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diff --git a/Thermodynamics_for_Engineers/Chapter_17_2.ipynb b/Thermodynamics_for_Engineers/Chapter_17_2.ipynb deleted file mode 100755 index 98fc5f10..00000000 --- a/Thermodynamics_for_Engineers/Chapter_17_2.ipynb +++ /dev/null @@ -1,132 +0,0 @@ -{
- "metadata": {
- "name": "",
- "signature": "sha256:b620865a516deeb75cd703005b53698c7a7013658cab02400acc0bf08c43a5d1"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 17 - Internal-combustion engines"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1 - Pg 358"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the indicated efficiency, brake thermal efficiency in both cases\n",
- "#Initalization of variables\n",
- "hp1=2000. #bhp\n",
- "m=792. #lb/hr\n",
- "ex=0.5\n",
- "hp2=210.\n",
- "hv=18900. #Btu/lb\n",
- "etth=51.3\n",
- "#calculations\n",
- "ihp=hp1+hp2\n",
- "ietat= ihp*2544/(m*hv) *100\n",
- "betat=ietat*hp1/ihp\n",
- "betat2=hp1*2544/(m*hv) *100\n",
- "ietae=ietat/etth *100\n",
- "betae=betat/etth *100\n",
- "brake= ietae*hp1/ihp\n",
- "#results\n",
- "print '%s %.1f %s' %(\"Indicated efficiency =\",ietat,\"percent\")\n",
- "print '%s %.1f %s' %(\"\\n Brake thermal efficiency =\",betat,\" percent\")\n",
- "print '%s %.1f %s' %(\"\\n In case 2, Brake thermal efficiency =\",betat2,\"percent\")\n",
- "print '%s %.1f %s' %(\"\\n Indicated thermal efficiency =\",ietae,\" percent\")\n",
- "print '%s %.1f %s' %(\"\\n Brake engine efficiency =\",betae,\" percent\")\n",
- "print '%s %.1f %s' %(\"\\n In case 2, Brake engine efficiency =\",brake,\"percent\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Indicated efficiency = 37.6 percent\n",
- "\n",
- " Brake thermal efficiency = 34.0 percent\n",
- "\n",
- " In case 2, Brake thermal efficiency = 34.0 percent\n",
- "\n",
- " Indicated thermal efficiency = 73.2 percent\n",
- "\n",
- " Brake engine efficiency = 66.3 percent\n",
- "\n",
- " In case 2, Brake engine efficiency = 66.3 percent\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2 - Pg 361"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the indicated mep\n",
- "#Initalization of variables\n",
- "J=778.\n",
- "o2=12.5\n",
- "theo=0.95\n",
- "N=56.5\n",
- "R0=1545.\n",
- "T=540. #R\n",
- "p=14. #psia\n",
- "LHV=2368089. #Btu/lb\n",
- "ther=39.4\n",
- "iep=0.78\n",
- "ve=0.8\n",
- "#calculations\n",
- "Ar=o2/0.21 *theo\n",
- "vol=N*R0*T/(144*p)\n",
- "hv=(LHV -17730)/LHV\n",
- "ithep=iep*ther\n",
- "pd=ithep/100 *ve *100.5\n",
- "mep=J*pd\n",
- "#results\n",
- "print '%s %d %s' %(\"Indicated mep =\",mep,\"lb/sq ft\")\n",
- "print '%s' %(\"The answer might differ from textbook due to rounding off error\")"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Indicated mep = 19223 lb/sq ft\n",
- "The answer might differ from textbook due to rounding off error\n"
- ]
- }
- ],
- "prompt_number": 1
- }
- ],
- "metadata": {}
- }
- ]
-}
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