diff options
Diffstat (limited to 'modern_physics_by_Satish_K._Gupta/chap18.ipynb')
| -rwxr-xr-x | modern_physics_by_Satish_K._Gupta/chap18.ipynb | 1298 |
1 files changed, 0 insertions, 1298 deletions
diff --git a/modern_physics_by_Satish_K._Gupta/chap18.ipynb b/modern_physics_by_Satish_K._Gupta/chap18.ipynb deleted file mode 100755 index 94dff4f2..00000000 --- a/modern_physics_by_Satish_K._Gupta/chap18.ipynb +++ /dev/null @@ -1,1298 +0,0 @@ -{
- "metadata": {
- "name": "",
- "signature": "sha256:14dd6f2dca7ff6e4458a0a97e28043f8703a45199dee1a45b482cebdf3ee0a74"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 18 Alternating current"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.2 Page no 555"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "f1=100\n",
- "f2=2.0\n",
- "I0=50\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "f=f1/f2\n",
- "Im=0.636*I0\n",
- "Iv=0.707*I0\n",
- "I=I0*math.sin(60*3.14/180.0)\n",
- "\n",
- "#Result\n",
- "print\"(i) Frequency of A.C applied is\",f,\"c.p.s\"\n",
- "print\"(ii) Mean value of current is\",Im,\"A\"\n",
- "print\"(iii) Virtual value of current is\",Iv,\"A\"\n",
- "print\"(iv) Value of current is\",round(I,1),\"A\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(i) Frequency of A.C applied is 50.0 c.p.s\n",
- "(ii) Mean value of current is 31.8 A\n",
- "(iii) Virtual value of current is 35.35 A\n",
- "(iv) Value of current is 43.3 A\n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Example 18.3 Page no 555"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "R=10.0 #ohm\n",
- "E0=200\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "Ev=E0/math.sqrt(2)\n",
- "Iv=Ev/R\n",
- "Pav=Ev*Iv\n",
- "\n",
- "#Result\n",
- "print\"(i) r.m.s value of voltage is\", E0,\"V\"\n",
- "print\"(ii) r.m.s value of current is\",round(Iv,2),\"A\"\n",
- "print\"(iii)Power dissipated is\",Pav,\"W\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(i) r.m.s value of voltage is 200 V\n",
- "(ii) r.m.s value of current is 14.14 A\n",
- "(iii)Power dissipated is 2000.0 W\n"
- ]
- }
- ],
- "prompt_number": 18
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.4 Page no 555"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "L=1 #H\n",
- "Ev=110 #V\n",
- "f=70 #Hz\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "Xl=2*3.14*f*L\n",
- "I=Ev/Xl\n",
- "I0=math.sqrt(2)*I\n",
- "\n",
- "#Result\n",
- "print\"(a) Reactance is\", round(Xl,0)\n",
- "print\"(b) Current through inductance is\",round(I,2),\"A\"\n",
- "print\"(c) Peak value of current is\",round(I0,3),\"A\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) Reactance is 440.0\n",
- "(b) Current through inductance is 0.25 A\n",
- "(c) Peak value of current is 0.354 A\n"
- ]
- }
- ],
- "prompt_number": 28
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.5 Page no 555"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "L=2*10**-3\n",
- "w=200 #rad/s\n",
- "I0=0.2\n",
- "\n",
- "#Calculation\n",
- "Xl=w*L\n",
- "e=L*I0*w\n",
- "I0=e/Xl\n",
- "\n",
- "#Result\n",
- "print\"Maximum value of induced current is\", I0,\"A\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Maximum value of induced current is 0.2 A\n"
- ]
- }
- ],
- "prompt_number": 35
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.6 Page no 555"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "C=10*10**-6 #F\n",
- "f=50 #cycles/s\n",
- "Ev=110\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "Xc=1/(math.pi*2*f*C)\n",
- "Iv=Ev/Xc\n",
- "\n",
- "#Result\n",
- "print\"Virtual value of current is\", round(Iv,3),\"A\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Virtual value of current is 0.346 A\n"
- ]
- }
- ],
- "prompt_number": 40
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.7 Page no 555"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "L=4\n",
