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+{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:47f72be1b9c6cd56213869831cb1984e5af98a10c08e54d4fdad5c35b07de8a5"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 11 : Introduction to Working of IC Engines"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 11.1 Page No : 264"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math \n",
+ "\n",
+ "# Variables\n",
+ "n = 3;\n",
+ "l = 80;\t\t\t# in mm\n",
+ "d = 76;\t\t\t# in mm\n",
+ "r = 8.5;\n",
+ "\n",
+ "# Calculations and Results\n",
+ "V_s = (math.pi/4.) * d * d * l;\t\t\t# in mm**3\n",
+ "V_s = V_s * 10**-3;\t\t\t# in cm**3\n",
+ "# r = 1+ (V_s/V_c)\n",
+ "V_c = (1/(r - 1)) * V_s;\t\t\t# in cm**3\n",
+ "print \"volume of cylinder in mm**3 is : \",round(V_c*10**3) #incorrect answer in the textbook\n",
+ "\n",
+ "C = V_s * n;\t\t\t# C s math.radians(numpy.tan(s for capacity of engine in cm**3\n",
+ "C = C * 10**-3;\t\t\t# in litre\n",
+ "print \"Capacity of the engine in litre is : %.3f\"%C\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "volume of cylinder in mm**3 is : 48389.0\n",
+ "Capacity of the engine in litre is : 1.089\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+} \ No newline at end of file