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Diffstat (limited to 'Thermodynamics_for_Engineers/Chapter_15.ipynb')
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diff --git a/Thermodynamics_for_Engineers/Chapter_15.ipynb b/Thermodynamics_for_Engineers/Chapter_15.ipynb deleted file mode 100755 index 25cf3bae..00000000 --- a/Thermodynamics_for_Engineers/Chapter_15.ipynb +++ /dev/null @@ -1,158 +0,0 @@ -{
- "metadata": {
- "name": "",
- "signature": "sha256:d798b16416897dedbfd57aff5c233c1f7e9c52a7f0081b45c972d6ab47468c7c"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 15 - Thermodynamics of chemical reactions"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1 - Pg 318"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the amount of dissociation\n",
- "#Initalization of variables\n",
- "import math\n",
- "import numpy\n",
- "kp=math.pow(10,(1.45))\n",
- "#calculations\n",
- "s=[1-kp*kp , 0, -3, 2]\n",
- "vec=numpy.roots(s)\n",
- "X=numpy.real(vec[2])\n",
- "xper=X*100\n",
- "#results\n",
- "print '%s %.1f %s' %(\"Amount of dissociaton =\",xper,\"percent\")\n",
- "print '%s %.3f %s %.3f %s %.3f %s' %(\"\\n Of each original mole of CO2, there will be\",X,\"mole of CO \",X/2.,\" mol of Oxygen and\",(1-X),\"mol of CO2\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Amount of dissociaton = 12.7 percent\n",
- "\n",
- " Of each original mole of CO2, there will be 0.127 mole of CO 0.063 mol of Oxygen and 0.873 mol of CO2\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2 - Pg 319"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the max. temperature reached\n",
- "#Initalization of variables\n",
- "U=121200. #Btu/mol\n",
- "Uco2=51635. #Btu/mol\n",
- "Un2=27589. #Btu/mol\n",
- "Uco22=57875. #Btu/mol\n",
- "Un22=21036. #Btu/mol\n",
- "T1=5000. #R\n",
- "T2=5500. #R\n",
- "#calculations\n",
- "Ut1=Uco2+1.88*Un2\n",
- "Ut2=Uco22 + 1.88*Un22\n",
- "print '%s' %(\"By extrapolation,\")\n",
- "Tx=5710 #R\n",
- "#results\n",
- "print '%s %d %s' %(\"Max. Temperature reached =\",Tx,\"R\")\n",
- "print '%s' %(\"The calculation for Ut2 is wrong in textbook. Please use a calculator.\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "By extrapolation,\n",
- "Max. Temperature reached = 5710 R\n",
- "The calculation for Ut2 is wrong in textbook. Please use a calculator.\n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3 - Pg 319"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the max. obtainable temperature\n",
- "#Initalization of variables\n",
- "print '%s' %(\"By trial and error,\")\n",
- "import math\n",
- "X=0.201\n",
- "X1=0.2\n",
- "R=59.3 #universal gas constant\n",
- "T=5000 #R\n",
- "U=121200 #Btu/mol\n",
- "Uco2=51635. #Btu/mol\n",
- "Un2=27907. #Btu/mol\n",
- "U3=29616. #Btu/mol\n",
- "U4=27589. #Btu/mol\n",
- "#calculations\n",
- "kp1=R*(1-X1)/math.pow(X1,1.5) /math.pow(T,0.5)\n",
- "kp2=R*(1-X)/math.pow(X,1.5) /math.pow(T,0.5)\n",
- "q=(1-X)*Uco2 + X*Un2+ X/2 *U3 +1.88*U4 + X*U\n",
- "print '%s' %(\"Interpolating between T=4500 R and T=5000 R, we get\")\n",
- "T2=4907 #R\n",
- "#results\n",
- "print '%s %d %s' %(\"Max. obtainable temperature =\",T2,\" R\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "By trial and error,\n",
- "Interpolating between T=4500 R and T=5000 R, we get\n",
- "Max. obtainable temperature = 4907 R\n"
- ]
- }
- ],
- "prompt_number": 3
- }
- ],
- "metadata": {}
- }
- ]
-}
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