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author | hardythe1 | 2015-01-30 12:30:05 +0530 |
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committer | hardythe1 | 2015-01-30 12:30:05 +0530 |
commit | 62aa228e2519ac7b7f1aef53001f2f2e988a6eb1 (patch) | |
tree | 7b632b21341f832c3d3b1352dabceaefb36c9a7b /Teach_Yourself_C_in_24_Hours/hour4.ipynb | |
parent | 9add422993fb2649287260bc91d429a07d1810d5 (diff) | |
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1 files changed, 164 insertions, 0 deletions
diff --git a/Teach_Yourself_C_in_24_Hours/hour4.ipynb b/Teach_Yourself_C_in_24_Hours/hour4.ipynb new file mode 100755 index 00000000..7496626d --- /dev/null +++ b/Teach_Yourself_C_in_24_Hours/hour4.ipynb @@ -0,0 +1,164 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:a2f721b4c266424e2bea1224b09de694c0f19e61e65e603f28f9ade00148c17a"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Hour 4: Understanding Data Types and Keywords"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 4.1, Page No.60"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "c1='A'\n",
+ "c2='a'\n",
+ "\n",
+ "print \"Convert the value of c1 to character : \",c1\n",
+ "print \"Convert the value of c2 to character : \",c2"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Convert the value of c1 to character : A\n",
+ "Convert the value of c2 to character : a\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 4.2, Page No.61"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "c1=65\n",
+ "c2=97\n",
+ "\n",
+ "print \"The character that has numeric value of 65 is:\", chr(c1)\n",
+ "print \"The character that has numeric value of 97 is:\", chr(c2)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The character that has numeric value of 65 is: A\n",
+ "The character that has numeric value of 97 is: a\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 4.3, Page No.63"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "c1='A'\n",
+ "c2='a'\n",
+ "print \"The Numeric Value of A is:\",ord(c1)\n",
+ "print \"The Numeric Value of a is:\",ord(c2)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The Numeric Value of A is: 65\n",
+ "The Numeric Value of a is: 97\n"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 4.4, Page No.65"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "int_num1=int(32/10)\n",
+ "flt_num1=float(32/10)\n",
+ "int_num2=int(32.0/10)\n",
+ "flt_num2=float(32.0/10)\n",
+ "int_num3=int(32/10.0)\n",
+ "flt_num3=float(32/10.0)\n",
+ "\n",
+ "print \"The integer divis. of 32/10 is\",int_num1\n",
+ "print \"The floating-point divis. of 32/10 is\",flt_num1\n",
+ "\n",
+ "print \"The integer divis. of 32.0/10 is\",int_num2\n",
+ "print \"The floating-point divis. of 32.0/10 is\",flt_num2\n",
+ "\n",
+ "print \"The integer divis. of 32/10.0 is\",int_num3\n",
+ "print \"The floating-point divis. of 32/10.0 is\",flt_num3"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The integer divis. of 32/10 is 3\n",
+ "The floating-point divis. of 32/10 is 3.0\n",
+ "The integer divis. of 32.0/10 is 3\n",
+ "The floating-point divis. of 32.0/10 is 3.2\n",
+ "The integer divis. of 32/10.0 is 3\n",
+ "The floating-point divis. of 32/10.0 is 3.2\n"
+ ]
+ }
+ ],
+ "prompt_number": 10
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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