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Diffstat (limited to 'modern_physics_by_Satish_K._Gupta/chap23.ipynb')
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diff --git a/modern_physics_by_Satish_K._Gupta/chap23.ipynb b/modern_physics_by_Satish_K._Gupta/chap23.ipynb new file mode 100644 index 00000000..3565eff3 --- /dev/null +++ b/modern_physics_by_Satish_K._Gupta/chap23.ipynb @@ -0,0 +1,641 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:fd3a71d11d7e73e323877019a1c5f0e92d8e8b30b7f927fde2bcadd4742b58c1"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 23 Optical instruments"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 23.1 Page no 704"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "f=5.0 #cm\n",
+ "D=25\n",
+ "\n",
+ "#Calculation\n",
+ "M=1+(D/f)\n",
+ "\n",
+ "#Result\n",
+ "print\"Magnifying power is\",M"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Magnifying power is 6.0\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 23.2 Page no 704"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "f=6.25 #cm\n",
+ "v=-25\n",
+ "\n",
+ "#Calculation\n",
+ "u=v*f/(v-f)\n",
+ "M=1+(D/f)\n",
+ "M1=D/f\n",
+ "\n",
+ "#Result\n",
+ "print\"(i) The distance of the object from the lens is\", M\n",
+ "print\"(ii) Anguar magnification is\",M1"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(i) The distance of the object from the lens is 5.0\n",
+ "(ii) Anguar magnification is 4.0\n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 23.3 Page no 704"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "u=-9\n",
+ "f=10 #cm\n",
+ "v1=-25.0\n",
+ "\n",
+ "#Calculation\n",
+ "v=u*f/(u+f)\n",
+ "M=v/u\n",
+ "u=-v1*f/(v1-f)\n",
+ "M1=1-(v1/f)\n",
+ "\n",
+ "#Result\n",
+ "print\"(i) Magnification is\", M,\"\\n Size of each square in the image will appear as 100 mm**2\"\n",
+ "print\"(ii) Magnification is\",M1"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(i) Magnification is 10 \n",
+ " Size of each square in the image will appear as 100 mm**2\n",
+ "(ii) Magnification is 3.5\n"
+ ]
+ }
+ ],
+ "prompt_number": 15
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 23.4 Page no 704"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "v=-25\n",
+ "f=10.0\n",
+ "\n",
+ "#Calculation\n",
+ "u=-v*f/(f-v)\n",
+ "m=-v/u\n",
+ "M=1-(v/f)\n",
+ "\n",
+ "#Result\n",
+ "print\"(a) Distance is\", round(u,2),\"cm\"\n",
+ "print\"(b) Magnification is\",m\n",
+ "print\"(c) Magnification is\",M"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a) Distance is 7.14 cm\n",
+ "(b) Magnification is 3.5\n",
+ "(c) Magnification is 3.5\n"
+ ]
+ }
+ ],
+ "prompt_number": 28
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 23.5 Page no 705"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "M=-30\n",
+ "fe=5 #cm\n",
+ "D=25 #cm\n",
+ "\n",
+ "#Calculation\n",
+ "m0=M/(1+(D/fe))\n",
+ "\n",
+ "#Result\n",
+ "print\"Magnification produced is\",m0"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Magnification produced is -5\n"
+ ]
+ }
+ ],
+ "prompt_number": 29
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 23.6 Page no 705"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "f0=4\n",
+ "u0=-6\n",
+ "D=25\n",
+ "fe=6.0\n",
+ "\n",
+ "#Calculation\n",
+ "v0=f0*u0/(f0+u0)\n",
+ "M=v0/u0*(1+(D/fe))\n",
+ "\n",
+ "#Result\n",
+ "print\"Magnification produceed by the microscope is\", round(M,2)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Magnification produceed by the microscope is -10.33\n"
+ ]
+ }
+ ],
+ "prompt_number": 34
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 23.7 Page no 705"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "L=20\n",
+ "fe=5\n",
+ "f0=1.0 \n",
+ "\n",
+ "#Calculation\n",
+ "v01=L-fe\n",
+ "u0=v01*f0/(f0-v01)\n",
+ "M=v01*D/(u0*fe)\n",
+ "\n",
+ "#Result\n",
+ "print\"Magnification power is\", M,\"\\nThe -ve sigh shows that the image formed is inverted and real\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Magnification power is -70.0 \n",
+ "The -ve sigh shows that the image formed is inverted and real\n"
+ ]
+ }
+ ],
+ "prompt_number": 41
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 23.8 Page no 705"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "f=36 #cm\n",
+ "M=-8\n",
+ "\n",
+ "#Calculation\n",
+ "fe=-f/(M-1)\n",
+ "f0=-M*fe\n",
+ "\n",
+ "#Result\n",
+ "print\"Focal length of the lenses is\", fe,\"cm and\",f0,\"cm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Focal length of the lenses is 4 cm and 32 cm\n"
+ ]
+ }
+ ],
+ "prompt_number": 46