- "R=30 #ohm\n",
- "Ev=200\n",
- "f=50\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "Xl=2*math.pi*f*(L/math.pi)\n",
- "Z=math.sqrt(R**2+Xl**2)\n",
- "Iv=Ev/Z\n",
- "\n",
- "#Result\n",
- "print\"current flowing in the circuit is\", round(Iv,3),\"A\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "current flowing in the circuit is 0.499 A\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.8 Page no 556"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "E=100\n",
- "I=1.0\n",
- "Iv=0.5\n",
- "f=50\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "R=E/I\n",
- "Z=E/Iv\n",
- "Xl=math.sqrt(Z**2-R**2)\n",
- "L=Xl/(2*math.pi*f)\n",
- "\n",
- "#Result\n",
- "print\"Inductance of the coil is\", round(L,2),\"H\"\n",
- "print\"Resistance is\",R,\"ohm\"\n",
- "print\"Impedence is\",Z,\"ohm\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Inductance of the coil is 0.55 H\n",
- "Resistance is 100.0 ohm\n",
- "Impedence is 200.0 ohm\n"
- ]
- }
- ],
- "prompt_number": 18
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.9 Page no 556"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "L=0.50 #H\n",
- "R=100.0 #ohm\n",
- "f=50 #Hz\n",
- "Ev=240\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "Iv=Ev/(math.sqrt(R**2+(2*math.pi*f*L)**2))\n",
- "I0=math.sqrt(2)*Iv\n",
- "a=2*math.pi*f*L/R\n",
- "a1=math.atan(a)*180/3.14\n",
- "\n",
- "#Result\n",
- "print\"(a) Maximum current in the coil is\", round(I0,3),\"A\"\n",
- "print\"(b) Phase difference is\",round(a1,1),\"degree (e.m.f. leads current)\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) Maximum current in the coil is 1.823 A\n",
- "(b) Phase difference is 57.5 degree (e.m.f. leads current)\n"
- ]
- }
- ],
- "prompt_number": 29
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.10 Page no 556"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "Ev=220\n",
- "Iv=0.5\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "R=Ev/Iv\n",
- "Xl=Ev/Iv\n",
- "Z=math.sqrt(R**2+Xl**2)\n",
- "Iv1=Ev/Z\n",
- "\n",
- "#Result\n",
- "print\"(a) X is a resistor of\",R,\"ohm\\n and Y is a inductor of\",Xl,\"ohm\"\n",
- "print\"(b) Current in the circuit is\",round(Iv1,3),\"A\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) X is a resistor of 440.0 ohm\n",
- " and Y is a inductor of 440.0 ohm\n",
- "(b) Current in the circuit is 0.354 A\n"
- ]
- }
- ],
- "prompt_number": 37
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.11 Page no 556"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "Z=100 #ohm\n",
- "a=45 #degree\n",
- "f=1000\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "Xl=Z/math.sqrt(2)\n",
- "L=Xl/(2*math.pi*f)\n",
- "\n",
- "#Result\n",
- "print\"Self inductance of the coil is\", round(L*10**2,4),\"*10**-2 H\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Self inductance of the coil is 1.1254 *10**-2 H\n"
- ]
- }
- ],
- "prompt_number": 43
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.12 Page no 556"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "R=10 #ohm\n",
- "Ev=220\n",
- "f=50 #Hz\n",
- "Iv=2.0 #A\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "Z=Ev/Iv\n",
- "Xc=math.sqrt(Z**2-R**2)\n",
- "\n",
- "#Result\n",
- "print\"Reactance of the capacitor is\",round(Xc,2),\"ohm\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Reactance of the capacitor is 109.54 ohm\n"
- ]
- }
- ],
- "prompt_number": 46
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.13 Page no 556"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "R=10\n",
- "C=0.1*10**-6 #F\n",
- "Ev=100 #V\n",
- "f=50\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "Z=math.sqrt(R**2+(1/(2*math.pi*f*C))**2)\n",
- "Iv=Ev/Z\n",
- "\n",
- "#Result\n",
