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diff --git a/backup/Quantum_mechanics_by_M.C.Jain_version_backup/chapter8.ipynb b/backup/Quantum_mechanics_by_M.C.Jain_version_backup/chapter8.ipynb new file mode 100755 index 00000000..8c294517 --- /dev/null +++ b/backup/Quantum_mechanics_by_M.C.Jain_version_backup/chapter8.ipynb @@ -0,0 +1,269 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:52aec0ea98abde6e8f04f9a7bf644564cf443f3e3280ece147b509c27e4e9a1b"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 8 Scattering of psrticles by barriers and wells"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 8.2 page no 155 "
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "b=-32\n",
+ "a=32.0\n",
+ "c=1\n",
+ "\n",
+ "#Calculation\n",
+ "import math\n",
+ "r=(-b+(math.sqrt(b**2-(4*a*c))))/(2.0*a)\n",
+ "\n",
+ "#Result\n",
+ "print\"The ratio of E/V0 = \", round(r*10**0)\n",
+ "print \"-ve value is not possible. \""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The ratio of E/V0 = 1.0\n",
+ "-ve value is not possible. \n"
+ ]
+ }
+ ],
+ "prompt_number": 28
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 8.3 Page no 156"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "E=9 #ev\n",
+ "v0=5 #ev\n",
+ "\n",
+ "#Calculation\n",
+ "R=((math.sqrt(E)-(math.sqrt(E-v0)))/(math.sqrt(E)+(math.sqrt(E-v0))))**2\n",
+ "\n",
+ "#Result\n",
+ "print\"Reflection ratio is \", R"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Reflection ratio is 0.04\n"
+ ]
+ }
+ ],
+ "prompt_number": 53
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 8.4 Page no 156"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "E=9 #Kinetic energy of a particle in ev\n",
+ "v0=10 #ev\n",
+ "E1=5 #ev\n",
+ "E2=15\n",
+ "E3=10 #ev\n",
+ "\n",
+ "#calculation\n",
+ "import math\n",
+ "R=((math.sqrt(E2)-(math.sqrt(E2-v0)))/(math.sqrt(E2)+(math.sqrt(E2-v0))))**2\n",
+ "T=1-R\n",
+ "\n",
+ "#Result\n",
+ "print\"(a) E1 < vo, therefore R=1, T=0\"\n",
+ "print\"(b) reflection coefficient R= \",round(R,3),\"\\n transmission coefficient T= \",round(T,3)\n",
+ "print\"(c) E3=v0, therefore R=1 , T=0\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a) E1 < vo, therefore R=1, T=0\n",
+ "(b) reflection coefficient R= 0.072 \n",
+ " transmission coefficient T= 0.928\n",
+ "(c) E3=v0, therefore R=1 , T=0\n"
+ ]
+ }
+ ],
+ "prompt_number": 52
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 8.6 Page no 163"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "E=2 #ev\n",
+ "v0=3 #ev\n",
+ "m=9*10**-31\n",
+ "a=4*10**-10 #m\n",
+ "h=1.05*10**-34\n",
+ "b=(v0-E)*(1.6*10**-19)\n",
+ "\n",
+ "#Calculation\n",
+ "import math\n",
+ "Ka=((math.sqrt(2*m*(b)))*a)/h\n",
+ "x=math.sin(Ka*3.14/180.0)\n",
+ "T=(v0**2)/(4.0*E*(v0-E))\n",
+ "T1=1/(1+(T*x**2))\n",
+ "\n",
+ "#Result\n",
+ "print\"Transmission coefficient is \", round(T1,3)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Transmission coefficient is 0.999\n"
+ ]
+ }
+ ],
+ "prompt_number": 103
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 8.7 Page no 164"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "E=2 #ev\n",
+ "v0=3 #ev\n",
+ "m=9*10**-31\n",
+ "a=1*10**-10 #m\n",
+ "h=1.05*10**-34\n",
+ "b=(v0-E)*(1.6*10**-19)\n",
+ "\n",
+ "#Calculation\n",
+ "import math\n",
+ "Ka=((math.sqrt(2*m*(b)))*a)/h\n",
+ "x=math.sin(Ka*3.14/180.0)\n",
+ "T=(v0**2)/(4.0*E*(v0-E))\n",
+ "T1=1/(1.0+(T*x))\n",
+ "\n",
+ "#Result\n",
+ "print\"Transmission coefficient is \", round(T1,2)\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Transmission coefficient is 0.99\n"
+ ]
+ }
+ ],
+ "prompt_number": 94
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 8.8 Page no 164"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "E=10*10**6 #ev\n",
+ "T=2.0*10**-3\n",
+ "m=6.68*10**-27 #kg\n",
+ "h=1.054*10**-34 #Js\n",
+ "e=1.6*10**-19\n",
+ "v0=30.0*10**6 #ev\n",
+ "\n",
+ "#Calculation\n",
+ "import math\n",
+ "K=(math.sqrt(2*m*(v0-E)*e))/h\n",
+ "a=(1/(2.0*K))*(2.303*log10((16/T)*(E/v0)*(1-(E/v0))))\n",
+ "\n",
+ "#Result\n",
+ "print\"The width of the barrier is \", round(a,17),\"m\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The width of the barrier is 1.91e-15 m\n"
+ ]
+ }
+ ],
+ "prompt_number": 24
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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