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diff --git a/modern_physics_by_Satish_K._Gupta/chap4.ipynb b/modern_physics_by_Satish_K._Gupta/chap4.ipynb new file mode 100644 index 00000000..488631fb --- /dev/null +++ b/modern_physics_by_Satish_K._Gupta/chap4.ipynb @@ -0,0 +1,397 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:1087fb8dbcb5b183b8a1d36b431412b33d35209d5f6a3a237469594e817213fb"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 4 Gauss theorem"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 4.1 Page no 88"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "E=25 #V/m\n",
+ "s=150*10**-4 #m**2\n",
+ "a=60 #degree\n",
+ "\n",
+ "#Calculation\n",
+ "import math\n",
+ "A=E*s*math.cos(a*3.14/180.0)\n",
+ "\n",
+ "#Result\n",
+ "print\"Flux of the electric field is\",round(A,4),\"Nm**2/C\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Flux of the electric field is 0.1877 Nm**2/C\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 4.2 Page no 88"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "E=3*10**3 #N/C\n",
+ "S=10**-2 #m**2\n",
+ "\n",
+ "#Calculation\n",
+ "import math\n",
+ "a=E*S\n",
+ "A=E*S*math.cos(60*3.14/180.0)\n",
+ "\n",
+ "#Result\n",
+ "print\"(a) Flux of the field is\",a,\"Nm**2/C\"\n",
+ "print\"(b) Flux through the square is\", round(A,0),\"Nm**2/C\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a) Flux of the field is 30.0 Nm**2/C\n",
+ "(b) Flux through the square is 15.0 Nm**2/C\n"
+ ]
+ }
+ ],
+ "prompt_number": 10
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 4.3 Page no 88"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "e=8.854*10**-12 #C**2/N/m**2\n",
+ "q=1 #C\n",
+ "\n",
+ "#Calculation\n",
+ "a=q/e\n",
+ "\n",
+ "#Result\n",
+ "print\"Number of electric lines are\",round(a*10**-11,3)*10**11"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Number of electric lines are 1.129e+11\n"
+ ]
+ }
+ ],
+ "prompt_number": 14
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 4.4 Page no 88"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "a=8*10**3 #Nm**2/C\n",
+ "e=8.854*10**-12 #C**2/N/m**2\n",
+ "\n",
+ "#Calculation\n",
+ "q=a*e\n",
+ "\n",
+ "#Result\n",
+ "print\"(a) Net charge inside the box is\",q,\"C\"\n",
+ "print\"(b) If the net outward flux is zero,we can't conclude that the charge inside the box is zero.\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a) Net charge inside the box is 7.0832e-08 C\n",
+ "(b) If the net outward flux is zero,we can't conclude that the charge inside the box is zero.\n"
+ ]
+ }
+ ],
+ "prompt_number": 18
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 4.5 Page no 89"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "q=10**-5\n",
+ "e=8.854*10**-12\n",
+ "\n",
+ "#Calculation\n",
+ "a=q/(6.0*e)\n",
+ "\n",
+ "#Result\n",
+ "print\"Magnitude of electric flux is\", round(a*10**-5,2),\"*10**5 Nm**2/C\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Magnitude of electric flux is 1.88 *10**5 Nm**2/C\n"
+ ]
+ }
+ ],
+ "prompt_number": 23
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 4.6 Page no 89"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "E=9*10**4 #N/C\n",
+ "r=0.04 #m\n",
+ "m=9*10**9\n",
+ "\n",
+ "#Calculation\n",
+ "l=E*r/(2.0*m)\n",
+ "\n",
+ "#Result\n",
+ "print\"Linear charge density is\", l,\"C/m\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Linear charge density is 2e-07 C/m\n"
+ ]
+ }
+ ],
+ "prompt_number": 26
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 4.7 Page no 89"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "a=5*10**-6 #C/m**2\n",
+ "e=8.854*10**-12 #C**2/Nm**2\n",
+ "r=0.1 #m\n",
+ "a1=60 #Degree\n",
+ "\n",
+ "#Calculation\n",
+ "import math\n",
+ "A=(a*math.pi*r**2*math.cos(a1*3.14/180.0))/(2.0*e)\n",
+ "\n",
+ "#Result\n",
+ "print\"Electric flux is\", round(A*10**-3,2),\"*10**3 N m**2/C\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Electric flux is 4.44 *10**3 N m**2/C\n"
+ ]
+ }
+ ],
+ "prompt_number": 31
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 4.8 Page no 89"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "a=17*10**-22 #C/m**2\n",
+ "e=8.854*10**-12\n",
+ "\n",
+ "#Calculation\n",
+ "E=a/e\n",
+ "\n",
+ "#Result\n",
+ "print\"(a) Electric field to the left of the plate is zero\"\n",
+ "print\"(b) Electric field to the right of the plate is zero\"\n",
+ "print\"(c) Electric field between the plates is\",round(E*10**10,2)*10**-10,\"N/C\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a) Electric field to the left of the plate is zero\n",
+ "(b) Electric field to the right of the plate is zero\n",
+ "(c) Electric field between the plates is 1.92e-10 N/C\n"
+ ]
+ }
+ ],
+ "prompt_number": 38
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 4.9 Page no 89"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "q=1.6*10**-7 #C\n",
+ "R=0.12 #m\n",
+ "m=9*10**9\n",
+ "r=0.18\n",
+ "\n",
+ "#Calculation\n",
+ "E=(m*q)/R**2\n",
+ "E1=(m*q)/r**2\n",
+ "\n",
+ "#Result\n",
+ "print\"(a) ELectric field inside the sphere is zero\"\n",
+ "print\"(b) Electric field outside the sphere is\",E,\"N/C\"\n",
+ "print\"(c) Electric field at a point 18 cm from the centre is\", round(E1*10**-4,2),\"*10**4 N/C\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a) ELectric field inside the sphere is zero\n",
+ "(b) Electric field outside the sphere is 100000.0 N/C\n",
+ "(c) Electric field at a point 18 cm from the centre is 4.44 *10**4 N/C\n"
+ ]
+ }
+ ],
+ "prompt_number": 51
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 4.11 Page no 90"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "e=50\n",
+ "V=0.2\n",
+ "m=9*10**9\n",
+ "\n",
+ "#Calculation\n",
+ "q=e*V**2/m\n",
+ "\n",
+ "#Result\n",
+ "print\"Charge contained in the sphere is\",round(q*10**10,2)*10**-10,\"C\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Charge contained in the sphere is 2.22e-10 C\n"
+ ]
+ }
+ ],
+ "prompt_number": 56
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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