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diff --git a/Water_and_Wastewater_Engineering/ch15.ipynb b/Water_and_Wastewater_Engineering/ch15.ipynb new file mode 100644 index 00000000..5101dc59 --- /dev/null +++ b/Water_and_Wastewater_Engineering/ch15.ipynb @@ -0,0 +1,221 @@ +{ + "metadata": { + "name": "", + "signature": "sha256:209dfa66c415d9b6d77e6ef0fd2310df1d6593c2b60b5941934cee9e5b7d9fa6" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter 15 : Wastewater Collection" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 15.1 Page No : 15-4" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\t\n", + "#initialisation of variables\n", + "q = 0.25\t#in\n", + "Q = 0.34\t#in\n", + "r = 0.76\t#in\n", + "v = 0.83\t#in\n", + "n = 0.78\t#in\n", + "r1 = 0.84\t#in\n", + "v1 = 0.70\t#in\n", + "w = 2\t#in\n", + "q1 = 0.056\t#in\n", + "d = 0.16\t#in\n", + "v2 = 0.53\t#in\n", + "n1 = 0.80\t#in\n", + "d1 = 0.18\t#in\n", + "n2 = 0.46\t#in\n", + "\t\n", + "#CALCULATIONS\n", + "V = v*w\t#fps\n", + "N = v1*w\t#fps\n", + "V1 = v2*w\t#fps\n", + "V2 = n2*w\t#fps\n", + "\t\n", + "#RESULTS\n", + "print 'The one fourth their full flow = %.2f fps'%(N)\n", + "print 'The one enghteenth their full flow = %.2f fps'%(V2)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The one fourth their full flow = 1.40 fps\n", + "The one enghteenth their full flow = 0.92 fps\n" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 15.2 Page No : 15-9" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\t\n", + "#initialisation of variables\n", + "v = 2.5\t#fps\n", + "N = 0.015\t#fps\n", + "a = (40+27)\t#in\n", + "b = (40*27+27*19)/a\n", + "c = 0.440\t#cfs\n", + "w = 49*0.09/100\t#cfs\n", + "g = 0.008\t#percent\n", + "Q = 0.82\t#cfs\n", + "r = 0.795\t#cfs\n", + "t = 2.35*1.16\t#fps\n", + "d1 = 113.20-113.03\t#ft\n", + "d2 = 12\t#ft\n", + "\t\n", + "#CALCULATIONS\n", + "R = r/Q\t#cfs\n", + "D = g*r\t#in\n", + "D2 = d1*d2\t#in\n", + "\t\n", + "#RESULTS\n", + "print 'The required capacity and find the slope size and hydraulic characteristics of the system = %.0f in'%(D2)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The required capacity and find the slope size and hydraulic characteristics of the system = 2 in\n" + ] + } + ], + "prompt_number": 2 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 15.3 Page No : 15-17" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\t\n", + "#initialisation of variables\n", + "p = 20\t#min\n", + "N = 0.012\t#in\n", + "k = 2.19\t#min\n", + "l = k+1.97\t#min\n", + "q = 340/(60*3.94)\t#min\n", + "r = 2.56*0.508\t#min\n", + "del1 = 0.42\t#min\n", + "j = 84.28\t#min\n", + "w1 = 0.92\t#min\n", + "\t\n", + "#CALCULATIONS\n", + "r1 = r*k\t#cfs\n", + "w = p+q\t#min\n", + "G = j-del1\t#min\n", + "S = (G-w1)\t#min\n", + "\t\n", + "#RESULTS\n", + "print 'The required capacity and find the slop size and hydraulic = %.2f min'%(S)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The required capacity and find the slop size and hydraulic = 82.94 min\n" + ] + } + ], + "prompt_number": 3 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 15.4 Page No : 15-25" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math \n", + "\t\n", + "#initialisation of variables\n", + "a = 42.\t#in\n", + "d = 45.\t#mgd\n", + "d1 = 0.75\t#in\n", + "s = 60.\t#ft\n", + "p1 = 9.\t#in\n", + "p2 = 8.4\t#in\n", + "p3 = 9.\t#in\n", + "c1 = 13*63.6\t#sq in\n", + "c2 = 9*55.4\t#sq in\n", + "c3 = 9.21\t#sq ft\n", + "M = d*1.547\t#cfs\n", + "v = M/c3\t#fps\n", + "g = 0.025*32.2\t#ft/sec**2\n", + "\t\n", + "#CALCULATIONS\n", + "F = v/math.sqrt(g*(p1/12))\t#ft\n", + "S = s/d1\t#in\n", + "\t\n", + "#RESULTS\n", + "print 'the port near the end of the diffuser pipe = %.2f in'%(F)\n", + "\n", + "# note : rounding off error." + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "the port near the end of the diffuser pipe = 9.73 in\n" + ] + } + ], + "prompt_number": 2 + } + ], + "metadata": {} + } + ] +}
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