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+{
+ "metadata": {
+ "celltoolbar": "Raw Cell Format",
+ "name": "",
+ "signature": "sha256:58e66a1486b17622aacd34bb93b225c18134442ddc1f2fbedecd0abdd0c9b88e"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "A TEXTBOOK OF PHYSICAL CHEMISTRY BY K.I. KAPOOR"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "CHAPTER NUMBER 1 : EQUILIBRIUM BETWEEN PHASES"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "EXAMPLE NUMBER 1.5.1 : PAGE NUMBER 10"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math \n",
+ "T1 = 234.5 # Temperature in K\n",
+ "P = 1 # Pressure in atm\n",
+ "rho1 = 14.19 # Density of solid Hg in g/(cm**3)\n",
+ "rho2 = 13.70 # Density of liquid Hg in g/(cm**3)\n",
+ "V = 200.59 # volume of liquid and solid in g/mol\n",
+ "delV = ((V/rho2)-(V/rho1))*(10**-3)# in dm**3/mol\n",
+ "delTdelP = 0.0051 # K/atm\n",
+ "R1 = 8.314 # in J\n",
+ "R2 = 0.082 # in (dm)**3/atm\n",
+ "delH = ((delV*T1)/(delTdelP))*(R1/R2)*10**-3;#molar heat of fusion in kJ/mol\n",
+ "print \" delH = \",round(delH,4),\"(KJ)/mol \"\n",
+ "T2 = 273# in K\n",
+ "delP = (delH*(R2/R1)*(T2-T1))/(delV*T1)*10**3;#pressure required to raise melting point to T2 in atm\n",
+ "print \" delP = \",round(delP,4),\"atm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ " delH = 2.3571 (KJ)/mol \n",
+ " delP = 7549.0196 atm\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "EXAMPLE NUMBER 1.5.2 : PAGE NUMBER 15"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math;\n",
+ "T1=373.15;#in K\n",
+ "P=1;#atm\n",
+ "Vv=1674;#in cm**3/gm\n",
+ "delPdelT=27.12;#in torr/K\n",
+ "R1=8.314;#in J\n",
+ "R2=0.082;#in atm/(dm)**3\n",
+ "delH=((delPdelT)/760)*T1*((Vv*10**-3)*18)*(R1/R2)\n",
+ "print \" delH = \",round(delH,4),\" J/mol \""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ " delH = 40680.2549 J/mol \n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "EXAMPLE NUMBER 1.5.3 : PAGE NUMBER 16"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math;\n",
+ "T1=313.75;#in K\n",
+ "P1=59.1;#in torr\n",
+ "T2=353.15;#in K\n",
+ "P2=298.7;#in torr\n",
+ "R=2.303*8.314;#in J/(K*mol)\n",
+ "delH=R*math.log10(P2/P1)*((T2*T1)/(T2-T1))\n",
+ "print \" delH= \",round(delH,4),\" J/mol \""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ " delH= 37888.375 J/mol \n"
+ ]
+ }
+ ],
+ "prompt_number": 9
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "EXAMPLE NUMBER 1.5.4 : PAGE NUMBER 16"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "T1=325.15;#in K\n",
+ "T2=338.15;#in K\n",
+ "P2=760;#in torr\n",
+ "DelHm_v=10.5;#\n",
+ "P1=P2/(10**((DelHm_v/2.303)*((T2/T1)-1)));#in torr\n",
+ "print \" P1= \",round(P1,4),\"torr \"\n",
+ "P=200;#in torr\n",
+ "T=T2/(1+((2.303/10.5)*math.log10(P2/P)));#in K\n",
+ "print \" T =\",round(T,4),\" K \"\n",
+ "I=math.log10(P2)-(((DelHm_v*T2)/2.303)*(-1/T2));#\n",
+ "print \" I = \",round(I,4)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ " P1= 499.4901 torr \n",
+ " T = 306.1154 K \n",
+ " I = 7.4401\n"
+ ]
+ }
+ ],
+ "prompt_number": 13
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "EXAMPLE NUMBER 1.5.5 : PAGE NUMBER 17"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math;\n",
+ "P=760;#in torr\n",
+ "dP=52;#in torr\n",
+ "dT=2;#in K\n",
+ "DelH_RTb=10.5;#Trouton rule\n",
+ "Tb=(DelH_RTb*P)/(dP/dT)\n",
+ "print \" Tb = \",round(Tb,4),\" K\"\n",
+ "R=8.314;#in J/Kmol\n",
+ "DelH_v=(DelH_RTb*R*Tb)\n",
+ "print \" DelH_v = \",round(DelH_v,4),\"J/mol \""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ " Tb = 306.9231 K\n",
+ " DelH_v = 26793.4638 J/mol \n"
+ ]
+ }
+ ],
+ "prompt_number": 16
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+} \ No newline at end of file