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Diffstat (limited to 'Thermodynamics_for_Engineers/Chapter_5.ipynb')
| -rwxr-xr-x | Thermodynamics_for_Engineers/Chapter_5.ipynb | 199 |
1 files changed, 0 insertions, 199 deletions
diff --git a/Thermodynamics_for_Engineers/Chapter_5.ipynb b/Thermodynamics_for_Engineers/Chapter_5.ipynb deleted file mode 100755 index 60d3de94..00000000 --- a/Thermodynamics_for_Engineers/Chapter_5.ipynb +++ /dev/null @@ -1,199 +0,0 @@ -{
- "metadata": {
- "name": "",
- "signature": "sha256:86a66a56e6c068c1b5488c8e726c9aecdd48422f90b429aec4b5cc311da3bb32"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 5 - Actual Gases"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1 - Pg 74"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the volume occupied by the gas and also the tabulated volume\n",
- "#Initialization of variables\n",
- "m=20. #lbm\n",
- "P=1000. #psia\n",
- "T=580. #R\n",
- "R=35.12\n",
- "#calculations\n",
- "print '%s' %(\"From table 5-2,\")\n",
- "z=0.667\n",
- "V=z*m*R*T/(P*144.)\n",
- "vt=0.0935\n",
- "vtt=vt*m\n",
- "#results\n",
- "print '%s %.3f %s' %(\"Volume occupied =\",V,\"cu ft\")\n",
- "print '%s %.2f %s' %(\"\\n Tablulated value for volume =\",vtt,\" cu ft\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "From table 5-2,\n",
- "Volume occupied = 1.887 cu ft\n",
- "\n",
- " Tablulated value for volume = 1.87 cu ft\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2 - Pg 74"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the pressure obtained and theoretical pressure\n",
- "#Initialization of variables\n",
- "m=90 #lbm\n",
- "T=200+459.7 #R\n",
- "Tc=232.7+459.7 #R\n",
- "R0=1545.\n",
- "M=120.9\n",
- "V=30. #cu ft\n",
- "#calculations\n",
- "R=R0/M\n",
- "print '%s' %(\"From fig 5.5\")\n",
- "z=0.883\n",
- "P=z*R*m*T/V/144.\n",
- "vc=V/m\n",
- "P2=156.1 #psia\n",
- "#results\n",
- "print '%s %.2f %s' %(\"Pressure obtained =\",P,\"psia\")\n",
- "print '%s %.1f %s' %(\"\\n Theoretical pressure =\",P2,\"psia\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "From fig 5.5\n",
- "Pressure obtained = 155.08 psia\n",
- "\n",
- " Theoretical pressure = 156.1 psia\n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3 - Pg 84"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the heat added in both cases\n",
- "#Initialization of variables\n",
- "import math\n",
- "T1=140+460. #R\n",
- "T2=240 +460. #R\n",
- "N=1.\n",
- "#calculations\n",
- "Q=N*(9.47*(T2-T1)-3.47*1000. *math.log(T2/T1) -1.16*math.pow(10,6) *(1/T2-1/T1))\n",
- "Tm=(T1+T2)/2\n",
- "Cp=9.47-3.47*1000. /Tm +1.16*math.pow(10,6) /Tm/Tm\n",
- "Q2=N*Cp*(T2-T1)\n",
- "#results\n",
- "print '%s %d %s' %(\"Heat added in case 1 =\",Q,\"Btu\")\n",
- "print '%s %.1f %s' %(\"\\n Heat added in case 2 =\",Q2,\"Btu\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Heat added in case 1 = 688 Btu\n",
- "\n",
- " Heat added in case 2 = 687.7 Btu\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4 - Pg 85"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the heat added in both cases\n",
- "#Initialization of variables\n",
- "import math\n",
- "Rj=1.985\n",
- "N=1\n",
- "T1=540.+460 #R\n",
- "T2=3540.+460 #R\n",
- "#calculations\n",
- "Q=N*(14.215*(T2-T1)-6.53*1000. *math.log(T2/T1) -1.41*math.pow(10,6) *(1/T2-1/T1))\n",
- "Tm=(T1+T2)/2\n",
- "Cv=14.215-6.53*1000. /Tm +1.41*math.pow(10,6) /Tm/Tm\n",
- "Q2=N*Cv*(T2-T1)\n",
- "#results\n",
- "print '%s %.1f %s' %(\"Heat added in case 1 =\",Q,\"Btu\")\n",
- "print '%s %.1f %s' %(\"\\n Heat added in case 2 =\",Q2,\"Btu\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Heat added in case 1 = 34650.0 Btu\n",
- "\n",
- " Heat added in case 2 = 35485.8 Btu\n"
- ]
- }
- ],
- "prompt_number": 6
- }
- ],
- "metadata": {}
- }
- ]
-}
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