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diff --git a/backup/Mechanical_Metallurgy_version_backup/Chapter_15.ipynb b/backup/Mechanical_Metallurgy_version_backup/Chapter_15.ipynb new file mode 100755 index 00000000..4b4e7632 --- /dev/null +++ b/backup/Mechanical_Metallurgy_version_backup/Chapter_15.ipynb @@ -0,0 +1,294 @@ +{
+ "cells": [
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "# Chapter 15: Fundamentals of Metalworking"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "### Example 15.1, Mechanics of Metal Working, Page No. 506"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 9,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "\n",
+ "Enginering Strain = 1\n",
+ "True Strain = 0.693147\n",
+ "Reduction = 1\n",
+ "\n",
+ "\n",
+ "Enginering Strain = -0.5\n",
+ "True Strain = -0.693147\n",
+ "Reduction = -1\n"
+ ]
+ }
+ ],
+ "source": [
+ "from math import log\n",
+ "\n",
+ "#For Bar which is double in length\n",
+ "#variable declaration 1\n",
+ "L2=2;\n",
+ "L1=1;\n",
+ "\n",
+ "#calculation 1\n",
+ "e=(L2-L1)/L1;\n",
+ "e1=log(L2/L1);\n",
+ "r=1-L1/L2;\n",
+ "\n",
+ "#result 1\n",
+ "print('\\nEnginering Strain = %g\\nTrue Strain = %g\\nReduction = %g')%(e,e1,r);\n",
+ "\n",
+ "\n",
+ "\n",
+ "#For bar which is halved in length\n",
+ "#variable declaration 2\n",
+ "L1=1;\n",
+ "L2=0.5;\n",
+ "\n",
+ "#calculation 2\n",
+ "e=(L2-L1)/L1;\n",
+ "e1=log(L2/L1);\n",
+ "r=1-L1/L2;\n",
+ "\n",
+ "#result 2\n",
+ "print('\\n\\nEnginering Strain = %g\\nTrue Strain = %g\\nReduction = %g')%(e,e1,r);\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {
+ "collapsed": true
+ },
+ "source": [
+ "### Example 15.2, Mechanics of Metal Working, Page No. 511"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 10,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "\n",
+ "Plastic work done in 1st step = 39752.1 lb/in^2\n",
+ "Plastic work done in 2nd step = 97934.8 lb/in^2\n",
+ "\n"
+ ]
+ }
+ ],
+ "source": [
+ "\n",
+ "from scipy.integrate import quad\n",
+ "from math import log\n",
+ "\n",
+ "#variable declaration\n",
+ "D0=25.0;\n",
+ "D1=20.0;\n",
+ "D2=15.0;\n",
+ "def integrand(e):\n",
+ " return 200000*e**0.5\n",
+ "\n",
+ "#calculation\n",
+ "ep1=log((D0/D1)**2);\n",
+ "U1,U1_err=quad(integrand,0,ep1);\n",
+ "ep2=log((D1/D2)**2);\n",
+ "U2,U2_err=quad(integrand,ep1,ep1+ep2);\n",
+ "\n",
+ "#result\n",
+ "print('\\nPlastic work done in 1st step = %g lb/in^2\\nPlastic work done in 2nd step = %g lb/in^2\\n')%(U1,U2);"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "### Example 15.3, Hodography, Page No. 517"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 11,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "Pressure = 2.88675\n"
+ ]
+ }
+ ],
+ "source": [
+ "\n",
+ "from math import sin\n",
+ "from math import radians\n",
+ "\n",
+ "#variable declaration\n",
+ "alpha=60;\n",
+ "\n",
+ "#calculation\n",
+ "r=radians(alpha);\n",
+ "mu=1/sin(r);\n",
+ "p_2k=mu*5/2;\n",
+ "\n",
+ "#result\n",
+ "print('Pressure = %g')%(p_2k);"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "### Example 15.4, Temperature in Metalworking, Page No. 526"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 12,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "\n",
+ "Temperature Rise for aluminium = 78.4808 C\n",
+ "Temperature Rise for titanium = 162.686 C\n",
+ "\n"
+ ]
+ }
+ ],
+ "source": [
+ "\n",
+ "\n",
+ "#variable declaration\n",
+ "Al_s=200;\n",
+ "Al_e=1;\n",
+ "Al_p=2.69;\n",
+ "Al_c=0.215;\n",
+ "Ti_s=400;\n",
+ "Ti_e=1;\n",
+ "Ti_p=4.5;\n",
+ "Ti_c=0.124;\n",
+ "J=4.186;\n",
+ "b=0.95;\n",
+ "\n",
+ "#calculation\n",
+ "Al_Td=Al_s*Al_e*b/(Al_p*Al_c*J);\n",
+ "Ti_Td=Ti_s*Ti_e*b/(Ti_p*Ti_c*J);\n",
+ "\n",
+ "#result\n",
+ "print('\\nTemperature Rise for aluminium = %g C\\nTemperature Rise for titanium = %g C\\n')%(Al_Td,Ti_Td);\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "### Example 15.5, Friction and Lubrication, Page No. 546"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 13,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "\n",
+ "For OD after deformation being 70 mm, Di = 22.3607 mm\n",
+ "Precent change in inside diameter = 25.4644 percent\n",
+ "Peak pressure = 1.93531\n",
+ "\n",
+ "\n",
+ "\n",
+ "\n",
+ "For OD after deformation being 81.4 mm, Di = 35.0137 mm\n",
+ "Precent change in inside diameter = -16.7124 percent\n",
+ "Peak pressure = 1.17321\n"
+ ]
+ }
+ ],
+ "source": [
+ "\n",
+ "\n",
+ "from math import sqrt\n",
+ "\n",
+ "#variable declaration\n",
+ "Do=60;\n",
+ "Di=30;\n",
+ "def1=70;\n",
+ "def2=81.4;\n",
+ "h=10;\n",
+ "a=30;\n",
+ "\n",
+ "#calculation1\n",
+ "di=sqrt((Do**2-Di**2)*2-def1**2);\n",
+ "pr=(Di-di)/Di*100;\n",
+ "m=0.27;\n",
+ "p_s=1+2*m*a/(sqrt(3)*h);\n",
+ "\n",
+ "#result 1\n",
+ "print('\\nFor OD after deformation being 70 mm, Di = %g mm\\nPrecent change in inside diameter = %g percent\\nPeak pressure = %g')%(di,pr,p_s);\n",
+ "\n",
+ "#calculation 2\n",
+ "di=sqrt(def2**2-(Do**2-Di**2)*2);\n",
+ "pr=(Di-di)/Di*100;\n",
+ "m=0.05;\n",
+ "p_s=1+2*m*a/(sqrt(3)*h);\n",
+ "\n",
+ "#result 2\n",
+ "print('\\n\\n\\n\\nFor OD after deformation being 81.4 mm, Di = %g mm\\nPrecent change in inside diameter = %g percent\\nPeak pressure = %g')%(di,pr,p_s);\n"
+ ]
+ }
+ ],
+ "metadata": {
+ "kernelspec": {
+ "display_name": "Python 2",
+ "language": "python",
+ "name": "python2"
+ },
+ "language_info": {
+ "codemirror_mode": {
+ "name": "ipython",
+ "version": 2
+ },
+ "file_extension": ".py",
+ "mimetype": "text/x-python",
+ "name": "python",
+ "nbconvert_exporter": "python",
+ "pygments_lexer": "ipython2",
+ "version": "2.7.9"
+ }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 0
+}
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