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diff --git a/Theory_Of_Machines_by__B._K._Sarkar/Chapter12.ipynb b/Theory_Of_Machines_by__B._K._Sarkar/Chapter12.ipynb new file mode 100755 index 00000000..6706c05c --- /dev/null +++ b/Theory_Of_Machines_by__B._K._Sarkar/Chapter12.ipynb @@ -0,0 +1,380 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:2fbbfd8e1fae5de695230b7f28341e3abac22cade207682955694bcaba6d0716"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter12-Balancing of reciprocating of masses"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex1-pg310"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "##CHAPTER 12 ILLUSRTATION 1 PAGE NO 310\n",
+ "##TITLE:Balancing of reciprocating of masses\n",
+ "import math\n",
+ "#calculate the magnitude of balance mass required and residual balance error\n",
+ "pi=3.141\n",
+ "N=250.## speed of the reciprocating engine in rpm\n",
+ "s=18.## length of stroke in mm\n",
+ "mR=120.## mass of reciprocating parts in kg\n",
+ "m=70.## mass of revolving parts in kg\n",
+ "r=.09## radius of revolution of revolving parts in m\n",
+ "b=.15## distance at which balancing mass located in m\n",
+ "c=2./3.## portion of reciprocating mass balanced \n",
+ "teeta=30.## crank angle from inner dead centre in degrees\n",
+ "##===============================\n",
+ "B=r*(m+c*mR)/b## balance mass required in kg\n",
+ "w=2.*math.pi*N/60.## angular speed in rad/s\n",
+ "F=mR*w**2.*r*(((1.-c)**2.*(math.cos(teeta/57.3))**2.)+(c**2.*(math.sin(teeta/57.3))**2.))**.5## residual unbalanced forces in N\n",
+ "print'%s %.1f %s %.3f %s'%('Magnitude of balance mass required= ',B,'kg' and 'Residual unbalanced forces= ',F,' N')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Magnitude of balance mass required= 90.0 Residual unbalanced forces= 3263.971 N\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex2-pg310"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "##CHAPTER 12 ILLUSRTATION 2 PAGE NO 310\n",
+ "##TITLE:Balancing of reciprocating of masses\n",
+ "#calculate speed and swaying couples \n",
+ "pi=3.141\n",
+ "g=10.## acceleration due to gravity approximately in m/s**2\n",
+ "mR=240.## mass of reciprocating parts per cylinder in kg\n",
+ "m=300.## mass of rotating parts per cylinder in kg\n",
+ "a=1.8##distance between cylinder centres in m\n",
+ "c=.67## portion of reciprocating mass to be balanced\n",
+ "b=.60## radius of balance masses in m\n",
+ "r=24.## crank radius in cm\n",
+ "R=.8##radius of thread of wheels in m\n",
+ "M=40.\n",
+ "##=======================================\n",
+ "Ma=m+c*mR## total mass to be balanced in kg\n",
+ "mD=211.9## mass of wheel D from figure in kg\n",
+ "mC=211.9##..... mass of wheel C from figure in kg\n",
+ "theta=171.## angular position of balancing mass C in degrees\n",
+ "Br=c*mR/Ma*mC## balancing mass for reciprocating parts in kg\n",
+ "w=(M*g**3./Br/b)**.5## angular speed in rad/s\n",
+ "v=w*R*3600./1000.## speed in km/h\n",
+ "S=a*(1.-c)*mR*w**2*r/2.**.5/100./1000.## swaying couple in kNm\n",
+ "print'%s %.3f %s %.3f %s'%('speed=',v,' kmph'and ' swaying couple=',S,' kNm')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "speed= 86.476 swaying couple= 21.812 kNm\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex3-pg313"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "##CHAPTER 12 ILLUSRTATION 3 PAGE NO 313\n",
+ "##TITLE:Balancing of reciprocating of masses\n",
+ "#calculate hammer blow and tractive effort and swaying couple\n",
