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diff --git a/_Theory_Of_Machines/Chapter12.ipynb b/_Theory_Of_Machines/Chapter12.ipynb deleted file mode 100755 index 6706c05c..00000000 --- a/_Theory_Of_Machines/Chapter12.ipynb +++ /dev/null @@ -1,380 +0,0 @@ -{
- "metadata": {
- "name": "",
- "signature": "sha256:2fbbfd8e1fae5de695230b7f28341e3abac22cade207682955694bcaba6d0716"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter12-Balancing of reciprocating of masses"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex1-pg310"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "##CHAPTER 12 ILLUSRTATION 1 PAGE NO 310\n",
- "##TITLE:Balancing of reciprocating of masses\n",
- "import math\n",
- "#calculate the magnitude of balance mass required and residual balance error\n",
- "pi=3.141\n",
- "N=250.## speed of the reciprocating engine in rpm\n",
- "s=18.## length of stroke in mm\n",
- "mR=120.## mass of reciprocating parts in kg\n",
- "m=70.## mass of revolving parts in kg\n",
- "r=.09## radius of revolution of revolving parts in m\n",
- "b=.15## distance at which balancing mass located in m\n",
- "c=2./3.## portion of reciprocating mass balanced \n",
- "teeta=30.## crank angle from inner dead centre in degrees\n",
- "##===============================\n",
- "B=r*(m+c*mR)/b## balance mass required in kg\n",
- "w=2.*math.pi*N/60.## angular speed in rad/s\n",
- "F=mR*w**2.*r*(((1.-c)**2.*(math.cos(teeta/57.3))**2.)+(c**2.*(math.sin(teeta/57.3))**2.))**.5## residual unbalanced forces in N\n",
- "print'%s %.1f %s %.3f %s'%('Magnitude of balance mass required= ',B,'kg' and 'Residual unbalanced forces= ',F,' N')\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Magnitude of balance mass required= 90.0 Residual unbalanced forces= 3263.971 N\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex2-pg310"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "##CHAPTER 12 ILLUSRTATION 2 PAGE NO 310\n",
- "##TITLE:Balancing of reciprocating of masses\n",
- "#calculate speed and swaying couples \n",
- "pi=3.141\n",
- "g=10.## acceleration due to gravity approximately in m/s**2\n",
- "mR=240.## mass of reciprocating parts per cylinder in kg\n",
- "m=300.## mass of rotating parts per cylinder in kg\n",
- "a=1.8##distance between cylinder centres in m\n",
- "c=.67## portion of reciprocating mass to be balanced\n",
- "b=.60## radius of balance masses in m\n",
- "r=24.## crank radius in cm\n",
- "R=.8##radius of thread of wheels in m\n",
- "M=40.\n",
- "##=======================================\n",
- "Ma=m+c*mR## total mass to be balanced in kg\n",
- "mD=211.9## mass of wheel D from figure in kg\n",
- "mC=211.9##..... mass of wheel C from figure in kg\n",
- "theta=171.## angular position of balancing mass C in degrees\n",
- "Br=c*mR/Ma*mC## balancing mass for reciprocating parts in kg\n",
- "w=(M*g**3./Br/b)**.5## angular speed in rad/s\n",
- "v=w*R*3600./1000.## speed in km/h\n",
- "S=a*(1.-c)*mR*w**2*r/2.**.5/100./1000.## swaying couple in kNm\n",
- "print'%s %.3f %s %.3f %s'%('speed=',v,' kmph'and ' swaying couple=',S,' kNm')\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "speed= 86.476 swaying couple= 21.812 kNm\n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex3-pg313"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "##CHAPTER 12 ILLUSRTATION 3 PAGE NO 313\n",
- "##TITLE:Balancing of reciprocating of masses\n",
- "#calculate hammer blow and tractive effort and swaying couple\n",
- "import math\n",
- "pi=3.141\n",
