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+{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:e984fee9b841dd6e9b7eedf1533b0a0d297cd9f484c047f051ce48a09b156826"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter2-Nuclear Engineering"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex1-pg54"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "## Example 2.1\n",
+ "import math\n",
+ "#determine atoms in deuterium\n",
+ "## Given data\n",
+ "atom_h = 6.6*10**24; ## Number of atoms in Hydrogen\n",
+ "## Using the data given in Table II.2, Appendix II for isotropic abundance of deuterium\n",
+ "isoab_H2 = 0.015; ## Isotropic abundance of deuterium\n",
+ "## Calculation\n",
+ "totatom_d=(isoab_H2*atom_h)/100.;\n",
+ "## Result\n",
+ "print\"%s %.2e %s \"%('\\n Number of deuterium atoms = ',totatom_d,'');\n",
+ "\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "\n",
+ " Number of deuterium atoms = 9.90e+20 \n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex2-pg54"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "## Example 2.2\n",
+ "import math\n",
+ "#determine atomic weight of oxygen\n",
+ "## Given data \n",
+ "## Using the data given in the example 2.2\n",
+ "atwt_O16 = 15.99492; ## Atomic weight of O-16 isotope\n",
+ "isoab_O16 = 99.759; ## Abundance of O-16 isotope\n",
+ "atwt_O17 = 16.99913; ## Atomic weight of O-17 isotope\n",
+ "isoab_O17 = 0.037; ## Abundance of O-17 isotope\n",
+ "atwt_O18 = 17.99916; ## Atomic weight of O-18 isotope\n",
+ "isoab_O18 = 0.204; ## Abundance of O-18 isotope\n",
+ "## Calculation\n",
+ "atwt_O=(isoab_O16*atwt_O16 + isoab_O17*atwt_O17 + isoab_O18*atwt_O18)/100.;\n",
+ "## Result\n",
+ "print\"%s %.2f %s \"%('\\n Atomic Weight of Oxygen = ',atwt_O,'');\n",
+ "\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "\n",
+ " Atomic Weight of Oxygen = 16.00 \n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex3-pg55"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "## Example 2.3\n",
+ "import math\n",
+ "#determine rest mass energy of electron\n",
+ "## Given data\n",
+ "me = 9.1095*10**(-28); ## Mass of electron in grams\n",
+ "c = 2.9979*10**10; ## Speed of light in vacuum in cm/sec\n",
+ "## Calculation\n",
+ "rest_mass = me*c**2;\n",
+ "## Result\n",
+ "print\"%s %.2e %s \"%('\\n Rest mass energy of electron = ',rest_mass,' ergs\\n');\n",
+ "print('Expressing the result in joules')\n",
+ "## 1 Joule = 10^(-7)ergs\n",
+ "rest_mass_j = rest_mass*10**(-7);\n",
+ "print\"%s %.2e %s \"%('\\n Rest mass energy of electron = ',rest_mass_j,' joules\\n');\n",
+ "print('Expressing the result in MeV')\n",
+ "## 1 MeV = 1.6022*10^(-13)joules\n",
+ "rest_mass_mev = rest_mass_j/(1.6022*10**(-13));\n",
+ "print\"%s %.2f %s \"%('\\n Rest mass energy of electron = ',rest_mass_mev,' MeV\\n');\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "\n",
+ " Rest mass energy of electron = 8.19e-07 ergs\n",
+ " \n",
+ "Expressing the result in joules\n",
+ "\n",
+ " Rest mass energy of electron = 8.19e-14 joules\n",
+ " \n",
+ "Expressing the result in MeV\n",
+ "\n",
+ " Rest mass energy of electron = 0.51 MeV\n",
+ " \n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+} \ No newline at end of file