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diff --git a/modern_physics_by_Satish_K._Gupta/chap8.ipynb b/modern_physics_by_Satish_K._Gupta/chap8.ipynb deleted file mode 100755 index 1b06633c..00000000 --- a/modern_physics_by_Satish_K._Gupta/chap8.ipynb +++ /dev/null @@ -1,994 +0,0 @@ -{
- "metadata": {
- "name": "",
- "signature": "sha256:a40c0c75d3ca70fc3ecf4f82797b161ff3f00d80a8c81333303a3e01cdc2b09b"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 8 Thermal effects of current"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.1 Page no 258"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "P=100.0 #W\n",
- "V=220.0 #V\n",
- "\n",
- "#Calculation\n",
- "I=P/V\n",
- "R=V**2/P\n",
- "\n",
- "#Result\n",
- "print\"Resistance is\",R,\"ohm\"\n",
- "print\"Current capacity is\",round(I,3),\"A\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Resistance is 484.0 ohm\n",
- "Current capacity is 0.455 A\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.2 Page no 258"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "e=1.6*10**-19 #C\n",
- "P=100 #W\n",
- "V=200.0 #V\n",
- "t=1\n",
- "\n",
- "#Calculation\n",
- "I=P/V\n",
- "q=I*t\n",
- "N=q/e\n",
- "\n",
- "#Result\n",
- "print\"Number of electrons is\", N"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Number of electrons is 3.125e+18\n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.3 Page no 258"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "P1=60 #W\n",
- "P2=100.0 \n",
- "\n",
- "#Calculation\n",
- "I=P1/P2\n",
- "\n",
- "#Result\n",
- "print\"Hence 100 W bulb draws more current\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Hence 100 W bulb draws more current\n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.4 Page no 259"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "P1=60.0 #W\n",
- "P2=100\n",
- "\n",
- "#Calculation\n",
- "R=P2/P1\n",
- "\n",
- "#Result\n",
- "print\"(a) 60 W bulb will dissipate more power.\"\n",
- "print\"(b) Since 60 W bulb is dissipating more power, it glows brighter.\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) 60 W bulb will dissipate more power.\n",
- "(b) Since 60 W bulb is dissipating more power, it glows brighter.\n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.5 Page no 259"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "P1=500.0 #W\n",
- "V1=220 #V\n",
- "P2=100.0\n",
- "V2=220\n",
- "\n",
- "#Calculation\n",
- "R1=V1**2/P1\n",
- "R2=V2**2/P2\n",
- "I=V2/(R1+R2)\n",
- "P11=I**2*R1\n",
- "P22=I**2*R2\n",
- "\n",
- "#Result\n",
- "print\"(i) Power consumed by heater is\",round(P11,2),\"W\"\n",
- "print\"(ii) Power consumed by electric bulb is\",round(P22,2),\"W\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(i) Power consumed by heater is 13.89 W\n",
- "(ii) Power consumed by electric bulb is 69.44 W\n"
- ]
- }
- ],
- "prompt_number": 18
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.6 Page no 259"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "P=100.0 #W\n",
- "V=220 #V\n",
- "V1=110\n",
- "\n",
- "#Calculation\n",
- "R=V**2/P\n",
- "P1=V1**2/R\n",
- "\n",
- "#Result\n",
- "print\"Power consumed by the bulb is\",P1,\"W\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Power consumed by the bulb is 25.0 W\n"
- ]
- }
- ],
- "prompt_number": 23
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.7 Page no 259"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "P=550 #W\n",
- "V=220 #V\n",
- "V1=222.2 #V\n",
- "V2=217.8 #V\n",
- "\n",
- "#Calculation\n",
- "R=V**2/P\n",
- "P=V1**2/R\n",
- "P1=V2**2/R\n",
- "\n",
- "#Result\n",
- "print\"minimum power is\",round(P,0),\"W\"\n",
- "print\"maximum power is\",round(P1,0),\"W\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "minimum power is 561.0 W\n",
- "maximum power is 539.0 W\n"
- ]
- }
- ],
- "prompt_number": 30
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.8 Page no 259"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "V=220\n",
- "P=60.0 #W\n",
- "P1=85\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "R=V**2/P\n",
- "V1=math.sqrt(P1*R)\n",
- "\n",
- "#Result\n",
- "print\"Voltage fluctuation is\",round(V1,1),\"V\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Voltage fluctuation is 261.9 V\n"
- ]
- }
- ],
- "prompt_number": 34
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.9 Page no 259"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "P=50*10**3 #W\n",
- "V=5000.0\n",
- "R=20\n",
- "\n",
- "#Calculation\n",
- "I=P/V\n",
- "P1=I**2*R\n",
