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Diffstat (limited to 'Thermodynamics:_From_concepts_to_applications/Chapter17.ipynb')
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diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter17.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter17.ipynb deleted file mode 100755 index 2d6dc101..00000000 --- a/Thermodynamics:_From_concepts_to_applications/Chapter17.ipynb +++ /dev/null @@ -1,250 +0,0 @@ -{
- "metadata": {
- "name": "",
- "signature": "sha256:0bd1584504a5182c99f46d576a77cfaa07f83a047faf3b55eaafd0cea74518f2"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter17-Ideal solutions"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example1-pg367"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#calculate Total pressure and composition of vapour phases and composition of last drop liquids\n",
- "##initialisation of variables\n",
- "Pa= 40. ##kPa\n",
- "Pb= 50. ##kPa\n",
- "na= 2. ##moles\n",
- "nb= 6. ##moles\n",
- "##CALCULATIONS\n",
- "a= Pb/Pa\n",
- "xa= na/(na+nb)\n",
- "xb= 1.-xa\n",
- "p= xa*Pa+xb*Pb\n",
- "y= (xa*Pa)/p\n",
- "ya= 1.-y\n",
- "Xa= a*xa/(1+(a-1)*xa)\n",
- "Xb= 1.-Xa\n",
- "##RESULTS\n",
- "print'%s %.1f %s'%('Total pressure=',p,'kPa')\n",
- "print'%s %.4f %s'%('composition of vapour phase=',y,'')\n",
- "print'%s %.4f %s'%('composition of vapour phase=',ya,'')\n",
- "print'%s %.4f %s'%('composition of last drop of liquid=',Xa,'')\n",
- "print'%s %.4f %s'%('composition of last drop of liquid=',Xb,'')\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Total pressure= 47.5 kPa\n",
- "composition of vapour phase= 0.2105 \n",
- "composition of vapour phase= 0.7895 \n",
- "composition of last drop of liquid= 0.2941 \n",
- "composition of last drop of liquid= 0.7059 \n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example2-pg371"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\t\n",
- "#calculate pressure of the phase of pure A\n",
- "##initialisation of variables\n",
- "p0= 10. ##Mpa\n",
- "R= 8.314 ##J/mol K\n",
- "T= 30. ##C\n",
- "va= 0.02 ##m^3/kmol\n",
- "xa= 0.98\n",
- "##CALCULATIONS\n",
- "p= p0+(R*(273.15+T)*math.log(xa)/(va*1000.))\n",
- "##RESULTS\n",
- "print'%s %.2f %s'%('Pressure of the phase of pure A=',p,'Mpa')\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Pressure of the phase of pure A= 7.45 Mpa\n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example3-pg373"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#calculate the boiling point elevation\n",
- "##initialisation of variables\n",
- "hfg= 2257.0 ##kJ/kg\n",
- "Tb= 100 ##C\n",
- "R= 8.314 ##J/mol K\n",
- "m2= 10 ##gms\n",
- "M2= 58.5 ##gms\n",
- "m1= 90. ##gms\n",
- "M1= 18. ##gms\n",
- "##CALCULATIONS\n",
- "x2= (m2/M2)/((m2/M2)+(m1/M1))\n",
- "dT= R*math.pow(273.15+Tb,2)*x2/(M1*hfg)\n",
- "##RESULTS\n",
- "print'%s %.3f %s'%(' Boiling point elevation=',dT,'C')\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " Boiling point elevation= 0.942 C\n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example4-pg376"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#calculate Osomatic pressures\n",
- "##initialisation of variables\n",
- "M1= 18.02 ##gms\n",
- "m1= 0.965 ##gms\n",
- "m2= 0.035 ##gms\n",
- "M2= 58.5 ##gms\n",
- "R= 8.314 ##J/mol K\n",
- "M= 18.02 ##kg\n",
- "T= 20. ##C\n",
- "vf= 0.001002 ##m^3\n",
- "x21= 0.021856 ##m^3\n",
- "##CALCULATIONS\n",
- "n1= m1/M1\n",
- "n2= m2/M2\n",
- "x1= n1/(n1+n2)\n",
- "x2= n2/(n2+n1)\n",
- "P= R*(273.15+T)*x2/(M*vf)\n",
- "P1= R*(273.15+T)*x21/(M*vf)\n",
- "##RESULTS\n",
- "print'%s %.1f %s'%('Osmotic pressure=',P,'kpa')\n",
- "print'%s %.1f %s'%('Osmotic pressure=',P1,'kpa')\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Osmotic pressure= 1491.4 kpa\n",
- "Osmotic pressure= 2950.2 kpa\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example5-pg377"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#what is useful work in the process and heat interaction and maximum work and irreversibility\n",
- "##initialisation of variables\n",
- "W= 0.\n",
- "Q= 0.\n",
- "R= 8.314 ##J/mol K\n",
- "T0= 300. ##K\n",
- "x= 5./13.\n",
- "n1= 0.5 ##kmol/s\n",
- "n2= 0.8 ##kmol/s\n",
- "##CALCULATIONS\n",
- "W1= (n1+n2)*R*T0*(x*math.log(1/x)+(1-x)*math.log(1/(1-x)))\n",
- "I= W1\n",
- "##RESULTS\n",
- "print'%s %.f %s'%('useful work of the process=',W,'kW') \n",
- "print'%s %.f %s'%('heat interaction=',Q,'kW') \n",
- "print'%s %.1f %s'%('maximum work=',W1,'kW') \n",
- "print'%s %.1f %s'%('irreversibility=',I,'kW')\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "useful work of the process= 0 kW\n",
- "heat interaction= 0 kW\n",
- "maximum work= 2160.4 kW\n",
- "irreversibility= 2160.4 kW\n"
- ]
- }
- ],
- "prompt_number": 7
- }
- ],
- "metadata": {}
- }
- ]
-}
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