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+{
+ "metadata": {
+ "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 11: Voltage Regulators"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "example 11.1, Page No. 414"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# op-amp series voltage regulator design\n",
+ "\n",
+ "import math\n",
+ "#Variable declaration\n",
+ "Vin_min = 18-3 # min input voltage specification\n",
+ "Vin_max = 18+3 # max input voltage specification\n",
+ "Vout = 9 # output voltage specification\n",
+ "Iout_min = 10*10**-3 # min output current specification\n",
+ "Iout_max = 50*10**-3 # max output current specification\n",
+ "Vz = 5.6 # zener breakdown voltage\n",
+ "Pzmax = 0.5 # Maximum power dissipation in zener\n",
+ "\n",
+ "#Calculations\n",
+ "R1 = 10*10**3 # assumed\n",
+ "R2 = R1/((Vout/Vz)-1)\n",
+ "R3 = (Vin_min-Vz)/Iout_max\n",
+ "Iz = (Vin_max-Vz)/R3\n",
+ "Pd = Iz*Vz\n",
+ "beta = 30 # assumed\n",
+ "Ib = Iout_max/(beta+1)\n",
+ "\n",
+ "#Result\n",
+ "print(\"Element values for designed circuit are as follows:\\nR1 = %d k-ohm\\nR2 = %.2f k-ohm\"%(R1/1000,R2/1000))\n",
+ "print(\"R3 = %.3f k-ohm\\nIB = %.2f mA\"%(R3/1000,Ib*1000))\n",
+ "#Answer for R3 is wrong in the book"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Element values for designed circuit are as follows:\n",
+ "R1 = 10 k-ohm\n",
+ "R2 = 16.47 k-ohm\n",
+ "R3 = 0.188 k-ohm\n",
+ "IB = 1.61 mA\n"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "example 11.2, Page No. 420"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Regulator using IC 723\n",
+ "\n",
+ "import math\n",
+ "#Variable declaration\n",
+ "Vout = 5 # Required output voltage\n",
+ "Iout = 100*10**-3 # Required output current\n",
+ "Vin_min = 15-(0.2*15) # Min input voltage\n",
+ "Vin_max = 15+(0.2*15) # Max input voltage\n",
+ "Isc = 150*10**-3 # Short circuit current requirement\n",
+ "Vsense = 0.7 # short circuit voltage\n",
+ "Vref = 7.15 # reference votage for IC 723\n",
+ "Id = 1*10**-3 # potential divider current\n",
+ "\n",
+ "\n",
+ "#Calculation\n",
+ "Rsc = Vsense/Isc\n",
+ "R1 = (Vref-Vout)/Id\n",
+ "R1std = 2.2*10**3 \n",
+ "R2 = R1std/((Vref/Vout)-1)\n",
+ "R2std = 5.1*10**3 \n",
+ "R3 = R1std*R2std/(R1std+R2std)\n",
+ "R3std = 1.5*10**3 \n",
+ "\n",
+ "#Result\n",
+ "print(\"R1 = %.3f k-ohm\\t We use %.1f k-ohm as standard resistor.\"%(R1/1000,R1std/1000))\n",
+ "print(\"R2 = %.3f k-ohm\\t We use %.1f k-ohm as standard resistor.\"%(R2/1000,R2std/1000))\n",
+ "print(\"R3 = %.3f k-ohm\\t We use %.1f k-ohm as standard resistor.\"%(math.floor((R3/1000)*1000)/1000,R3std/1000))"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "R1 = 2.150 k-ohm\t We use 2.2 k-ohm as standard resistor.\n",
+ "R2 = 5.116 k-ohm\t We use 5.1 k-ohm as standard resistor.\n",
+ "R3 = 1.536 k-ohm\t We use 1.5 k-ohm as standard resistor.\n"
+ ]
+ }
+ ],
+ "prompt_number": 12
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "example 11.3, Page No. 421"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Ic 723 based positive voltage regulator\n",
+ "\n",
+ "import math\n",
+ "#Variable declaration\n",
+ "Vout = 12.0 # output voltage\n",
+ "Il = 500*10**-3 # load current\n",
+ "Isc = 600*10**-3 # short circuit current\n",
