375))))/((2)*(3.14)*(.033))); # using eq 2.31,F\n",
+ "print\"\\t t1 is : F \\n\",round(t1,1)\n",
+ "# end \n"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": null,
+ "metadata": {
+ "collapsed": true
+ },
+ "outputs": [],
+ "source": []
+ }
+ ],
+ "metadata": {
+ "kernelspec": {
+ "display_name": "Python 2",
+ "language": "python",
+ "name": "python2"
+ },
+ "language_info": {
+ "codemirror_mode": {
+ "name": "ipython",
+ "version": 2
+ },
+ "file_extension": ".py",
+ "mimetype": "text/x-python",
+ "name": "python",
+ "nbconvert_exporter": "python",
+ "pygments_lexer": "ipython2",
+ "version": "2.7.9"
+ }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 0
+}
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