diff options
Diffstat (limited to 'sample_notebooks/Vedantam Lakshmi Manasa')
-rwxr-xr-x | sample_notebooks/Vedantam Lakshmi Manasa/Chapter_2_Electric_Fields.ipynb | 296 |
1 files changed, 296 insertions, 0 deletions
diff --git a/sample_notebooks/Vedantam Lakshmi Manasa/Chapter_2_Electric_Fields.ipynb b/sample_notebooks/Vedantam Lakshmi Manasa/Chapter_2_Electric_Fields.ipynb new file mode 100755 index 00000000..cdc8b25e --- /dev/null +++ b/sample_notebooks/Vedantam Lakshmi Manasa/Chapter_2_Electric_Fields.ipynb @@ -0,0 +1,296 @@ +{
+ "cells": [
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "# Chapter 2 Electric Fields"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 2_5 pgno:65"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 2,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "Maximum field = V/m per volt 42064315640.1\n"
+ ]
+ }
+ ],
+ "source": [
+ "#Chapter 2, Example 5, page 65\n",
+ "#Calculate the maximum field at the sphere surface\n",
+ "#Calulating Field at surface E based on figure 2.31 and table 2.3\n",
+ "from math import pi\n",
+ "Q1 = 0.25\n",
+ "e0 = 8.85418*10**-12 #Epselon nought\n",
+ "RV1= ((1/0.25**2)+(0.067/(0.25-0.067)**2)+(0.0048/(0.25-0.067)**2))\n",
+ "RV2= ((0.25+0.01795+0.00128)/(0.75-0.067)**2)\n",
+ "RV= RV1+RV2\n",
+ "E = (Q1*RV)/(4*pi*e0)\n",
+ "print\"Maximum field = V/m per volt\",E\n",
+ "\n",
+ "#Answers vary due to round off error\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 2_6 pgno:66"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": null,
+ "metadata": {
+ "collapsed": true
+ },
+ "outputs": [],
+ "source": [
+ "#Chapter 2, Exmaple 6, page 66\n",
+ "#calculation based on figure 2.32\n",
+ "\n",
+ "#(a)Charge on each bundle\n",
+ "print\"Part a\\t\"\n",
+ "req = (0.0175*0.45)**0.5\n",
+ "print\"Equivalent radius = m \", req\n",
+ "from math import log\n",
+ "from math import pi\n",
+ "V = 400*10**3 #Voltage\n",
+ "H = 12. #bundle height in m\n",
+ "d = 9. #pole to pole spacing in m\n",
+ "e0 = 8.85418*10**-12 #Epselon nought\n",
+ "Hd = ((2*H)**2+d**2)**0.5#2*H**2 + d**2\n",
+ "Q = V*2*pi*e0/(log((2*H/req))-log((Hd/d)))\n",
+ "q = Q/2\n",
+ "print\"Charge per bundle = uC/m \",Q #micro C/m\n",
+ "print\"Charge per sunconducter = uC/m \",q #micro C/m\n",
+ "\n",
+ "#(b part i)Maximim & average surface feild\n",
+ "print\"\\tPart b\"\n",
+ "print\"\\tSub part 1\\t\"\n",
+ "r = 0.0175 #subconductor radius\n",
+ "R = 0.45 #conductor to subconductor spacing\n",
+ "MF = (q/(2*pi*e0))*((1/r)+(1/R)) # maximum feild\n",
+ "print\"Maximum feild = kV/m \\t\",MF\n",
+ "MSF = (q/(2*pi*e0))*((1/r)-(1/R)) # maximum surface feild\n",
+ "print\"Maximum feild = kV/m \\t\",MSF\n",
+ "ASF = (q/(2*pi*e0))*(1/r) # Average surface feild\n",
+ "print\"Maximum feild = kV/m \\t\",ASF\n",
+ "\n",
+ "#(b part ii) Considering the two sunconductors on the left\n",
+ "print\"\\tSub part 2\\t\"\n",
+ "#field at the outer point of subconductor #1 \n",
+ "drO1 = 1/(d+r)\n",
+ "dRrO1 = 1/(d+R+r)\n",
+ "EO1 = MF -((q/(2*pi*e0))*(drO1+dRrO1))\n",
+ "print\"EO1 = kV/m \\t\",EO1\n",
+ "#field at the outer point of subconductor #2 \n",
+ "drO2 = 1/(d-r)\n",
+ "dRrO2 = 1/(d-R-r)\n",
+ "EO2 = MF -((q/(2*pi*e0))*(dRrO2+drO2))\n",
+ "print\"EO2 = kV/m \\t\",EO2\n",
+ "\n",
+ "#field at the inner point of subconductor #1 \n",
+ "drI1 = 1/(d-r)\n",
+ "dRrI1 = 1/(d+R-r)\n",
+ "EI1 = MSF -((q/(2*pi*e0))*(drI1+dRrI1))\n",
+ "print\"EI1 = kV/m \\t\",EI1\n",
+ "#field at the inner point of subconductor #2 \n",
+ "drI2 = 1/(d+r)\n",
+ "dRrI2 = 1/(d-R+r)\n",
+ "EI2 = MSF -((q/(2*pi*e0))*(dRrI2+drI2)) \n",
+ "print\"EI2 = kV/m \\t\",EI2\n",
+ "\n",
+ "#(part c)Average of the maximim gradient\n",
+ "print\"\\tPart c\\t\"\n",
+ "Eavg = (EO1+EO2)/2\n",
+ "print\"The average of the maximum gradient = kV/m \\t\",Eavg\n",