- "print\"Current in the circuit is\", round(Iv*10**3,3),\"*10**-3 A\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current in the circuit is 3.142 *10**-3 A\n"
- ]
- }
- ],
- "prompt_number": 51
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.14 Page no 557"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "C=100*10**-6\n",
- "R=40\n",
- "Ev=110\n",
- "f=60\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "Iv=Ev/(math.sqrt(R**2+(1/(2*math.pi*f*C)**2)))\n",
- "Iv1=math.sqrt(2)*Iv\n",
- "a=1/(2*math.pi*f*C*R)\n",
- "a1=math.atan(a)*180/3.14\n",
- "\n",
- "#Result\n",
- "print\"(a) Maximum current in the circuit is\", round(Iv1,2),\"A\"\n",
- "print\"(b) Phase lag between the current maximum and voltage maximum is\",round(a1,2),\"degree (e.m.f. lags behind the current)\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) Maximum current in the circuit is 3.24 A\n",
- "(b) Phase lag between the current maximum and voltage maximum is 33.57 degree (e.m.f. lags behind the current)\n"
- ]
- }
- ],
- "prompt_number": 62
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.15 page no 557"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "C=100*10**-6\n",
- "R=50 #ohm\n",
- "L=0.5 #H\n",
- "Ev=110\n",
- "f=50\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "Z=math.sqrt(R**2+(2*math.pi*f*L-1/(2*math.pi*f*C))**2)\n",
- "I0=Ev/Z\n",
- "\n",
- "#Result\n",
- "print\"r.m.s value of current is\", round(I0,3),\"A\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "r.m.s value of current is 0.816 A\n"
- ]
- }
- ],
- "prompt_number": 68
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.16 Page no 557"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "L=0.1 #H\n",
- "C=25*10**-6\n",
- "R=25.0\n",
- "e=314\n",
- "E0=310\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "f=e/(2*math.pi)\n",
- "Xl=2*math.pi*f*L\n",
- "Xc=1/(2*math.pi*f*C)\n",
- "A=Xc-Xl\n",
- "Z=math.sqrt(R**2+(Xc-Xl)**2)\n",
- "Ev=E0/math.sqrt(2)\n",
- "Iv=Ev/Z\n",
- "a1=(Xc-Xl)/R\n",
- "a2=math.atan(a1)*180/3.14\n",
- "a3=a2*math.pi/180.0\n",
- "V=Iv*Xc\n",
- "V1=Iv*Xl\n",
- "V2=Iv*R\n",
- "L=1/(((2*math.pi*f)**2)*C)\n",
- "\n",
- "#Result\n",
- "print\"(a) The frequency of the e.m.f is\",round(f,0),\"cycle s**-1\" \n",
- "print\"(b) The reactance of the circuit is\",round(A,0),\"ohm\"\n",
- "print\"(c) The impedance of the circuit is\",round(Z,1),\"ohm\"\n",
- "print\"(d) The current in the circuit is\",round(Iv,2),\"A\"\n",
- "print\"(e) The phase angle of the current is\",round(a3,3),\"rad\"\n",
- "print\"(f) The expression for the instantaneous value of the current is 3.125 cos(314t-1.316)\"\n",
- "print\"(g) Effective voltage across the capacitor is\",round(V,1),\"V\"\n",
- "print\" Effective Voltage across the inductor is\",round(V1,1),\"V\"\n",
- "print\"Effective voltage across the resistor is\",round(V2,2),\"V\"\n",
- "print\"(h) Value of inductance is\",round(L,3),\"H\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) The frequency of the e.m.f is 50.0 cycle s**-1\n",
- "(b) The reactance of the circuit is 96.0 ohm\n",
- "(c) The impedance of the circuit is 99.2 ohm\n",
- "(d) The current in the circuit is 2.21 A\n",
- "(e) The phase angle of the current is 1.317 rad\n",
- "(f) The expression for the instantaneous value of the current is 3.125 cos(314t-1.316)\n",
- "(g) Effective voltage across the capacitor is 281.5 V\n",
- " Effective Voltage across the inductor is 69.4 V\n",
- "Effective voltage across the resistor is 55.25 V\n",
- "(h) Value of inductance is 0.406 H\n"
- ]
- }
- ],
- "prompt_number": 113
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.17 Page no 558"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "f=50 #Hz\n",
- "L=101.5*10**-3\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "C=1/((2*math.pi*f)**2*L)\n",
