diff options
Diffstat (limited to 'backup/Machine_Design_by_U.C._Jindal_version_backup/Ch30.ipynb')
| -rwxr-xr-x | backup/Machine_Design_by_U.C._Jindal_version_backup/Ch30.ipynb | 210 |
1 files changed, 210 insertions, 0 deletions
diff --git a/backup/Machine_Design_by_U.C._Jindal_version_backup/Ch30.ipynb b/backup/Machine_Design_by_U.C._Jindal_version_backup/Ch30.ipynb new file mode 100755 index 00000000..335560f0 --- /dev/null +++ b/backup/Machine_Design_by_U.C._Jindal_version_backup/Ch30.ipynb @@ -0,0 +1,210 @@ +{ + "metadata": { + "name": "", + "signature": "sha256:55c40faafb847932f0fdcda855b3af16f1a2e4ef45941baaf0d7ee692a22c20c" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Ch:30 Chain drive" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "exa 30-1 - Page 778" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from __future__ import division\n", + "from math import sqrt, pi\n", + "n1=17#\n", + "n2=51#\n", + "C=300#\n", + "p=9.52#\n", + "Ln=(2*C/p)+((n1+n2)/2)+((((n2-n1)/(2*pi))**2)*(p/C))#\n", + "x=(Ln-((n2+n1)/(2)))**2#\n", + "y=8*(((n2-n1)/(2*pi))**2)#\n", + "z=Ln-((n1+n2)/2)#\n", + "C=(p/4)*(z+(sqrt(x-y)))\n", + "\n", + "\n", + " # printing data in scilab o/p window\n", + "print \"C is %0.2f mm \"%(C)#\n", + " " + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "C is 300.00 mm \n" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "exa 30-2 - Page 778" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from math import tan\n", + "G=4#\n", + "n1=17#\n", + "n2=n1*G#\n", + "N1=2300#\n", + "Kc=1.2# #from table 30-2\n", + "p=12.7# #fom table 30-1\n", + "D1=p*n1#\n", + "D2=p*n2#\n", + "phi=2*10.6#\n", + "x=tan(phi/2)# #phi/2 = 10.6deg, from table 30-3\n", + "Da1=(p/x)+(0.6*p)#\n", + "Da2=(p/x*4)+(0.6*p)#\n", + "Cmin=Kc*((Da1+Da2)/2)#\n", + "Ln1=(2*Cmin/p)+((n1+n2)/2)+((((n2-n1)/(2*pi))**2)*(p/Cmin))#\n", + "Ln1=80#\n", + "print \"Ln is %0.0f \"%(Ln1)#" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Ln is 80 \n" + ] + } + ], + "prompt_number": 2 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "exa 30-3 - Page 779" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "N1=1000#\n", + "N2=500#\n", + "P=2.03*10**3# #from table 30-8\n", + "K1=1.26#\n", + "Ks=1#\n", + "#let Pc be the power transmitting capacity of the chain\n", + "Pc=P*K1/Ks#\n", + "p=9.52#\n", + "n1=21#\n", + "n2=42#\n", + "V=n1*p*N1/(60*10**3)#\n", + "#Let the chain tension be T\n", + "T=Pc/V#\n", + "#Let the breaking load be BL\n", + "BL=10700#\n", + "FOS=BL/T#\n", + "C=50*p#\n", + "Ln=(2*C/p)+((n1+n2)/2)+((((n2-n1)/(2*pi))**2)*(p/C))#\n", + "L=Ln*p#\n", + "Pc=Pc*10**-3#\n", + "print \" Pc is %0.2f KW \"%(Pc)#\n", + "print \"\\n V is %0.3f m/s \"%(V)#\n", + "print \"\\n T is %0.1f N \"%(T)#\n", + "print \"\\n FOS is %0.2f \"%(FOS)#\n", + "print \"\\n L is %0.2f mm \"%(L)#\n", + "\n", + "#The difference in the value of L and T is due to rounding-off the values." + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + " Pc is 2.56 KW \n", + "\n", + " V is 3.332 m/s \n", + "\n", + " T is 767.6 N \n", + "\n", + " FOS is 13.94 \n", + "\n", + " L is 1254.01 mm \n" + ] + } + ], + "prompt_number": 3 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "exa 30-5 - Page 780" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "G=2#\n", + "P=5000#\n", + "Ks=1.7#\n", + "Pd=P*Ks#\n", + "K2=1.7#\n", + "p=15.88#\n", + "n1=17#\n", + "n2=n1*G#\n", + "D1=n1*p#\n", + "D2=n2*p#\n", + "C=40*p#\n", + "Ln=(2*C/p)+((n1+n2)/2)+((((n2-n1)/(2*pi))**2)*(p/C))#\n", + "L=Ln*p#\n", + "print \"L is %0.2f mm \"%(L)#\n", + "#The difference in the value of L is due to rounding-off the values." + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "L is 1678.25 mm \n" + ] + } + ], + "prompt_number": 4 + } + ], + "metadata": {} + } + ] +}
\ No newline at end of file |