- "P2=P-P1\n",
- "\n",
- "#Result \n",
- "print\"Power received by the factory is\",P2*10**-3,\"Kw\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Power received by the factory is 48.0 Kw\n"
- ]
- }
- ],
- "prompt_number": 42
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.10 Page no 260"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "R2=2 #ohm\n",
- "R3=2 #ohm\n",
- "I=3 #A\n",
- "\n",
- "#Calculation\n",
- "P=I**2*R2\n",
- "R1=(R2*R3)/(R2+R3)\n",
- "P1=I**2*R1\n",
- "D=P+P1\n",
- "\n",
- "#Result\n",
- "print\"The maximum power is\",D,\"W\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The maximum power is 27 W\n"
- ]
- }
- ],
- "prompt_number": 50
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.11 Page no 260"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "R=0.5 #ohm\n",
- "I=100 #A\n",
- "T=24*60*60\n",
- "\n",
- "#Calculation\n",
- "Q=I**2*R*T\n",
- "\n",
- "#Result\n",
- "print\"Energy is being lost per day in the form of heat is\",Q*10**-8,\"*10**8 J\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Energy is being lost per day in the form of heat is 4.32 *10**8 J\n"
- ]
- }
- ],
- "prompt_number": 59
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.12 Page no 260"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "R=50.0 #ohm\n",
- "V=10 #V\n",
- "T=3600 #s\n",
- "\n",
- "#Calculation\n",
- "I=V/R\n",
- "W=I**2*R*T\n",
- "\n",
- "#Result \n",
- "print\"The source of this energy is\",W,\"J\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The source of this energy is 7200.0 J\n"
- ]
- }
- ],
- "prompt_number": 64
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.13 Page no 260"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "P=100 #W\n",
- "V=200 #V\n",
- "T=60\n",
- "I=10\n",
- "\n",
- "#Calculation\n",
- "R=V**2/P\n",
- "W=(P**2/R)*I*T\n",
- "\n",
- "#Result \n",
- "print\"The heat & light produced by the bulb is\",W,\"J\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The heat & light produced by the bulb is 15000 J\n"
- ]
- }
- ],
- "prompt_number": 70
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.14 Page no 260"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "R1=3 #ohm\n",
- "R2=6\n",
- "R3=2\n",
- "V=12 #V\n",
- "T=300 #s\n",
- "\n",
- "#Calculation\n",
- "R12=R1*R2/(R1+R2)\n",
- "R=R12+R3\n",
- "I=V/R\n",
- "I1=I*R2/(R1+R2)\n",
- "I2=I*R1/(R1+R2)\n",
- "Q1=I1**2*R1*T\n",
- "Q2=I2**2*R2*T\n",
- "Q3=I**2*R3*T\n",
- "\n",
- "#Result \n",
- "print\"Heat produced in resistance R1 is\",Q1,\"J\"\n",
- "print\"Heat produced in resistance R2 is\",Q2,\"J\"\n",
- "print\"Heat produced in resistance R3 is\",Q3,\"J\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Heat produced in resistance R1 is 3600 J\n",
- "Heat produced in resistance R2 is 1800 J\n",
- "Heat produced in resistance R3 is 5400 J\n"
- ]
- }
- ],
- "prompt_number": 82
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.15 Page no 260"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "t1=300 #S\n",
- "t2=600 #S\n",
- "\n",
- "#Calculation\n",
- "t=(t1+t2)/60.0\n",
- "\n",
- "#Result\n",
- "print\"Time required to boil water is\",t,\"minute\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Time required to boil water is 15.0 minute\n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.16 Page no 261"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "R=100 #ohm\n",
- "I=0.5 #A\n",
- "W=10*10**-3 #Kg\n",
- "M=250*10**-3 #Kg\n",
- "T=1800 #s\n",
- "C=4.2*10**3\n",
- "\n",
- "#Calculation\n",
- "Q=I**2*R*T\n",
- "V=Q/((W+M)*C)\n",
- "\n",
- "#Result\n",
- "print\"The rise of the temperature is\",round(V,1),\"C\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The rise of the temperature is 41.2 C\n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.17 Page no 261"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "V=200\n",
- "R=100\n",
- "R1=121.0\n",
- "A=1000 #W\n",
- "B=400 #W\n",
- "C=400 #W\n",
- "T=116 #h\n",
- "G=2.50\n",
- "\n",
- "#Calculation\n",
- "D=V**2/R\n",
- "D1=V**2/R1\n",
- "E=A+B+C+D1\n",
- "F=E*T\n",
- "H=F*G\n",
- "\n",
- "#Result \n",
- "print\"The bill for february is\",round(H*10**-3,2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The bill for february is 617.87\n"
- ]
- }
- ],
- "prompt_number": 26
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.18 Page no 261"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "a=0.12 #KWh\n",
- "b=1.44 #KWh\n",
- "c=0.48 #KWh\n",
- "d=0.24 \n",
- "e=0.30\n",
- "i=2.70\n",
- "g=30\n",
- "\n",