+ "Vref = 7.0 # IC 723 reference voltage \n",
+ "Vsense = 0.6 # voltage at short circuit\n",
+ "\n",
+ "#Calculation\n",
+ "R1 = 4.7*10**3 # assumed\n",
+ "R2 = Vref*R1/(Vout-Vref)\n",
+ "R2std = 6.8*10**3 \n",
+ "Rsc = Vsense/Isc\n",
+ "R3 = R2std*R1/(R2std+R1)\n",
+ "Psc = Isc**2*Rsc*1000\n",
+ "I = Vout/(R1+R2std)\n",
+ "I= math.floor(I*10**6)/10**6\n",
+ "P1 = I**2*R1*1000\n",
+ "P2 = I**2*R2std*1000\n",
+ "\n",
+ "#Result\n",
+ "print(\"R1 = %.1f k-ohm\\nR2 = %.2f k-ohm = %.1f k-ohm(standard value)\\nRsc = %.1f ohm\"%(R1/1000,R2/1000,R2std/1000,Rsc))\n",
+ "print(\"\\nPower wattage:\\nPsc = %.0f mW\\nP1 = %.3f mW\\nP2 = %.3f mW\"%(Psc,math.floor(P1*1000)/1000,P2))\n",
+ "print(\"Hence, both R1 and R2 may be selected safely of 1/16th watt power rating.\")"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "R1 = 4.7 k-ohm\n",
+ "R2 = 6.58 k-ohm = 6.8 k-ohm(standard value)\n",
+ "Rsc = 1.0 ohm\n",
+ "\n",
+ "Power wattage:\n",
+ "Psc = 360 mW\n",
+ "P1 = 5.112 mW\n",
+ "P2 = 7.397 mW\n",
+ "Hence, both R1 and R2 may be selected safely of 1/16th watt power rating.\n"
+ ]
+ }
+ ],
+ "prompt_number": 24
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "example 11.4, Page No. 426"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Regulator design using IC 723(refer to fig. 11.26)\n",
+ "\n",
+ "import math\n",
+ "#Variable declaration\n",
+ "Vout = 6 # output voltage\n",
+ "Il = 1 # load current\n",
+ "Isc = 0.250 # short circuit \n",
+ "Vref = 7 # reference voltage\n",
+ "Vbe = 0.7 # base-emitter junction voltage\n",
+ "\n",
+ "#Calculations\n",
+ "R1 = 2.7*10**3 # assumed\n",
+ "R2 = Vout*R1/(Vref-Vout)\n",
+ "kRsc = Vbe/Isc\n",
+ "k =1-(((Il-Isc)*kRsc)/Vout)\n",
+ "R4 = 10*10**3 # assumed \n",
+ "R3 = (1-k)*R4\n",
+ "Rsc = kRsc/k\n",
+ "R = (R1*R2)/(R1+R2)\n",
+ "\n",
+ "#Result\n",
+ "print(\"R1 = %.1f k-ohm\\nR2 = %.1f k-ohm\\nR3 = %.1f k-ohm\\nR4 = %.1f k-ohm\\nR = %.2f k-ohm\"%(R1/1000,R2/1000,R3/1000,R4/1000,R/1000))"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "R1 = 2.7 k-ohm\n",
+ "R2 = 16.2 k-ohm\n",
+ "R3 = 3.5 k-ohm\n",
+ "R4 = 10.0 k-ohm\n",
+ "R = 2.31 k-ohm\n"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "example 11.5, Page No.432"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Current source design using IC7812\n",
+ "\n",
+ "import math\n",
+ "#Variable declaration\n",
+ "RL = 25.0 # load resistance\n",
+ "P = 10.0 # power \n",
+ "I = 0.5 # current required\n",
+ "V = 12.0 # rated voltage\n",
+ "\n",
+ "#Calculations\n",
+ "R = V/I\n",
+ "Vout = V+(I*RL)\n",
+ "Vin = Vout+2\n",
+ "\n",
+ "#Result\n",
+ "print(\"R = %d ohm\\nVout = %.1f V\\nVin = %.1f V\"%(R,Vout,Vin))"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "R = 24 ohm\n",
+ "Vout = 24.5 V\n",
+ "Vin = 26.5 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 16
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "example 11.6, Page NO. 432"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# min and max voltage of regulator(refer fig.11.34)\n",
+ "\n",
+ "import math\n",
+ "#variable declaration\n",
+ "Iq = 10*10**-3 # quiescent current\n",
+ "Vreg = 15.0 # regulated output voltage\n",
+ "R2 = 0 # min value of potentiometer\n",
+ "R1 = 40.0 # R1 resistor\n",
+ "\n",
+ "#Calculations\n",