- "\n",
- "#Result\n",
- "print\"Capacitance of the capacitor is\",round(C*10**6,0),\"micro F\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Capacitance of the capacitor is 100.0 micro F\n"
- ]
- }
- ],
- "prompt_number": 117
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.18 Page no 558"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "Ev=230 #V\n",
- "L=5 #H\n",
- "C=80*10**-6\n",
- "R=40.0\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "f=1/(math.pi*2*math.sqrt(L*C))\n",
- "E0=math.sqrt(2)*Ev\n",
- "A=E0/R\n",
- "\n",
- "#Result\n",
- "print\"(i) Angular frequency is\", round(f,2),\"Hz\"\n",
- "print\"(ii) Impedence of circuit is\",R,\"ohm\"\n",
- "print\"(iii) Amplitude of the current is\",round(A,2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(i) Angular frequency is 7.96 Hz\n",
- "(ii) Impedence of circuit is 40.0 ohm\n",
- "(iii) Amplitude of the current is 8.13\n"
- ]
- }
- ],
- "prompt_number": 126
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.19 Page no 558"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "C=2*10**-6 #F\n",
- "R=100 #ohm\n",
- "L=8 #H\n",
- "E=200 #V\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "F=1/((2*math.pi*math.sqrt(L*C)))\n",
- "D=2*math.pi*F*L\n",
- "L1=E/R\n",
- "\n",
- "#Result\n",
- "print\"The resonant frequency is\",round(F,2),\"Hz\"\n",
- "print\"(i) The inductive and capacitive reactances of the circuit is\",D,\"ohm\"\n",
- "print\"(ii) Total impedance of the circuit is 100\",\"ohm\"\n",
- "print\"(iii) Peak value of current is\",L1,\"A\"\n",
- "print\"(iv) The voltages across inductor and resistor differ in phase by\",\"90\"\n",
- "print\"(v) The voltages across inductor and capacitor differ in phase by\",\"180\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The resonant frequency is 39.79 Hz\n",
- "(i) The inductive and capacitive reactances of the circuit is 2000.0 ohm\n",
- "(ii) Total impedance of the circuit is 100 ohm\n",
- "(iii) Peak value of current is 2 A\n",
- "(iv) The voltages across inductor and resistor differ in phase by 90\n",
- "(v) The voltages across inductor and capacitor differ in phase by 180\n"
- ]
- }
- ],
- "prompt_number": 144
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.20 Page no 558"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "Ev=220 #V\n",
- "f=50 #Hz\n",
- "R=100.0 #ohm\n",
- "Vr=65 #V\n",
- "Vc=415 #V\n",
- "Vl=204 #V\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "Iv=Vr/R\n",
- "Xl=Vl/Iv\n",
- "L=Xl/(2*math.pi*f)\n",
- "Xc=Vc/Iv\n",
- "C=1/(2*math.pi*f*Xc)\n",
- "C1=1/(4*math.pi**2*f**2*L)\n",
- "\n",
- "#Result\n",
- "print\"(i) The current in the circuit is\",Iv,\"A\"\n",
- "print\"(ii) The value of the inductor is\",round(L,0),\"H\"\n",
- "print\"(iii) The value of the capacitor C is\",round(C*10**6,1),\"micro F\"\n",
- "print\"(iv) The value of C required to produce resonance is\",round(C1*10**6,1),\"micro F\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(i) The current in the circuit is 0.65 A\n",
- "(ii) The value of the inductor is 1.0 H\n",
- "(iii) The value of the capacitor C is 5.0 micro F\n",
- "(iv) The value of C required to produce resonance is 10.1 micro F\n"
- ]
- }
- ],
- "prompt_number": 189
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.21 Page no 559"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "L=3 #H\n",
- "C=27*10**-6\n",
- "R=7.4 #ohm\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "w0=1/(math.sqrt(L*C))\n",
- "Q=1/R*(math.sqrt(L/C))\n",
- "\n",
- "#Result\n",
- "print\"Resonant frequency is\", round(w0,1),\"rad/s\"\n",
- "print\"Q factor is\",round(Q,2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Resonant frequency is 111.1 rad/s\n",
- "Q factor is 45.05\n"
- ]
- }
- ],