+ "import math\n",
+ "pi=3.141\n",
+ "g=10.## acceleration due to gravity approximately in m/s**2\n",
+ "a=.70##distance between cylinder centres in m\n",
+ "r=60.## crank radius in cm\n",
+ "m=130.##mass of rotating parts per cylinder in kg\n",
+ "mR=210.## mass of reciprocating parts per cylinder in kg\n",
+ "c=.67## portion of reciprocating mass to be balanced\n",
+ "N=300.##e2engine speed in rpm\n",
+ "b=.64## radius of balance masses in m\n",
+ "##============================\n",
+ "Ma=m+c*mR## total mass to be balanced in kg\n",
+ "mA=100.44## mass of wheel A from figure in kg\n",
+ "Br=c*mR/Ma*mA## balancing mass for reciprocating parts in kg\n",
+ "H=Br*(2.*math.pi*N/60.)**2*b## hammer blow in N\n",
+ "w=(2.*math.pi*N/60.)## angular speed\n",
+ "T=2**.5*(1.-c)*mR*w**2.*r/2./100.##tractive effort in N\n",
+ "S=a*(1.-c)*mR*w**2.*r/2./2.**.5/100.## swaying couple in Nm\n",
+ "\n",
+ "print'%s %.3f %s %.3f %s %.3f %s'%('Hammer blow=',H,' in N' 'tractive effort= ',T,' in N' 'swaying couple= ',S,' in Nm')\n",
+ "print '%s'%(\"The answer is a bit different due to rounding off error in textbook\")"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Hammer blow= 32975.566 in Ntractive effort= 29018.117 in Nswaying couple= 10156.341 in Nm\n",
+ "The answer is a bit different due to rounding off error in textbook\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex4-pg314"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "##CHAPTER 12 ILLUSRTATION 4 PAGE NO 314\n",
+ "##TITLE:Balancing of reciprocating of masses\n",
+ "import math\n",
+ "#calculate maximum unbalanced primary couples\n",
+ "pi=3.141\n",
+ "mR=900.## mass of reciprocating parts in kg\n",
+ "N=90.## speed of the engine in rpm\n",
+ "r=.45##crank radius in m\n",
+ "cP=.9*mR*(2.*math.pi*N/60.)**2.*r*2.**.5/1000.## maximum unbalanced primary couple in kNm\n",
+ "print'%s %.3f %s'%('maximum unbalanced primary couple=',cP,' k Nm')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "maximum unbalanced primary couple= 45.788 k Nm\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex5-pg315"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "##CHAPTER 12 ILLUSRTATION 5 PAGE NO 315\n",
+ "##TITLE:Balancing of reciprocating of masses\n",
+ "import math\n",
+ "#calculate maximum unbalanced secondary force and with reasons\n",
+ "pi=3.141\n",
+ "mRA=160.## mass of reciprocating cylinder A in kg\n",
+ "mRD=160.## mass of reciprocating cylinder D in kg\n",
+ "r=.05## stroke lenght in m\n",
+ "l=.2## connecting rod length in m\n",
+ "N=450.## engine speed in rpm\n",
+ "##===========================\n",
+ "theta2=78.69## crank angle between A & B cylinders in degrees\n",
+ "mRB=576.88## mass of cylinder B in kg\n",
+ "n=l/r## ratio between connecting rod length and stroke length\n",
+ "w=2.*math.pi*N/60.## angular speed in rad/s\n",
+ "F=mRB*2.*w**2.*r*math.cos((2.*theta2)/57.3)/n\n",
+ "print'%s %.3f %s'%('Maximum unbalanced secondary force=',F,' N in anticlockwise direction thats why - sign')\n",
+ "print '%s'%(\"The answer is a bit different due to rounding off error in textbook\")"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Maximum unbalanced secondary force= -29560.284 N in anticlockwise direction thats why - sign\n",
+ "The answer is a bit different due to rounding off error in textbook\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex6-pg316"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "##CHAPTER 12 ILLUSRTATION 6 PAGE NO 316\n",
+ "##TITLE:Balancing of reciprocating of masses\n",