+ "\n",
+ "\n",
+ "#Answers might vary due to round off error\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 2_7 pgno:69"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 4,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "Electric Feild = V/m \t30015596280.4\n"
+ ]
+ }
+ ],
+ "source": [
+ "#Chapter 2, Exmaple 7, page 69\n",
+ "#Electric feild induced at x\n",
+ "from math import pi\n",
+ "e0 = 8.85418*10**-12 #Epselon nought\n",
+ "q = 1 # C/m\n",
+ "C = (q/(2*pi*e0))\n",
+ "#Based on figure 2.33\n",
+ "E = C-(C*(1./3.+1./7.))+(C*(1+1./5.+1./9.))+(C*(1./5.+1./9.))-(C*(1./3.+1./7.))\n",
+ "print\"Electric Feild = V/m \\t\",E\n",
+ "\n",
+ "#Answers might vary due to round off error\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 2_8 pgno:70"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 5,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "\n",
+ "Thickness of graded design= cm 4.24264068712\n",
+ "Curve = cm**2 62.4264068712\n",
+ "V1 = cm**3 47402.906725\n",
+ "Thickness of regular design = cm 14.684289433\n",
+ "V2 = cm**3 861.944682812\n"
+ ]
+ }
+ ],
+ "source": [
+ "#Chapter 2, Exmaple 8, page 70\n",
+ "#Calculate the volume of the insulator\n",
+ "#Thinkness of graded design\n",
+ "from math import e\n",
+ "from math import pi\n",
+ "V = 150*(2)**0.5\n",
+ "Ebd = 50\n",
+ "T = V/Ebd\n",
+ "print\"\\nThickness of graded design= cm \",T\n",
+ "#Based on figure 2.24\n",
+ "r = 2 # radius of the conductor\n",
+ "l = 10 #length of graded cylinder; The textbook uses 10 instead of 20\n",
+ "zr = l*(T+r)\n",
+ "print\"Curve = cm**2 \",zr\n",
+ "#Volume of graded design V1\n",
+ "V1 = 4*pi*zr*(zr-r)\n",
+ "print\"V1 = cm**3 \",V1 #Unit is wrong in the textbook\n",
+ "#Thickness of regular design as obtained form Eq.2.77\n",
+ "pow = V/(2*Ebd)\n",
+ "t = 2*(e**pow-1)\n",
+ "print\"Thickness of regular design = cm \",t\n",
+ "#Volume of regular design V2\n",
+ "V2 = pi*((2+t)**2-4)\n",
+ "print\"V2 = cm**3 \",V2#unit not mentioned in textbook\n",
+ " \n",
+ "#Answers may vary due to round off error\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 2_11 pgno:75"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 6,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "The values of Phi2 and Phi4 are: [[ -3.6568 326.5 ]\n",
+ " [ 261.92857143 -4.37537287]]\n"
+ ]
+ }
+ ],
+ "source": [
+ "#Chapter 2, Exmaple 11, page 75\n",
+ "#Calculate the potential within the mesh\n",
+ "#Based on figure 2.38(b)\n",
+ "#equations are obtained using Eq.2.46\n",
+ "import numpy\n",
+ "from numpy import linalg\n",
+ "A1 = 1/2*(0.54+0.16)\n",
+ "A2 = 1/2*(0.91+0.14)\n",
+ "S = numpy.matrix([[0.5571, -0.4571, -0.1],[-0.4751, 0.828, 0.3667],[-0.1, 0.667, 0.4667]])\n",
+ "#By obtaining the elements of the global stiffness matrix(Sadiku,1994)\n",
+ "#and by emplying the Eq.2.49(a)\n",
+ "S1 = numpy.matrix([[1.25, -0.014],[-0.014, 0.8381]])\n",
+ "S2 = numpy.matrix([[-0.7786, -0.4571],[-0.4571, -0.3667]])\n",
+ "Phi13 = numpy.matrix([[0], [10]])\n",
+ "val1 = S2*Phi13\n",
+ "Phi24 = val1/S1\n",
+ "print\"The values of Phi2 and Phi4 are:\",Phi24\n",
+ "\n",
+ "#Answers may vary due to round of error \n",
+ "\n"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": null,
+ "metadata": {
+ "collapsed": true
+ },
+ "outputs": [],
+ "source": []
+ }
+ ],
+ "metadata": {
+ "kernelspec": {
+ "display_name": "Python 2",
+ "language": "python",
+ "name": "python2"
+ },
+ "language_info": {
+ "codemirror_mode": {
+ "name": "ipython",
+ "version": 2
+ },
+ "file_extension": ".py",
+ "mimetype": "text/x-python",
+ "name": "python",
+ "nbconvert_exporter": "python",
+ "pygments_lexer": "ipython2",
+ "version": "2.7.9"
+ }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 0
+}
|