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diff --git a/modern_physics_by_Satish_K._Gupta/chap32.ipynb b/modern_physics_by_Satish_K._Gupta/chap32.ipynb new file mode 100644 index 00000000..69ecaa80 --- /dev/null +++ b/modern_physics_by_Satish_K._Gupta/chap32.ipynb @@ -0,0 +1,381 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:1a205c66d8c05960f2478abf5942d3dc43db8b63d7327dc1bc8decd646c4e601"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 32 Nuclear reactions"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 32.3 Page no 874"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "r1=6.015126\n",
+ "r2=1.008665\n",
+ "p1=4.002603\n",
+ "p2=3.016049\n",
+ "a=931\n",
+ "\n",
+ "#Calculation\n",
+ "R=r1+r2\n",
+ "P=p1+p2\n",
+ "M=R-P\n",
+ "E=M*a\n",
+ "\n",
+ "#Result\n",
+ "print\"Energy released is\",round(E,2),\"Mev\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Energy released is 4.78 Mev\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 32.4 Page no 874"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "P=400*10**6 #J/s\n",
+ "c=3.0*10**8\n",
+ "\n",
+ "#Calculation\n",
+ "E=P*24*60*60\n",
+ "m=E/c**2\n",
+ "\n",
+ "#Result\n",
+ "print\"U235 is\",m*10**3,\"g\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "U235 is 0.384 g\n"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 32.5 Page no 874"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "A=6.023*10**23\n",
+ "w=235.0\n",
+ "E=200\n",
+ "e=1.6*10**-13\n",
+ "\n",
+ "#Calculation\n",
+ "E1=((A*E)/w)*e\n",
+ "E2=E1/(1000.0*3600.0)\n",
+ "\n",
+ "#Result\n",
+ "print\"Energy released is\", round(E2*10**-4,3),\"*10**4 KWh\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Energy released is 2.278 *10**4 KWh\n"
+ ]
+ }
+ ],
+ "prompt_number": 17
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 32.6 Page no 874"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "E=7.6*10**13 #J\n",
+ "E1=200.0*1.6*10**-13\n",
+ "h=6.023*10**23\n",
+ "a=235\n",
+ "\n",
+ "#Calculation\n",
+ "n=E/E1\n",
+ "M=(a*n)/h\n",
+ "\n",
+ "#Result\n",
+ "print\"(i) Number of uranium atom is\",n\n",
+ "print\"(ii) Mass of uranium is\",round(M,2),\"g\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(i) Number of uranium atom is 2.375e+24\n",
+ "(ii) Mass of uranium is 926.66 g\n"
+ ]
+ }
+ ],
+ "prompt_number": 22
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 32.7 Page no 874"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "m1=235.043933\n",
+ "m2=140.917700\n",
+ "m3=91.895400\n",
+ "n1=1.0086651\n",
+ "a=931.5\n",
+ "\n",
+ "#Calculation\n",
+ "Q=(m1-m2-m3-2*(n1))*a\n",
+ "\n",
+ "#Result\n",
+ "print\"Energy released is\",round(Q,2),\"Mev\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Energy released is 198.88 Mev\n"
+ ]
+ }
+ ],
+ "prompt_number": 26
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 32.8 Page no 874"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "M1=1.007825\n",
+ "M2=4.002603\n",
+ "M3=0.000549\n",
+ "A=931.5\n",
+ "S=4\n",
+ "W=2\n",
+ "\n",
+ "#Calculation\n",
+ "Q=((S*M1-M2-W*M3)*A)\n",
+ "\n",
+ "#Result\n",
+ "print\"The energy is\",round(Q,2),\"MeV\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The energy is 25.71 MeV\n"
+ ]
+ }
+ ],
+ "prompt_number": 30
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 32.9 Page no 875"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "M1=1.008 #a.m.u.\n",
+ "M2=4.004 #a.m.u.\n",
+ "M3=7.016 #a.m.u.\n",
+ "A=2\n",
+ "W=931\n",
+ "\n",
+ "#Calculation\n",
+ "Q=(M3+M1-A*M2)*W\n",
+ "\n",
+ "#Result\n",
+ "print\"The initial energy of each alpha-particle is\",Q,\"MeV\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The initial energy of each alpha-particle is 14.896 MeV\n"
+ ]
+ }
+ ],
+ "prompt_number": 33
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 32.10 Page no 875"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "M1=235.0439\n",
+ "M2=93.9065\n",
+ "M3=139.9055\n",
+ "M4=1.00866\n",
+ "S=931.5\n",
+ "\n",
+ "#Calculation\n",
+ "Q=(M1-M2-M3-M4)*S\n",
+ "\n",
+ "#Result\n",
+ "print\"Total energy is\",round(Q,2),\"MeV\"\n",
+ "print\"All the available energy does not appear as the kinetic energy of fission products\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Total energy is 207.95 MeV\n",
+ "All the available energy does not appear as the kinetic energy of fission products\n"
+ ]
+ }
+ ],
+ "prompt_number": 38
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 32.11 Page no 875"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "M1=2.014102\n",
+ "M2=3.016049\n",
+ "M3=4.002603\n",
+ "M4=1.008665\n",
+ "S=931.5\n",
+ "q1=1.6*10**-19 #C\n",
+ "q2=9*10**9\n",
+ "r=2*1.5*10**-15\n",
+ "r1=1.38*10**-23\n",
+ "\n",
+ "#Calculation\n",
+ "Q=(M1+M2-M3-M4)*S\n",
+ "Q2=q2*(q1**2/r)\n",
+ "Q3=(2*Q2)/(3*r1)\n",
+ "\n",
+ "#Result\n",
+ "print\"(a) The amount of energy is\",round(Q,2),\"MeV\"\n",
+ "print\"(b) The kinetic energy is\",Q2,\"J\"\n",
+ "print\"The temperature is\",round(Q3*10**-9,2),\"*10**9 K\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a) The amount of energy is 17.59 MeV\n",
+ "(b) The kinetic energy is 7.68e-14 J\n",
+ "The temperature is 3.71 *10**9 K\n"
+ ]
+ }
+ ],
+ "prompt_number": 55
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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