+ "import math\n",
+ "pi=3.141\n",
+ "rA=.25## stroke length of A piston in m\n",
+ "rB=.25## stroke length of B piston in m\n",
+ "rC=.25## stroke length C piston in m\n",
+ "N=300.## engine speed in rpm\n",
+ "mRL=280.## mass of reciprocating parts in inside cylinder kg\n",
+ "mRO=240.## mass of reciprocating parts in outside cylinder kg\n",
+ "c=.5## portion ofreciprocating masses to be balanced \n",
+ "b1=.5## radius at which masses to be balanced in m\n",
+ "##======================\n",
+ "mA=c*mRO## mass of the reciprocating parts to be balanced foreach outside cylinder in kg\n",
+ "mB=c*mRL## mass of the reciprocating parts to be balanced foreach inside cylinder in kg\n",
+ "B1=79.4## balancing mass for reciprocating parts in kg\n",
+ "w=2.*math.pi*N/60.## angular speed in rad/s\n",
+ "H=B1*w**2*b1## hammer blow per wheel in N\n",
+ "print'%s %.1f %s'%('Hammer blow per wheel= ',H,' N')\n",
+ "print '%s'%(\"The answer is a bit different due to rounding off error in textbook\")"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Hammer blow per wheel= 39182.3 N\n",
+ "The answer is a bit different due to rounding off error in textbook\n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex7-pg318"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "##CHAPTER 12 ILLUSRTATION 7 PAGE NO 318\n",
+ "##TITLE:Balancing of reciprocating of masses\n",
+ "import math\n",
+ "\n",
+ "pi=3.141\n",
+ "mR=300.## reciprocating mass per cylinder in kg\n",
+ "r=.3## crank radius in m\n",
+ "D=1.7## driving wheel diameter in m\n",
+ "a=.7## distance between cylinder centre lines in m\n",
+ "H=40.## hammer blow in kN\n",
+ "v=90.## speed in kmph\n",
+ "##=======================================\n",
+ "R=D/2.## radius of driving wheel in m\n",
+ "w=90.*1000./3600./R## angular velocity in rad/s\n",
+ "##Br*b=69.625*c by mearument from diagram\n",
+ "c=H*1000./(w**2.)/69.625## portion of reciprocating mass to be balanced\n",
+ "T=2.**.5*(1-c)*mR*w**2.*r## variation in tractive effort in N\n",
+ "M=a*(1.-c)*mR*w**2.*r/2.**.5## maximum swaying couple in N-m\n",
+ "print'%s %.3f %s %.3f %s %.3f %s'%('portion of reciprocating mass to be balanced=',c,' ''variation in tractive effort=',T,' N'' maximum swaying couple=',M,' N-m')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "portion of reciprocating mass to be balanced= 0.664 variation in tractive effort= 36980.420 N maximum swaying couple= 12943.147 N-m\n"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex8-pg320"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "##CHAPTER 12 ILLUSRTATION 8 PAGE NO 320\n",
+ "##TITLE:Balancing of reciprocating of masses\n",
+ "import math\n",
+ "pi=3.141\n",
+ "N=1800.## speed of the engine in rpm\n",
+ "r=6.## length of crank in cm\n",
+ "l=24.## length of connecting rod in cm\n",
+ "m=1.5## mass of reciprocating cylinder in kg\n",
+ "##====================\n",
+ "w=2.*math.pi*N/60.## angular speed in rad/s\n",
+ "UPC=.019*w**2.## unbalanced primary couple in N-m\n",
+ "n=l/r## ratio of length of crank to the connecting rod \n",
+ "USC=.054*w**2./n## unbalanced secondary couple in N-m\n",
+ "print'%s %.f %s %.3f %s '%('unbalanced primary couple=',UPC,'N-m' 'unbalanced secondary couple=',USC,' N-m')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "unbalanced primary couple= 675 N-munbalanced secondary couple= 479.663 N-m \n"
+ ]
+ }
+ ],
+ "prompt_number": 8
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
\ No newline at end of file |