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 23.9 Page no 705"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "f=75 #cm\n",
+ "fe=5.0\n",
+ "D=25 \n",
+ "\n",
+ "#Calculation\n",
+ "M=-f/fe*(1+(fe/D))\n",
+ "\n",
+ "#Result\n",
+ "print\"Magnying power is\",M"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Magnying power is -18.0\n"
+ ]
+ }
+ ],
+ "prompt_number": 49
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 23.10 Page no 705"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "f0=140\n",
+ "fe=5\n",
+ "D=25.0\n",
+ "\n",
+ "#Calculation\n",
+ "M=-f0/fe\n",
+ "M1=-(f0/fe)*(1+(fe/D))\n",
+ "\n",
+ "#Result\n",
+ "print\"(a) Magnefying power, when telescope is in normal adjustment is\", M\n",
+ "print\"(b) Magnifying power, when image is formed at least distance of distinct vision is is\",M1"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a) Magnefying power, when telescope is in normal adjustment is -28\n",
+ "(b) Magnifying power, when image is formed at least distance of distinct vision is is -33.6\n"
+ ]
+ }
+ ],
+ "prompt_number": 54
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 23.11 Page no 706"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "f0=1 #m\n",
+ "fe=0.05\n",
+ "I=0.92*10**-2\n",
+ "u0=38*10**-7\n",
+ "fe1=5.0 #cm\n",
+ "ve=-25\n",
+ "\n",
+ "#Calculation\n",
+ "d=I*u0/f0\n",
+ "L=f0+fe\n",
+ "ue=ve*fe1/(fe1-ve)\n",
+ "L1=(f0*10**2)-ue\n",
+ "\n",
+ "#Result\n",
+ "print\"(i) Distance between two lenses is\", L*10**2,\"cm\"\n",
+ "print\"(ii) Distance when final image at 25 cm from the eye is\",round(L1,2),\"cm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(i) Distance between two lenses is 105.0 cm\n",
+ "(ii) Distance when final image at 25 cm from the eye is 104.17 cm\n"
+ ]
+ }
+ ],
+ "prompt_number": 71
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 23.12 Page no 706"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "M=-20\n",
+ "R=120\n",
+ "\n",
+ "#Calculation\n",
+ "f0=R/2.0\n",
+ "fe=-f0/M\n",
+ "\n",
+ "#Result\n",
+ "print\"Focal length of the eye piece is\",fe,\"cm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Focal length of the eye piece is 3.0 cm\n"
+ ]
+ }
+ ],
+ "prompt_number": 74
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 23.13 Page no 706"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "d=0.8 #cm\n",
+ "D=508\n",
+ "\n",
+ "#Calculation\n",
+ "B=D**2/d**2\n",
+ "\n",
+ "#Result\n",
+ "print\"The telescope can see a star \",B,\"time sfarther than the faintest star that can be seen with naked eye.\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The telescope can see a star 403225.0 time sfarther than the faintest star that can be seen with naked eye.\n"
+ ]
+ }
+ ],
+ "prompt_number": 76
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 23.14 Page no 706"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "ve=-25 #cm\n",
+ "fe=6.25\n",
+ "a=15\n",
+ "f0=2\n",
+ "\n",
+ "#Calculation\n",
+ "ue=-ve*fe/(ve-fe)\n",
+ "v0=a+ue\n",
+ "u0=f0*v0/(f0-v0)\n",
+ "v01=a-fe\n",
+ "u01=v01*f0/(f0-v01)\n",
+ "\n",
+ "#Result\n",
+ "print\"(a) Distance when final image at least distance of distinct vision is\", u0,\"cm\"\n",
+ "print\"(b) Distance when final image is at infinity is\",round(u01,2),\"cm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a) Distance when final image at least distance of distinct vision is -2.5 cm\n",
+ "(b) Distance when final image is at infinity is -2.59 cm\n"
+ ]
+ }
+ ],
+ "prompt_number": 87
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 23.15 Page no 707"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "a=10\n",
+ "D=24\n",
+ "fe=20.0\n",
+ "\n",
+ "#Calculation\n",
+ "import math\n",
+ "A=a/(1+(D/fe))/100.0\n",
+ "\n",
+ "#Result\n",
+ "print\"Angle is\", round(A,4),\"radian\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Angle is 0.0455 radian\n"
+ ]
+ }
+ ],
+ "prompt_number": 95
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 23.16 Page no 707"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "f0=-0.5 #m\n",
+ "fe=0.01\n",
+ "d=3.48*10**6\n",
+ "r=3.8*10**8\n",
+ "a1=15\n",
+ "\n",
+ "#Calculation\n",
+ "M=f0/fe\n",
+ "a=d/r\n",
+ "I=a*a1\n",
+ "\n",
+ "#Result\n",
+ "print\"(a) Angular Magnification of the telescope is\",M\n",
+ "print\"(b) Diameter of the image is\", round(I,3),\"m\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a) Angular Magnification of the telescope is -50.0\n",
+ "(b) Diameter of the image is 0.137 m\n"
+ ]
+ }
+ ],
+ "prompt_number": 103
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
\ No newline at end of file |