- "g=10.## acceleration due to gravity approximately in m/s**2\n",
- "a=.70##distance between cylinder centres in m\n",
- "r=60.## crank radius in cm\n",
- "m=130.##mass of rotating parts per cylinder in kg\n",
- "mR=210.## mass of reciprocating parts per cylinder in kg\n",
- "c=.67## portion of reciprocating mass to be balanced\n",
- "N=300.##e2engine speed in rpm\n",
- "b=.64## radius of balance masses in m\n",
- "##============================\n",
- "Ma=m+c*mR## total mass to be balanced in kg\n",
- "mA=100.44## mass of wheel A from figure in kg\n",
- "Br=c*mR/Ma*mA## balancing mass for reciprocating parts in kg\n",
- "H=Br*(2.*math.pi*N/60.)**2*b## hammer blow in N\n",
- "w=(2.*math.pi*N/60.)## angular speed\n",
- "T=2**.5*(1.-c)*mR*w**2.*r/2./100.##tractive effort in N\n",
- "S=a*(1.-c)*mR*w**2.*r/2./2.**.5/100.## swaying couple in Nm\n",
- "\n",
- "print'%s %.3f %s %.3f %s %.3f %s'%('Hammer blow=',H,' in N' 'tractive effort= ',T,' in N' 'swaying couple= ',S,' in Nm')\n",
- "print '%s'%(\"The answer is a bit different due to rounding off error in textbook\")"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Hammer blow= 32975.566 in Ntractive effort= 29018.117 in Nswaying couple= 10156.341 in Nm\n",
- "The answer is a bit different due to rounding off error in textbook\n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex4-pg314"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "##CHAPTER 12 ILLUSRTATION 4 PAGE NO 314\n",
- "##TITLE:Balancing of reciprocating of masses\n",
- "import math\n",
- "#calculate maximum unbalanced primary couples\n",
- "pi=3.141\n",
- "mR=900.## mass of reciprocating parts in kg\n",
- "N=90.## speed of the engine in rpm\n",
- "r=.45##crank radius in m\n",
- "cP=.9*mR*(2.*math.pi*N/60.)**2.*r*2.**.5/1000.## maximum unbalanced primary couple in kNm\n",
- "print'%s %.3f %s'%('maximum unbalanced primary couple=',cP,' k Nm')\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "maximum unbalanced primary couple= 45.788 k Nm\n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex5-pg315"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "##CHAPTER 12 ILLUSRTATION 5 PAGE NO 315\n",
- "##TITLE:Balancing of reciprocating of masses\n",
- "import math\n",
- "#calculate maximum unbalanced secondary force and with reasons\n",
- "pi=3.141\n",
- "mRA=160.## mass of reciprocating cylinder A in kg\n",
- "mRD=160.## mass of reciprocating cylinder D in kg\n",
- "r=.05## stroke lenght in m\n",
- "l=.2## connecting rod length in m\n",
- "N=450.## engine speed in rpm\n",
- "##===========================\n",
- "theta2=78.69## crank angle between A & B cylinders in degrees\n",
- "mRB=576.88## mass of cylinder B in kg\n",
- "n=l/r## ratio between connecting rod length and stroke length\n",
- "w=2.*math.pi*N/60.## angular speed in rad/s\n",
- "F=mRB*2.*w**2.*r*math.cos((2.*theta2)/57.3)/n\n",
- "print'%s %.3f %s'%('Maximum unbalanced secondary force=',F,' N in anticlockwise direction thats why - sign')\n",
- "print '%s'%(\"The answer is a bit different due to rounding off error in textbook\")"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Maximum unbalanced secondary force= -29560.284 N in anticlockwise direction thats why - sign\n",
- "The answer is a bit different due to rounding off error in textbook\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex6-pg316"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "##CHAPTER 12 ILLUSRTATION 6 PAGE NO 316\n",
- "##TITLE:Balancing of reciprocating of masses\n",