- "#Calculation\n",
- "f=a+b+c+d+e\n",
- "h=2*g*f\n",
- "k=i*h\n",
- "\n",
- "#Result\n",
- "print\"Electric bill for 2 month is\", k"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Electric bill for 2 month is 417.96\n"
- ]
- }
- ],
- "prompt_number": 103
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.19 Page no 261"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "P=100*10**6 #W\n",
- "V1=20000\n",
- "V2=200 #V\n",
- "\n",
- "#Calculation\n",
- "I1=P/V1\n",
- "Q1=I1**2\n",
- "I2=P/V2\n",
- "Q2=I2**2\n",
- "\n",
- "#Result\n",
- "print\"Transmission done at V1=20,000 is\", Q1*10**-5,\"10**5\"\n",
- "print\"Transmission done at V2=200 V is\", Q2*10**-10,\"10**10\"\n",
- "print\"Less power wastage when transmission is done at Q1\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Transmission done at V1=20,000 is 250.0 10**5\n",
- "Transmission done at V2=200 V is 25.0 10**10\n",
- "Less power wastage when transmission is done at Q1\n"
- ]
- }
- ],
- "prompt_number": 105
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.20 Page no 262"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "p1=4.9*10**-7 #ohm m\n",
- "l1=8.456 #m\n",
- "b1=1.0 #mm\n",
- "t1=0.03*10**-6 #m\n",
- "l2=4.235\n",
- "A2=0.12*10**-6\n",
- "p2=1.1*10**-6\n",
- "\n",
- "#Calculation\n",
- "A1=b1*t1\n",
- "R1=p1*(l1/A1)\n",
- "R2=p2*(l2/A2)\n",
- "\n",
- "#Result\n",
- "print\"Rate for heat production for constantan ribbon is\", round(R1,3),\"W\"\n",
- "print\"Rate for heat production for nichrome ribbon is\",round(R2,3),\"W\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Rate for heat production for constantan ribbon is 138.115 W\n",
- "Rate for heat production for nichrome ribbon is 38.821 W\n"
- ]
- }
- ],
- "prompt_number": 115
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.21 Page no 262"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "V=50 #V\n",
- "I=12 #A\n",
- "d=70\n",
- "\n",
- "#Calculation\n",
- "g=V*I\n",
- "t=g*(d/100.0)\n",
- "v=t/I**2\n",
- "\n",
- "#Result \n",
- "print\"The resistance of the motor is\",round(v,2),\"ohm\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The resistance of the motor is 2.92 ohm\n"
- ]
- }
- ],
- "prompt_number": 76
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.22 Page no 262"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "a=100\n",
- "b=6\n",
- "c=8.0\n",
- "d=2.0\n",
- "f=0.50\n",
- "t=15*60\n",
- "\n",
- "#Calculation\n",
- "e=a-b*d\n",
- "x=b*f\n",
- "r=(e/c)-x\n",
- "r1=a*r\n",
- "r2=r**2*(r+b*f)\n",
- "r3=r1-r2\n",
- "M=r3*t\n",
- "\n",
- "#Result\n",
- "print\"Resistance in the charging circuit is\",r,\"ohm\"\n",
- "print\"The power supplied by the d.c source is\",r1,\"W\"\n",
- "print\"The power dissipated as heat is\",r2,\"W\"\n",
- "print\"The power stored in the battery is\",r3,\"W\"\n",
- "print\"Energy stored in the battery in 15 minute is\",M,\"J\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Resistance in the charging circuit is 8.0 ohm\n",
- "The power supplied by the d.c source is 800.0 W\n",
- "The power dissipated as heat is 704.0 W\n",
- "The power stored in the battery is 96.0 W\n",
- "Energy stored in the battery in 15 minute is 86400.0 J\n"
- ]
- }
- ],
- "prompt_number": 96
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.23 Page no 262"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "V=64 #V\n",
- "e=2.0 #V\n",
- "n=8\n",
- "r=1/8.0\n",
- "R=7 #ohm\n",
- "I=3.5 #A\n",
- "b=3600\n",
- "\n",
- "#Calculation\n",
- "Te=e*n\n",
- "R1=r*n\n",
- "E=V*I\n",
- "E1=Te*I\n",
- "E11=I**2*(R+R1)\n",
- "Em=E-(E1+E11)\n",
- "Em1=Em*b\n",
- "Ec=E1*b\n",
- "\n",
- "#Result\n",
- "print\"(a) Mechanical energy yielded by motor is\", Em1,\"J\"\n",
- "print\"(b) Chemical energy stored in the battery is\",Ec,\"J\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) Mechanical energy yielded by motor is 252000.0 J\n",
- "(b) Chemical energy stored in the battery is 201600.0 J\n"
- ]
- }
- ],
- "prompt_number": 130
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8.25 Page no 263"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "E=24 #V\n",
- "r=4 #ohm\n",
- "a=1\n",
- "\n",
- "#Calculation\n",
- "R=r/(2.0-a)\n",
- "I=E/(R+r)\n",
- "\n",
- "#Result\n",
- "print\"Current drawn from the battery is\", I,\"A\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current drawn from the battery is 3.0 A\n"
- ]
- }
- ],
- "prompt_number": 134
- }
- ],
- "metadata": {}
- }
- ]
-}
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