- "prompt_number": 196
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.22 Page no 559"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "R=30 #ohm\n",
- "Xl=40\n",
- "E0=220\n",
- "I0=1 \n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "Z=math.sqrt(R**2+Xl**2)\n",
- "a=R/Z\n",
- "Pav=E0*I0*a/(math.sqrt(2)*math.sqrt(2))\n",
- "\n",
- "#Result\n",
- "print\"Power consumed in the circuit is\", Pav,\"Watt\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Power consumed in the circuit is 66.0 Watt\n"
- ]
- }
- ],
- "prompt_number": 201
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.23 Page no 559"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "Ev=100\n",
- "f=50 #Hz\n",
- "C=10*10**-6\n",
- "R=100\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "Xc=1/(2*math.pi*f*C)\n",
- "Iv=Ev/Xc\n",
- "Pav=Ev*Iv*Ev/(math.sqrt(Ev**2+Xc**2))\n",
- "\n",
- "#Result\n",
- "print\"(a) The reactance of the capacitor is\",round(Xc,2),\"ohm\"\n",
- "print\"(b) Current flowing is\",round(Iv,3),\"A\"\n",
- "print\"(c) Average power supplied is\",round(Pav,2),\"W\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) The reactance of the capacitor is 318.31 ohm\n",
- "(b) Current flowing is 0.314 A\n",
- "(c) Average power supplied is 9.42 W\n"
- ]
- }
- ],
- "prompt_number": 214
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.24 Page no 559"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "V=60.0\n",
- "P=10\n",
- "Ev=100\n",
- "f=60 #Hz\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "I=P/V\n",
- "R=f/I\n",
- "Z=Ev/I\n",
- "L=math.sqrt(Z**2-R**2)/(2*math.pi*f)\n",
- "R1=Z-R\n",
- "\n",
- "#Result\n",
- "print\"(i) The inductance is\", round(L,3),\"henry\"\n",
- "print\"(ii) Value of resistance is\",R1,\"ohm\"\n",
- "print\"(iii) If resistance is used in the place of inductance, the electrical energy is wasted.\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(i) The inductance is 1.273 henry\n",
- "(ii) Value of resistance is 240.0 ohm\n",
- "(iii) If resistance is used in the place of inductance, the electrical energy is wasted.\n"
- ]
- }
- ],
- "prompt_number": 224
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.25 Page no 559"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "V=50.0 #V\n",
- "P=20 #watt\n",
- "Ev=250 #V\n",
- "f=50\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "I=P/V\n",
- "R=V/I\n",
- "Z=Ev/I\n",
- "C=1/(2*math.pi*f*Ev*math.sqrt(6))\n",
- "\n",
- "#Result\n",
- "print\"Value of capacitance required is\", round(C*10**6,3)*10**-6,\"F\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Value of capacitance required is 5.198e-06 F\n"
- ]
- }
- ],
- "prompt_number": 233
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.26 Page no 560"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "Ev=200\n",
- "f=50 #H\n",
- "R=50\n",
- "L=0.3\n",
- "C=40*10**-6\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "Xl=2*math.pi*f*L\n",
- "Xc=1/(2*math.pi*f*C)\n",
- "Z=math.sqrt(R**2+(Xl-Xc)**2)\n",
- "Iv=Ev/Z\n",
- "a=R/Z\n",
- "Pav=Ev*Iv*a\n",
- "\n",
- "#Result\n",
- "print\"Impedence in the circuit is\", round(Z,2),\"ohm\"\n",
- "print\"Power in the circuit is\",round(Pav,1),\"watt\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Impedence in the circuit is 52.11 ohm\n",
- "Power in the circuit is 736.6 watt\n"
- ]
- }
- ],
- "prompt_number": 244
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.27 Page no 560"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "Ev=200 #v\n",
- "L=5 #H\n",
- "C=80\n",
- "R=40.0\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "W=10**3/(math.sqrt(L*C))\n",
- "Iv=Ev/R\n",
- "I0=math.sqrt(2)*Iv\n",
- "Pav=Ev*L*math.cos(0*3.14/180.0)\n",
- "\n",
- "print\"(a) Angular frequency is\",W,\"rad s**-1\"\n",
