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+{
+ "metadata": {
+ "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 11 : Some Applications"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 11.1, Page No 622"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "V_s=11000.0\n",
+ "V_ml=math.sqrt(2)*V_s\n",
+ "f=50.0\n",
+ "\n",
+ "#Calculations\n",
+ "w=2*math.pi*f\n",
+ "I_d=300\n",
+ "R_d=1\n",
+ "g=20 #g=gamma\n",
+ "a=math.degrees(math.acos(math.cos(math.radians(g))+math.pi/(3*V_ml)*I_d*R_d)) \n",
+ "L_s=.01\n",
+ "V_d=(3/math.pi)*((V_ml*math.cos(math.radians(a)))-w*L_s*I_d) \n",
+ "\n",
+ "#Results\n",
+ "print(\"firing angle=%.3f deg\" %a)\n",
+ "print(\"rectifier o/p voltage=%.1f V\" %V_d)\n",
+ "print(\"dc link voltage=%.3f V\" %(2*V_d/1000))"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "firing angle=16.283 deg\n",
+ "rectifier o/p voltage=13359.3 V\n",
+ "dc link voltage=26.719 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 11.2, Page No 623"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "V_d=(200.0+200)*10**3\n",
+ "P=1000.0*10**6\n",
+ "\n",
+ "#Calculations\n",
+ "I_d=P/V_d\n",
+ " #each thristor conducts for 120deg for a periodicity of 360deg\n",
+ "a=0\n",
+ "V_d=200.0*10**3\n",
+ "V_ml=V_d*math.pi/(3*math.cos(math.radians(a)))\n",
+ "\n",
+ "#Results\n",
+ "print(\"rms current rating of thyristor=%.2f A\" %(I_d*math.sqrt(120/360)))\n",
+ "print(\"peak reverse voltage across each thyristor=%.2f kV\" %(V_ml/2/1000))"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "rms current rating of thyristor=0.00 A\n",
+ "peak reverse voltage across each thyristor=104.72 kV\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 11.3 Page No 627"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "V_m=230.0\n",
+ "V_s=230/math.sqrt(2)\n",
+ "pf=0.8\n",
+ "P=2000.0\n",
+ "\n",
+ "#Calculations\n",
+ "I_m=P/(V_s*pf)\n",
+ "I_Tr=I_m/math.sqrt(2)\n",
+ "I_TA=2*I_m/math.pi\n",
+ "fos=2 #factor of safety\n",
+ "PIV=V_m*math.sqrt(2)\n",
+ "I_Tr=I_m/(2)\n",
+ "I_TA=I_m/math.pi\n",
+ "\n",
+ "#Results\n",
+ "print(\"rms value of thyristor current=%.2f A\" %(fos*I_Tr))\n",
+ "print(\"avg value of thyristor current=%.3f A\" %(fos*I_TA))\n",
+ "print(\"voltage rating of thyristor=%.2f V\" %PIV)\n",
+ "print(\"rms value of diode current=%.3f A\" %(fos*I_Tr))\n",
+ "print(\"avg value of diode current=%.3f A\" %(fos*I_TA))\n",
+ "print(\"voltage rating of diode=%.2f V\" %PIV)\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "rms value of thyristor current=15.37 A\n",
+ "avg value of thyristor current=9.786 A\n",
+ "voltage rating of thyristor=325.27 V\n",
+ "rms value of diode current=15.372 A\n",
+ "avg value of diode current=9.786 A\n",
+ "voltage rating of diode=325.27 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 11.4, Page No 629"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "V=200.0\n",
+ "I=10.0\n",
+ "\n",
+ "#Calculations\n",
+ "R_L=V/I \n",
+ "I_h=.005 #holding current\n",
+ "R2=V/I_h \n",
+ "t_c=20*10**-6\n",
+ "fos=2 #factor of safety\n",
+ "C=t_c*fos/(R_L*math.log(2)) \n",
+ "\n",
+ "#Results\n",
+ "print(\"value of load resistance=%.0f ohm\" %R_L)\n",
+ "print(\"value of R2=%.0f kilo-ohm\" %(R2/1000))\n",
+ "print(\"value of C=%.3f uF\" %(C*10**6))"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "value of load resistance=20 ohm\n",
+ "value of R2=40 kilo-ohm\n",
+ "value of C=2.885 uF\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 11.5 Page No 646"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "u_r=10\n",
+ "f=10000.0 #Hz\n",
+ "p=4.0*10**-8 #ohm-m\n",
+ "\n",
+ "#Calculations\n",
+ "dl=(1/(2*math.pi))*math.sqrt(p*10**7/(u_r*f)) \n",
+ "l=0.12 #length of cylinder\n",
+ "t=20.0 #no of turns\n",
+ "I=100.0\n",
+ "H=t*I/l\n",
+ "P_s=2*math.pi*H**2*math.sqrt(u_r*f*p*10**-7) \n",
+ "d=.02 #diameter\n",
+ "P_v=4*H**2*p/(d*dl) \n",
+ "\n",
+ "#Results\n",
+ "print(\"depth of heat of penetration=%.5f mm\" %(dl*1000))\n",
+ "print(\"heat generated per unit cylinder surface area=%.3f W/m**2\" %P_s)\n",
+ "print(\"heat generated per unit cylinder volume=%.0f W/m**3\" %P_v)\n",
+ " #answer of P_v varies as given in book as value of d is not taken as in formulae. "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "depth of heat of penetration=0.31831 mm\n",
+ "heat generated per unit cylinder surface area=34906.585 W/m**2\n",
+ "heat generated per unit cylinder volume=6981317 W/m**3\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 11.6 Page No 646"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "f=3000.0\n",
+ "\n",
+ "#Calculations\n",
+ "t_qmin=30.0*10**-6\n",
+ "f_r=f/(1-2*t_qmin*f)\n",
+ "R=0.06\n",
+ "L=20.0*10**-6\n",
+ "C=1/(L*((2*math.pi*f_r)**2+(R/(2*L))**2)) \n",
+ "\n",
+ "#Results\n",
+ "print(\"required capacitor size=%.4f F\" %(C*10**6))\n",
+ " #Answers have small variations from that in the book due to difference in the rounding off of digits."
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "required capacitor size=94.2215 F\n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+} \ No newline at end of file