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+{
+ "cells": [
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# 9: Nuclear Reactions"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example number 1, Page number 272"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 8,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "number of nuclei produced per second is 1.66 *10**5\n",
+      "answer given in the book is wrong\n"
+     ]
+    }
+   ],
+   "source": [
+    "#importing modules\n",
+    "import math\n",
+    "from __future__ import division\n",
+    "\n",
+    "#Variable declaration    \n",
+    "rho=19.3*10**3;         #density(kg/m**3)\n",
+    "N=6.02*10**23;          #avagadro number\n",
+    "M=197;                  #molecular weight\n",
+    "a=2*10**12;             #neutrons/m**2 sec\n",
+    "A=5*10**-4;             #area(m**2)\n",
+    "sigma=94*10**-28;               #reaction cross section(m**2)\n",
+    "t=0.3*10**-3;                  #thickness(m)\n",
+    "\n",
+    "#Calculations\n",
+    "n=rho*N/M;              #number of nuclei per unit volume(per m**3)\n",
+    "N0=a*A;                 #number of neutrons hitting the target\n",
+    "N0_N=N0*(1-math.exp(-n*sigma*t));       #number of nuclei produced per second\n",
+    "\n",
+    "#Result\n",
+    "print \"number of nuclei produced per second is\",round(N0_N/10**5,2),\"*10**5\"\n",
+    "print \"answer given in the book is wrong\""
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example number 2, Page number 275"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 20,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "energy of neutron is 19.768 MeV\n",
+      "energy of Be is 5.007 MeV\n",
+      "angle of recoil of Be atom is 44.855 or 45 degrees\n"
+     ]
+    }
+   ],
+   "source": [
+    "#importing modules\n",
+    "import math\n",
+    "from __future__ import division\n",
+    "\n",
+    "#Variable declaration    \n",
+    "M1=2.01472;       #molecular mass of H(amu)\n",
+    "M0=7.01784;       #molecular mass of Li(amu)\n",
+    "M2=8.00776;       #molecular mass of Be(amu)\n",
+    "M3=1.00893;       #molecular mass of n(amu)\n",
+    "Ek1=10;           #energy(MeV)\n",
+    "\n",
+    "#Calculations\n",
+    "M1M0=M1+M0;       #mass of interacting particles(amu)\n",
+    "M2M3=M2+M3;       #mass of product particles(amu)\n",
+    "Q=(M1M0-M2M3)*931; #decrease in mass(MeV)\n",
+    "Ek3=(Q+(Ek1*(1-(M1/M2))))/(1+(M3/M2));   #energy of neutron(MeV)\n",
+    "Ek2=Q+Ek1-Ek3;        #energy of Be(MeV)\n",
+    "phi=math.atan(math.sqrt(Ek3*M3/(Ek1*M1)));     #angle of recoil of Be atom(rad)\n",
+    "phi=phi*180/math.pi;                   #angle of recoil of Be atom(degrees)\n",
+    "\n",
+    "#Result\n",
+    "print \"energy of neutron is\",round(Ek3,3),\"MeV\" \n",
+    "print \"energy of Be is\",round(Ek2,3),\"MeV\" \n",
+    "print \"angle of recoil of Be atom is\",round(phi,3),\"or\",int(round(phi)),\"degrees\""
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example number 3, Page number 277"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 22,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "energy of emitted protons is 5.3 MeV\n"
+     ]
+    }
+   ],
+   "source": [
+    "#importing modules\n",
+    "import math\n",
+    "from __future__ import division\n",
+    "\n",
+    "#Variable declaration    \n",
+    "Q=-3.9;     #Q value of reaction(MeV)\n",
+    "M1=1.0087;       #molecular mass of incident neutron(amu)\n",
+    "M2=18.99;        #molecular mass of O nucleus(amu)\n",
+    "M3=1.0078;       #molecular mass of proton(amu)\n",
+    "Ek1=10;          #energy of incident neutron(MeV)\n",
+    "\n",
+    "#Calculations\n",
+    "x=1-(M1/M2);\n",
+    "y=1+(M3/M2);\n",
+    "Ek3=(Q+Ek1*x)/y;   #energy of emitted protons(MeV)\n",
+    "\n",
+    "#Result\n",
+    "print \"energy of emitted protons is\",round(Ek3,1),\"MeV\""
+   ]
+  }
+ ],
+ "metadata": {
+  "kernelspec": {
+   "display_name": "Python 2",
+   "language": "python",
+   "name": "python2"
+  },
+  "language_info": {
+   "codemirror_mode": {
+    "name": "ipython",
+    "version": 2
+   },
+   "file_extension": ".py",
+   "mimetype": "text/x-python",
+   "name": "python",
+   "nbconvert_exporter": "python",
+   "pygments_lexer": "ipython2",
+   "version": "2.7.11"
+  }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 0
+}