- "import math\n",
- "pi=3.141\n",
- "rA=.25## stroke length of A piston in m\n",
- "rB=.25## stroke length of B piston in m\n",
- "rC=.25## stroke length C piston in m\n",
- "N=300.## engine speed in rpm\n",
- "mRL=280.## mass of reciprocating parts in inside cylinder kg\n",
- "mRO=240.## mass of reciprocating parts in outside cylinder kg\n",
- "c=.5## portion ofreciprocating masses to be balanced \n",
- "b1=.5## radius at which masses to be balanced in m\n",
- "##======================\n",
- "mA=c*mRO## mass of the reciprocating parts to be balanced foreach outside cylinder in kg\n",
- "mB=c*mRL## mass of the reciprocating parts to be balanced foreach inside cylinder in kg\n",
- "B1=79.4## balancing mass for reciprocating parts in kg\n",
- "w=2.*math.pi*N/60.## angular speed in rad/s\n",
- "H=B1*w**2*b1## hammer blow per wheel in N\n",
- "print'%s %.1f %s'%('Hammer blow per wheel= ',H,' N')\n",
- "print '%s'%(\"The answer is a bit different due to rounding off error in textbook\")"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Hammer blow per wheel= 39182.3 N\n",
- "The answer is a bit different due to rounding off error in textbook\n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex7-pg318"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "##CHAPTER 12 ILLUSRTATION 7 PAGE NO 318\n",
- "##TITLE:Balancing of reciprocating of masses\n",
- "import math\n",
- "\n",
- "pi=3.141\n",
- "mR=300.## reciprocating mass per cylinder in kg\n",
- "r=.3## crank radius in m\n",
- "D=1.7## driving wheel diameter in m\n",
- "a=.7## distance between cylinder centre lines in m\n",
- "H=40.## hammer blow in kN\n",
- "v=90.## speed in kmph\n",
- "##=======================================\n",
- "R=D/2.## radius of driving wheel in m\n",
- "w=90.*1000./3600./R## angular velocity in rad/s\n",
- "##Br*b=69.625*c by mearument from diagram\n",
- "c=H*1000./(w**2.)/69.625## portion of reciprocating mass to be balanced\n",
- "T=2.**.5*(1-c)*mR*w**2.*r## variation in tractive effort in N\n",
- "M=a*(1.-c)*mR*w**2.*r/2.**.5## maximum swaying couple in N-m\n",
- "print'%s %.3f %s %.3f %s %.3f %s'%('portion of reciprocating mass to be balanced=',c,' ''variation in tractive effort=',T,' N'' maximum swaying couple=',M,' N-m')\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "portion of reciprocating mass to be balanced= 0.664 variation in tractive effort= 36980.420 N maximum swaying couple= 12943.147 N-m\n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex8-pg320"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "##CHAPTER 12 ILLUSRTATION 8 PAGE NO 320\n",
- "##TITLE:Balancing of reciprocating of masses\n",
- "import math\n",
- "pi=3.141\n",
- "N=1800.## speed of the engine in rpm\n",
- "r=6.## length of crank in cm\n",
- "l=24.## length of connecting rod in cm\n",
- "m=1.5## mass of reciprocating cylinder in kg\n",
- "##====================\n",
- "w=2.*math.pi*N/60.## angular speed in rad/s\n",
- "UPC=.019*w**2.## unbalanced primary couple in N-m\n",
- "n=l/r## ratio of length of crank to the connecting rod \n",
- "USC=.054*w**2./n## unbalanced secondary couple in N-m\n",
- "print'%s %.f %s %.3f %s '%('unbalanced primary couple=',UPC,'N-m' 'unbalanced secondary couple=',USC,' N-m')\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "unbalanced primary couple= 675 N-munbalanced secondary couple= 479.663 N-m \n"
- ]
- }
- ],
- "prompt_number": 8
- }
- ],
- "metadata": {}
- }
- ]
-}
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