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+{
+ "cells": [
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "# Chapter 1 CRYSTAL STRUCTURES"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 1_4 pgno:22"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 1,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "a= 1.0\n",
+ "r=a/2 = 0.5\n",
+ "Volume of one atom ,v=((4∗%pi∗(rˆ3))/3)= 0.523598775598\n",
+ "Total Volume of the cube ,V=aˆ3 = 1.0\n",
+ "Fp(S.C)=(v∗100/V)= 52.3598775598\n"
+ ]
+ }
+ ],
+ "source": [
+ "#exa 1.4\n",
+ "from math import pi\n",
+ "a=1.\n",
+ "print \"a= \",a # initializing value of lattice constant(a)=1.\n",
+ "r=a/2.\n",
+ "print \"r=a/2 = \",r # initializing value of radius of atom for simple cubic .\n",
+ "v=((4*pi*(r**3))/3)\n",
+ "print \"Volume of one atom ,v=((4∗%pi∗(rˆ3))/3)= \",v # calcuation . \n",
+ "V=a**3\n",
+ "print \"Total Volume of the cube ,V=aˆ3 = \",V # calcuation .\n",
+ "Fp=(v*100/V)\n",
+ "print \"Fp(S.C)=(v∗100/V)= \",Fp,# calculation"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 1_5 pgno:24"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 2,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "a= 1.0\n",
+ "Radius of the atoms,r=(sqrt(3)∗(aˆ2/4)) = 0.433012701892\n",
+ "Volume of two atom,v=((4∗pi∗(rˆ3))/3)∗2 = 0.680174761588\n",
+ "Total Volume of the cube ,V=aˆ3 = 1.0\n",
+ "Fp(B.C.C)=(v∗100/V)= 68.0174761588 %\n"
+ ]
+ }
+ ],
+ "source": [
+ "#exa 1.5\n",
+ "from math import sqrt\n",
+ "a=1.\n",
+ "print \"a= \",a # initializing value of lattice constant(a)=1.\n",
+ "r=(sqrt(3)*(a**2/4))\n",
+ "print \"Radius of the atoms,r=(sqrt(3)∗(aˆ2/4)) = \",r # initializing value of radius of atom for BCC.\n",
+ "v=((4*pi*(r**3))/3)*2\n",
+ "print \"Volume of two atom,v=((4∗pi∗(rˆ3))/3)∗2 = \",v # calcuation \n",
+ "V=a**3\n",
+ "print \"Total Volume of the cube ,V=aˆ3 = \",V # calcuation .\n",
+ "Fp=(v*100/V)\n",
+ "print \"Fp(B.C.C)=(v∗100/V)= \",Fp,\"%\" # calculation"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## example 1_6 pgno:25"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 3,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "a= 1\n",
+ "Radius of the atom,r=(a/(2∗sqrt(2)))= 0.353553390593\n",
+ "Volume of the four atom,v=(((4∗pi∗(rˆ3))/3)∗4)= 0.740480489693\n",
+ "Total volume of the cube ,V=aˆ3= 2\n",
+ "Fp(F.C.C)=(v∗100/V)= 37.0240244847 %\n"
+ ]
+ }
+ ],
+ "source": [
+ "#exa 1.6\n",
+ "a=1\n",
+ "print \"a= \",a # initializing value of lattice constant(a)=1.\n",
+ "r=(a/(2*sqrt(2)))\n",
+ "print \"Radius of the atom,r=(a/(2∗sqrt(2)))= \",r # initializing value of radius of atom for FCC .\n",
+ "v=(((4*pi*(r**3))/3)*4)\n",
+ "print \"Volume of the four atom,v=(((4∗pi∗(rˆ3))/3)∗4)= \",v # calcuation \n",
+ "V=a^3\n",
+ "print \"Total volume of the cube ,V=aˆ3= \",V # calcuation .\n",
+ "Fp=(v*100/V)\n",
+ "print \"Fp(F.C.C)=(v∗100/V)= \",Fp,\"%\" # calculation\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## example 1_8 pgno:26"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 4,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "a= 1\n",
+ "Radius of the atom , r=(sqrt (3)∗a/8))= 0.216506350946\n",
+ "v=(((4∗pi∗(rˆ3))/3)∗8) = 0.340087380794\n",
+ "V=aˆ3= 2\n",
+ "Fp(Diamond)=(v∗100/V) = 17.0043690397 %\n"
+ ]
+ }
+ ],
+ "source": [
+ "#Exa 1.8 \n",
+ "a=1\n",
+ "print \"a= \",a # initializing value of lattice constant(a)=1.\n",
+ "r=((sqrt(3)*a/8))\n",
+ "print \"Radius of the atom , r=(sqrt (3)∗a/8))= \",r # initializing value of radius of atom for diamond .\n",
+ "v=(((4*pi*(r**3))/3)*8)\n",
+ "print \"v=(((4∗pi∗(rˆ3))/3)∗8) = \",v # calcuation .\n",
+ "V=a^3\n",
+ "print \"V=aˆ3= \",V # calcuation .\n",
+ "Fp=(v*100/V)\n",
+ "print \"Fp(Diamond)=(v∗100/V) = \",Fp,\"%\" # calculation\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## example 1_9 pgno:28"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 5,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "a = 5e-08 cm\n",
+ "Radius of the atom,r=(sqrt(3)∗(a/4))= 2.16506350946e-08\n",
+ "Volume of the two atoms ,v=((4∗pi∗(rˆ3))/3)∗2= 8.50218451985e-23\n",
+ "Total Volume of the cube ,V=aˆ3 = 1.25e-22\n",
+ "Fp(B.C.C)=(v∗100/V) = 68.0174761588 %\n"
+ ]
+ }
+ ],
+ "source": [
+ "#exa 1.9\n",
+ "a=5*10**-8\n",
+ "print \"a = \",a,\" cm\" # initializing value of lattice constant .\n",
+ "r=(sqrt(3)*(a/4))\n",
+ "print \"Radius of the atom,r=(sqrt(3)∗(a/4))= \",r # initializing value of radius of atom for BCC.\n",
+ "v=((4*pi*(r**3))/3)*2\n",
+ "print \"Volume of the two atoms ,v=((4∗pi∗(rˆ3))/3)∗2= \",v # calcuation .\n",
+ "V=a**3\n",
+ "print \"Total Volume of the cube ,V=aˆ3 = \",V # calcuation .\n",
+ "Fp=(v*100/V)\n",
+ "print \"Fp(B.C.C)=(v∗100/V) = \",Fp,\"%\" # calculation"
+ ]
+ }
+ ],
+ "metadata": {
+ "kernelspec": {
+ "display_name": "Python 2",
+ "language": "python",
+ "name": "python2"
+ },
+ "language_info": {
+ "codemirror_mode": {
+ "name": "ipython",
+ "version": 2
+ },
+ "file_extension": ".py",
+ "mimetype": "text/x-python",
+ "name": "python",
+ "nbconvert_exporter": "python",
+ "pygments_lexer": "ipython2",
+ "version": "2.7.10"
+ }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 0
+}
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