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+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:7d21feb46ef90fdbbfbaad4563a2c375000b58700df6f4805ecd9fd8506686a5"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 8:Shear Stresses in Beams"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Problem 8.6,page no.355"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "from __future__ import division\n",
+      "import math\n",
+      "#Given\n",
+      "#Variable declaration\n",
+      "D=100           #Diameter in mm\n",
+      "R=D/2           #Radius in mm\n",
+      "F=5*10**3       #Shear force in N\n",
+      "y=40            #given distance from N.A. in mm\n",
+      "\n",
+      "#Calculation\n",
+      "#case(i):Average shear stress \n",
+      "A=math.pi*R**2\n",
+      "tau_avg=round(F/A,4)\n",
+      "#case(ii):Maximum shear stress for a circular section\n",
+      "tau_max=round(4/3*tau_avg,4)\n",
+      "#case(iii):Shear stress at a distance 40mm from N.A.\n",
+      "I=math.pi/64*D**4\n",
+      "tau=float(str(F/(3*I)*(R**2-y**2))[:6])\n",
+      "\n",
+      "#Result\n",
+      "print \"Average shear stress =\",tau_avg,\"N/mm^2\"\n",
+      "print \"Maximum shear stress =\",tau_max,\"N/mm^2\"\n",
+      "print \"Shear stress at a distance 40mm from N.A. =\",tau,\"N/mm^2\"\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Average shear stress = 0.6366 N/mm^2\n",
+        "Maximum shear stress = 0.8488 N/mm^2\n",
+        "Shear stress at a distance 40mm from N.A. = 0.3055 N/mm^2\n"
+       ]
+      }
+     ],
+     "prompt_number": 1
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Problem 8.12,page no.369"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "from __future__ import division\n",
+      "import math\n",
+      "\n",
+      "#Given\n",
+      "#Variable declaration\n",
+      "F=50*10**3              #Shear force in N\n",
+      "b=250                   #Base width in mm\n",
+      "h=200                   #height in mm\n",
+      "\n",
+      "#Calculation\n",
+      "tau_max=int((3*F)/(b*h))     #Maximum shear stress in N/sq.mm\n",
+      "tau=round((8*F)/(3*b*h),2)   #Shear stress at N.A. in N/sq.mm\n",
+      "\n",
+      "#Result\n",
+      "print \"Maximum shear stress =\",tau_max,\"N/mm^2\"\n",
+      "print \"Shear stress at N.A. =\",tau,\"N/mm^2\"\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Maximum shear stress = 3 N/mm^2\n",
+        "Shear stress at N.A. = 2.67 N/mm^2\n"
+       ]
+      }
+     ],
+     "prompt_number": 3
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [],
+     "language": "python",
+     "metadata": {},
+     "outputs": []
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file