- "print\"(b) The current amplitude is\",round(I0,2),\"A\" \n",
- "print\"(c) The power dissipation in the circuit is\",Pav,\"Watt\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) Angular frequency is 50.0 rad s**-1\n",
- "(b) The current amplitude is 7.07 A\n",
- "(c) The power dissipation in the circuit is 1000.0 Watt\n"
- ]
- }
- ],
- "prompt_number": 272
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.28 Page no 560"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "L=5.0 #H\n",
- "C=80*10**-6 #F\n",
- "R=40.0 #ohm\n",
- "Ev=230 #V\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "D=1/math.sqrt(L*C)\n",
- "Iv=Ev/R\n",
- "I0=math.sqrt(2)*Iv\n",
- "S=Iv*R\n",
- "S1=Iv*D*L\n",
- "S2=Iv/(1/D*C)\n",
- "S3=Iv/(D*L-1/D*C)\n",
- "\n",
- "#Result\n",
- "print\"(a) The resonant angular frequency is\",D,\"rad s**-1\"\n",
- "print\"(b) The impedance of the circuit and the amplitude of curremt is\",round(I0,2),\"A\"\n",
- "print\"(c) The R.M.S. potential drop across LC is\",round(S3,0)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) The resonant angular frequency is 50.0 rad s**-1\n",
- "(b) The impedance of the circuit and the amplitude of curremt is 8.13 A\n",
- "(c) The R.M.S. potential drop across LC is 0.0\n"
- ]
- }
- ],
- "prompt_number": 282
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.29 Page no 560"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "L=0.12 #H\n",
- "C=480*10**-9 #F\n",
- "R=23 #ohm\n",
- "Ev=230 #V\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "D=1/(math.sqrt(L*C))\n",
- "Iv=Ev/(math.sqrt(R**2+(D*L-1/D*C))**2)\n",
- "I0=(math.sqrt(2)*Ev)/(math.sqrt(R**2+(D*L-1/D*C))**2)\n",
- "I1=(math.sqrt(2)*Ev)/R\n",
- "EvIv=Ev*(I1/math.sqrt(2))\n",
- "\n",
- "#Result\n",
- "print\"(a) The source frequency is\",round(D,1),\"rad s**-1\"\n",
- "print\" The maximum value is\",round(I1,2),\"A\"\n",
- "print\"(b) Average power will also be maximum at resonant frequency is\",round(D,1),\"rad s**-1\" \n",
- "print\" The value of this maximum power is\",EvIv,\"Watt\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) The source frequency is 4166.7 rad s**-1\n",
- " The maximum value is 14.14 A\n",
- "(b) Average power will also be maximum at resonant frequency is 4166.7 rad s**-1\n",
- " The value of this maximum power is 2300.0 Watt\n"
- ]
- }
- ],
- "prompt_number": 298
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 18.30 Page no 561"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "L=80*10**-3 #H\n",
- "C=60*10**-6 #F\n",
- "Ev=230 #V\n",
- "f=50 #Hz\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "Iv=-Ev/((2*math.pi*f*L)-(1/(2*math.pi*f*C)))\n",
- "I0=math.sqrt(2)*Iv\n",
- "Iv1=Iv*2*math.pi*f*L\n",
- "Iv2=Iv*(1/(2*math.pi*f*C))\n",
- "Pav=math.cos(90*3.14/180.0)*Ev\n",
- "Pav1=math.cos(-90*3.14/180.0)*Ev\n",
- "\n",
- "#Result\n",
- "print\"(a) The current amplitude is\",round(Iv,2),\"A\",\"and r.m.s. value is\",round(I0,2),\"A\"\n",
- "print\"(b) The r.m.s. value of potential drops across L is\",round(Iv1,1),\"V\",\"and across C is\",round(Iv2,1),\"W\"\n",
- "print\"(c) The average power transferred to the inductor is\",round(Pav,0)\n",
- "print\"(d) The average power transferred to the capacitor is\",round(Pav1,0)\n",
- "print\"(e) Total average power absorbed is zero\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) The current amplitude is 8.24 A and r.m.s. value is 11.65 A\n",
- "(b) The r.m.s. value of potential drops across L is 207.0 V and across C is 437.0 W\n",
- "(c) The average power transferred to the inductor is 0.0\n",
- "(d) The average power transferred to the capacitor is 0.0\n",
- "(e) Total average power absorbed is zero\n"
- ]
- }
- ],
- "prompt_number": 357
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file |