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Diffstat (limited to 'Quantum_mechanics_by_M.C.Jain/chapter4.ipynb')
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diff --git a/Quantum_mechanics_by_M.C.Jain/chapter4.ipynb b/Quantum_mechanics_by_M.C.Jain/chapter4.ipynb deleted file mode 100755 index 214047e7..00000000 --- a/Quantum_mechanics_by_M.C.Jain/chapter4.ipynb +++ /dev/null @@ -1,329 +0,0 @@ -{
- "metadata": {
- "name": "",
- "signature": "sha256:b24ac6268abeb9e8ceafeb2b8fcac357229b810faa15684921ddb633803d3d99"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 4 Wave nature of matter and the need for a wave function"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.1 Page no 58"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given \n",
- "V=100 #volts\n",
- "\n",
- "#Calculation \n",
- "import math\n",
- "wavelength=12.3/(math.sqrt(V))\n",
- "\n",
- "#Result\n",
- "print\"de Broglie wavelength of electrons \", wavelength,\"A\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "de Broglie wavelength of electrons 1.23 A\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.2 Page no 58"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "K=100 #ev\n",
- "h=6.63*10**-34\n",
- "m=9.1*10**-31\n",
- "e=1.6*10**-19\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "v=h/(math.sqrt(2*m*K*e))\n",
- "\n",
- "#Result\n",
- "print\"de broglie wavelength of electrons \",round(v*10**10,1),\"A\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "de broglie wavelength of electrons 1.2 A\n"
- ]
- }
- ],
- "prompt_number": 109
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.3 Page no 58"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "m=1.675*10**-27 #mass of neutron in kg\n",
- "v=1.4*10**-10 #de broglie wavelength in m\n",
- "h=6.63*10**-34 #Js\n",
- "\n",
- "#Calculation \n",
- "K=(h**2/(2*m*(v**2)))/(1.6*10**-19)\n",
- "\n",
- "#Result\n",
- "print\"Kinetic energy of neutron is \", round(K*10**2,2),\"*10**-2 ev\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Kinetic energy of neutron is 4.18 *10**-2 ev\n"
- ]
- }
- ],
- "prompt_number": 113
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.4 Page no 58"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "E=-3.4 #total energy in ev\n",
- "h=6.63*10**-34 #Js\n",
- "m=9.1*10**-31\n",
- "e=1.6*10**-19 \n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "K=-E\n",
- "v=h/(math.sqrt(2*m*K*e))\n",
- "\n",
- "#Result \n",
- "print\"(a) Kinetic energy \",K,\"ev\"\n",
- "print\"(b) de broglie wavelength of the electron is \",round(v*10**10,3),\"A\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) Kinetic energy 3.4 ev\n",
- "(b) de broglie wavelength of the electron is 6.663 A\n"
- ]
- }
- ],
- "prompt_number": 64
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.5 Page no 59"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "m=1.672*10**-27 #mass of neutron in kg\n",
- "h=6.60*10**-34 #Js\n",
- "v=1.0*10**-10 #de broglie wavelength in m\n",
- "\n",
- "#Calculation\n",
- "K=(h**2/(2.0*m*v**2))/(1.6*10**-19)\n",
- "\n",
- "#Result\n",
- "print\"Kinetic energy of a neutron is \", round(K*10**2,2),\"*10**-2 ev\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Kinetic energy of a neutron is 8.14 *10**-2 ev\n"
- ]
- }
- ],
- "prompt_number": 116
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.6 Page no 59"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "m=10*10**-3 #mass of a ball in kg \n",
- "v=1 #Speed in m/s\n",
- "h=6.63*10**-34 #Js\n",
- "\n",
- "#Calculation\n",
- "V=h/(m*v) #Wavelength\n",
- "\n",
- "#Result\n",
- "print \"de broglie wavelength is \",V,\"m\"\n",
- "print\"This wavelength is negligible compared to the dimensions of the ball. therefore its effect can not be observed.\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "de broglie wavelength is 6.63e-32 m\n",
- "This wavelength is negligible compared to the dimensions of the ball. therefore its effect can not be observed.\n"
- ]
- }
- ],
- "prompt_number": 87
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.7 Page no 59"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "T=27 #temperature in degree c\n",
- "K=1.38*10**-23 #boltzmann constant in J/K\n",
- "h=6.63*10**-34 #Js\n",
- "m=1.67*10**-27\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "T1=T+273\n",
- "v=h/(math.sqrt(2*m*K*T1))\n",
- "\n",
- "#Result\n",
- "print\"de broglie wavelength is \",round(v*10**10,2),\"A\"\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "de broglie wavelength is 1.78 A\n"
- ]
- }
- ],
- "prompt_number": 94
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.10 Page no 64"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "V=100 #ev\n",
- "a=10 #degree\n",
- "n=1\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "v=12.3/(math.sqrt(V)) #De broglie wavelength\n",
- "d=v/(2*math.sin(a*3.14/180.0))\n",
- "n=(2*d)/v\n",
- "\n",
- "#Result\n",
- "print\"(a) Spacing between the crystal plane is \", round(d,2),\"A\"\n",
- "print\"(b) Peaks in the interference pattern is \",round(n,2)\n",
- "print\"the largest possible value of n is 5\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) Spacing between the crystal plane is 3.54 A\n",
- "(b) Peaks in the interference pattern is 5.76\n",
- "the largest possible value of n is 5\n"
- ]
- }
- ],
- "prompt_number": 117
- }
- ],
- "metadata": {}
- }
- ]
-}
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