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+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:a2f721b4c266424e2bea1224b09de694c0f19e61e65e603f28f9ade00148c17a"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Hour 4: Understanding Data Types and Keywords"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.1, Page No.60"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "c1='A'\n",
+      "c2='a'\n",
+      "\n",
+      "print \"Convert the value of c1 to character : \",c1\n",
+      "print \"Convert the value of c2 to character : \",c2"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Convert the value of c1 to character :  A\n",
+        "Convert the value of c2 to character :  a\n"
+       ]
+      }
+     ],
+     "prompt_number": 1
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.2, Page No.61"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "c1=65\n",
+      "c2=97\n",
+      "\n",
+      "print \"The character that has numeric value of 65 is:\", chr(c1)\n",
+      "print \"The character that has numeric value of 97 is:\", chr(c2)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The character that has numeric value of 65 is: A\n",
+        "The character that has numeric value of 97 is: a\n"
+       ]
+      }
+     ],
+     "prompt_number": 4
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.3, Page No.63"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "c1='A'\n",
+      "c2='a'\n",
+      "print \"The Numeric Value of A is:\",ord(c1)\n",
+      "print \"The Numeric Value of a is:\",ord(c2)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The Numeric Value of A is: 65\n",
+        "The Numeric Value of a is: 97\n"
+       ]
+      }
+     ],
+     "prompt_number": 7
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4.4, Page No.65"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "int_num1=int(32/10)\n",
+      "flt_num1=float(32/10)\n",
+      "int_num2=int(32.0/10)\n",
+      "flt_num2=float(32.0/10)\n",
+      "int_num3=int(32/10.0)\n",
+      "flt_num3=float(32/10.0)\n",
+      "\n",
+      "print \"The integer divis. of 32/10 is\",int_num1\n",
+      "print \"The floating-point divis. of 32/10 is\",flt_num1\n",
+      "\n",
+      "print \"The integer divis. of 32.0/10 is\",int_num2\n",
+      "print \"The floating-point divis. of 32.0/10 is\",flt_num2\n",
+      "\n",
+      "print \"The integer divis. of 32/10.0 is\",int_num3\n",
+      "print \"The floating-point divis. of 32/10.0 is\",flt_num3"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The integer divis. of 32/10 is 3\n",
+        "The floating-point divis. of 32/10 is 3.0\n",
+        "The integer divis. of 32.0/10 is 3\n",
+        "The floating-point divis. of 32.0/10 is 3.2\n",
+        "The integer divis. of 32/10.0 is 3\n",
+        "The floating-point divis. of 32/10.0 is 3.2\n"
+       ]
+      }
+     ],
+     "prompt_number": 10
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file