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diff --git a/Thermodynamics_by_F_P_Durham/chapter14.ipynb b/Thermodynamics_by_F_P_Durham/chapter14.ipynb new file mode 100755 index 00000000..e037e77a --- /dev/null +++ b/Thermodynamics_by_F_P_Durham/chapter14.ipynb @@ -0,0 +1,383 @@ +{ + "metadata": { + "name": "", + "signature": "sha256:e1f2ab4731e8126f69d8554acbb321ab940bce50cce33579f99b691416bd49a5" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter 14: Heat Transfer" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 14.1, page no. 279" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "#initialization\n", + "T = 50.0 #F\n", + "Q = 3.9 #B/hr-ft^2\n", + "\n", + "#calculation\n", + "#From table 14.1\n", + "k = 0.026 #B/hr-ft-F\n", + "dx = k*T/Q\n", + "\n", + "#result\n", + "print \"Required thickness = ft\", round(dx, 3), \"lb/in^2\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Required thickness = ft 0.333 lb/in^2\n" + ] + } + ], + "prompt_number": 2 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 14.2, page no. 281" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "#initialization\n", + "x1 = 1.0 #in\n", + "x2 = 4.0 #in\n", + "T1 = 85.0 #F\n", + "T2 = 30.0 #F\n", + "\n", + "#calculation\n", + "QbyA = 12*(T1-T2)/(x1/0.3 + x2/0.026)\n", + "\n", + "#result\n", + "print \"Rate of heat flow = \", round(QbyA, 1), \"B/r-ft^2-F\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Rate of heat flow = 4.2 B/r-ft^2-F\n" + ] + } + ], + "prompt_number": 3 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 14.3, page no. 283" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "import math\n", + "\n", + "#initialization\n", + "L = 6.5 #in\n", + "thick = 1.0 #in\n", + "k = 0.06 #B/hr-ft-F\n", + "T1 = 350.0 #F\n", + "T2 = 110.0 #F\n", + "\n", + "#calculation\n", + "QbyL = 2*math.pi*k*(T1-T2)/math.log(1+2/L)\n", + "\n", + "#result\n", + "print \"heat flow = %d B/hr-ft\" %QbyL" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "heat flow = 337 B/hr-ft\n" + ] + } + ], + "prompt_number": 4 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 14.4, page no. 283" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "import math\n", + "\n", + "#initialization\n", + "t = 0.25 #in\n", + "dia = 5.5 #in\n", + "t2 = 0.6 #in\n", + "To = 100.0 #F\n", + "kp = 34.5 #B/hr-ft-F\n", + "ki = 0.05 #B/hr-ft-F\n", + "l = 10.0 #ft\n", + "Q = 2000.0 #B/hr\n", + "\n", + "#calculation\n", + "dT = Q*(1/kp *math.log(1+ 2*t/dia) + 1/ki *math.log(1 + 4*t/(dia+2*t)))/(2*math.pi*l)\n", + "T1 = dT+To\n", + "\n", + "#result\n", + "print \"Inner surface temperature of the pipe = \", round(T1, 1), \"F\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Inner surface temperature of the pipe = 198.2 F\n" + ] + } + ], + "prompt_number": 6 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 14.5, page no. 286" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "#initialization\n", + "Tsurr = 90.0 #F\n", + "T = 85.0 #F\n", + "\n", + "#calculation\n", + "H = 4.2/(Tsurr-T)\n", + "\n", + "#result\n", + "print \"Film coefficient = %.2f B/hr-ft^2-F\" %H" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Film coefficient = 0.84 B/hr-ft^2-F\n" + ] + } + ], + "prompt_number": 7 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 14.6, page no. 288" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "#initialization\n", + "k = 0.04 #B/hr-ft-F\n", + "thick = 1.0 #in\n", + "T1 = 90.0 #F\n", + "T2 = 30.0 #F\n", + "Air = 2.5 #B/hr-ft^2-F\n", + "film = 2.0 #B/hr-ft^2-F\n", + "\n", + "#calculation\n", + "U = 1.0/(1.0/Air + thick/12.0/k + 1/film)\n", + "Q = U*(T1-T2)\n", + "\n", + "#result\n", + "print \"Rate of heat transfer per unit square area = %.1f B/hr-ft^2\" %Q" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Rate of heat transfer per unit square area = 20.1 B/hr-ft^2\n" + ] + } + ], + "prompt_number": 8 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 14.7, page no. 291" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "import math\n", + "\n", + "#initialization\n", + "U = 115.0 #B/hr-ft^2-F\n", + "T1 = 190.0 #F\n", + "T2 = 160.0 #F\n", + "Tc1 = 65.0 #F\n", + "Tc2 = 100.0 #F\n", + "w = 140.0 #lbm/min\n", + "c = 0.8 #B/lbm F\n", + "\n", + "#calculation\n", + "Q = w*60.0*c*(T1-T2) #answer in textbook for Q is wrong. Hence, the difference in final answer\n", + "dT = ((T1-Tc2) - (T2-Tc1))/math.log((T1-Tc2)/(T2-Tc1))\n", + "A = Q/(U*dT)\n", + "\n", + "#result\n", + "print \"Required Area = %.1f ft^2\" %A" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Required Area = 19.0 ft^2\n" + ] + } + ], + "prompt_number": 14 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 14.8, page no. 294" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "#initialization\n", + "e = 0.8\n", + "T1 = 100+460.0 #R\n", + "T2 = 300+460.0 #R\n", + "\n", + "#calculation\n", + "Qdot = 0.173*10**-8 *(T2**4 - T1**4)/(1/e +1/e -1)\n", + "\n", + "#result\n", + "print \"Radiant heat transfer per sq. foot = %d B/hr-ft^2\" %(Qdot+1)" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Radiant heat transfer per sq. foot = 272 B/hr-ft^2\n" + ] + } + ], + "prompt_number": 15 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 14.9, page no. 294" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "#initialization\n", + "T1 = 400+460.0 #R\n", + "A = 40.0 #in^2\n", + "e = 0.1\n", + "T2 = 70+460.0 #R\n", + "\n", + "#calculation\n", + "Q = A*e*0.173*10**-8 *(T1**4 - T2**4)/144.0\n", + "\n", + "#result\n", + "print \"Rate of heat transfer = %.2f B/hr\" %Q\n", + "#answer in the book is wrong" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Rate of heat transfer = 22.49 B/hr\n" + ] + } + ], + "prompt_number": 19 + } + ], + "metadata": {} + } + ] +}
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