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diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter_3_3.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter_3_3.ipynb new file mode 100755 index 00000000..0029d9f0 --- /dev/null +++ b/Thermodynamics:_From_concepts_to_applications/Chapter_3_3.ipynb @@ -0,0 +1,220 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:6d28037b4c9a453240f29bc629f78e4da0796902d617a06cee6c7af7af12458e"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "chapter3-Work energy and heat first law of thermodynamics"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 3 - Pg 25"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "##calculate the work interaction of spring\n",
+ "##initialisation of variables\n",
+ "m= 5 ##kg\n",
+ "g= 9.8 ##m/sec^2\n",
+ "k= 500 ##N/m\n",
+ "##CALCULATIONS\n",
+ "x= m*g/k\n",
+ "W= -m*g*x\n",
+ "##RESULTS\n",
+ "print'%s %.2f %s'% ('work interaction of spring = ',W,'J')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "work interaction of spring = -4.80 J\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 4 pg 27"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "##calculate the work done by the gas\n",
+ "##initialisation of variables\n",
+ "m= 500 ##kg\n",
+ "V= 50 ##L\n",
+ "P= 700 ##kPa\n",
+ "T= 25 ##C\n",
+ "P0= 100 ##kPa\n",
+ "g= 9.8 ##m/sec^2\n",
+ "A= 200 ##cm^2\n",
+ "V1= 100 ##L\n",
+ "##CALCULATIONS\n",
+ "pe= P0*math.pow(10,3)+(m*g/(A*(math.pow(10,-4))))\n",
+ "W= pe*(V1-V)*(math.pow(10,-6))\n",
+ "##RESULTS\n",
+ "print'%s %.2f %s'% ('work of the gas =',W,'kJ')"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "work of the gas = 17.25 kJ\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 5 pg 32"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "##calcualte the energy change in process 1,2,3 and work in third process\n",
+ "##initialisation of variables\n",
+ "W= 5 ##kJ\n",
+ "Q= 23 ##kJ\n",
+ "Q1= -50 ##kJ\n",
+ "W1= 0 ##kJ\n",
+ "##CALCULATIONS\n",
+ "E1= Q-W\n",
+ "E2= Q1-W1\n",
+ "E3= -(E1+E2)\n",
+ "W3= -E3\n",
+ "##RESULTS\n",
+ "print '%s %.f %s'%('energy change in process 1 =',E1,'kJ')\n",
+ "print'%s %.f %s'% ('energy change in process 2 = ',E2,'kJ')\n",
+ "print '%s %.f %s'%('energy change in process 3 = ',E3,'kJ')\n",
+ "print '%s %.f %s'%('Work in third process = ',W3,'kJ')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "energy change in process 1 = 18 kJ\n",
+ "energy change in process 2 = -50 kJ\n",
+ "energy change in process 3 = 32 kJ\n",
+ "Work in third process = -32 kJ\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 6 pg 34"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "##calculat the car mileage of given variable\n",
+ "##initialisation of variables\n",
+ "V= 12 ##km/L\n",
+ "##CALCULATIONS\n",
+ "MPG= V*3.7854/1.609\n",
+ "##RESULTS\n",
+ "print'%s %.2f %s'%('car mileage =',MPG,'MPG')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "car mileage = 28.23 MPG\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 7 pg 35"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "##find whether salesman is honest or not\n",
+ "##initialisation of variables\n",
+ "p= 800 ##atm\n",
+ "P= 10000 ##psi\n",
+ "x= 14.696 ##psi/atm\n",
+ "##CALCULATIONS\n",
+ "P1= p*x\n",
+ "##RESULTS\n",
+ "if (P1>P):\n",
+ "\tprint (\"Salesman is honest\")\n",
+ "\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Salesman is honest\n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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