+ "Vout = (1+(R2/R1))*Vreg+(Iq*R2)\n",
+ "\n",
+ "#Result\n",
+ "print(\"Vout = %d V\"%Vout)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Vout = 15 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 20
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "example 11.7, Page No. 432"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# current source using 7805\n",
+ "\n",
+ "import math\n",
+ "#Variable declaration\n",
+ "Il = 0.2 # required load current\n",
+ "RL = 22.0 # load resistance\n",
+ "P = 10.0 # required power\n",
+ "Iq = 4.2*10**-3 # quiescent current\n",
+ "Vr = 5 # regulated output voltage\n",
+ "\n",
+ "#Calculation\n",
+ "R = Vr/(Il-Iq)\n",
+ "Vout = Vr+Il*RL\n",
+ "Vin = Vout+2\n",
+ "\n",
+ "#Result\n",
+ "print(\"R = %f ohm\\nVout = %.1f V\\nVin = %.1f V\"%(R,Vout,Vin))\n",
+ "# Answer for R is wrong in the book"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "R = 25.536261 ohm\n",
+ "Vout = 9.4 V\n",
+ "Vin = 11.4 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 23
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "example 11.8, Page No.435"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Regulated outpuut voltage(refer fig. 11.38)\n",
+ "\n",
+ "import math\n",
+ "#Variable declaration\n",
+ "R1 = 220.0 # resistance R1\n",
+ "R2 = 1500.0 # Resistance R2\n",
+ "Iadj = 100*10**-6 # adj. current\n",
+ "\n",
+ "\n",
+ "#Calculartions\n",
+ "Vout = (1.25*(1+(R2/R1)))+(Iadj*R2)\n",
+ "\n",
+ "#Result\n",
+ "print(\"Vout = %.2f V\"%Vout)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Vout = 9.92 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "example 11.9, Page No. 435"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Output voltage range\n",
+ "\n",
+ "import math\n",
+ "#Variable declaration\n",
+ "R1 = 820.0 # resistance R1\n",
+ "R2min = 0 # min potentiometer resistance\n",
+ "R2max = 10*10**3 # max potentiometer resistance\n",
+ "Iadj = 100*10**-6 # adj. current\n",
+ "\n",
+ "#calculations\n",
+ "Vmin = 1.25*(1+(R2min/R1))+(Iadj*R2min)\n",
+ "Vmax = 1.25*(1+(R2max/R1))+(Iadj*R2max)\n",
+ "\n",
+ "#Result\n",
+ "print(\"The output can be varied in the range %.2f V to %.2f V\"%(Vmin,Vmax))"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The output can be varied in the range 1.25 V to 17.49 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 8
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "example 11.10, Page No. 436"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Maximum load current\n",
+ "\n",
+ "import math\n",
+ "#Variable declaration\n",
+ "Vbe = 1.0 # base emitter junction voltage\n",
+ "beta = 15.0 # current gain\n",
+ "R1 = 7.0 # resistance R1\n",
+ "Iout = 1.0 # max output current from IC \n",
+ "#Calculations\n",
+ "Il = ((1+beta)*Iout) - beta*(Vbe/R1)\n",
+ "Il = math.floor(Il*100)/100\n",
+ "#Result\n",
+ "print(\"IC which can supply maximum 1A can supply maximum load of %.2f A, with the help of the current boosting arrangements\"%Il)\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "IC which can supply maximum 1A can supply maximum load of 13.85 A, with the help of the current boosting arrangements\n"
+ ]
+ }
+ ],
+ "prompt_number": 12
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+} \ No newline at end of file