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diff --git a/Quantum_mechanics_by_M.C.Jain/chapter2.ipynb b/Quantum_mechanics_by_M.C.Jain/chapter2.ipynb deleted file mode 100755 index 3d83df64..00000000 --- a/Quantum_mechanics_by_M.C.Jain/chapter2.ipynb +++ /dev/null @@ -1,710 +0,0 @@ -{
- "metadata": {
- "name": "",
- "signature": "sha256:46bc70330d4213802afb03e252b2ad32eb9319ed4cc2a32fe2c16df97a5f1978"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 2 Particle nature of Radiation; The origin of Quantum theory"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.2 Page no-12"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "E=40 #W\n",
- "lembda=6000*10**-10 #m\n",
- "h=6.63*10**-34 #Js\n",
- "c=3*10**8 #m/s\n",
- "\n",
- "#Calculation\n",
- "n=(E*lembda)/(h*c)\n",
- "\n",
- "#Result\n",
- "print\"No. of photons emitted per second are given by \",round(n*10**-19,2),\"*10**19\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "No. of photons emitted per second are given by 12.07 *10**19\n"
- ]
- }
- ],
- "prompt_number": 27
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.3 Page no-12"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "a=3.2 #ev\n",
- "energy=3.8 #ev\n",
- "e=1.6*10**-19\n",
- "\n",
- "#Calculation\n",
- "c=energy-a\n",
- "Energy=c*e\n",
- "\n",
- "#Result\n",
- "print\"Kinetic energy of the photoelectron is given by \",Energy,\"Joule\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Kinetic energy of the photoelectron is given by 9.6e-20 Joule\n"
- ]
- }
- ],
- "prompt_number": 31
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.4 Page no-12"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "W=3.45 #ev\n",
- "h=6.63*10**-34 #Js\n",
- "c=3*10**8 #m/s\n",
- "e=1.6*10**-19\n",
- "\n",
- "#Calculation\n",
- "lembda=(h*c)/(W*e)\n",
- "\n",
- "#Result\n",
- "print\"Maximum wavelength of photon is \",round(lembda*10**10,0),\"A\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Maximum wavelength of photon is 3603.0 A\n"
- ]
- }
- ],
- "prompt_number": 193
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.5 Page no-12"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "W=3 #ev\n",
- "h=6.63*10**-34\n",
- "e=1.6*10**-19\n",
- "lembda=3.0*10**-7 #m\n",
- "c=3*10**8 #m/s\n",
- "\n",
- "#Calculation\n",
- "v0=(W*e)/h\n",
- "v=c/lembda\n",
- "E=h*(v-v0)\n",
- "E1=(h*(v-v0))/(1.6*10**-19)\n",
- "V0=E/e\n",
- "\n",
- "#Result\n",
- "print\"(a) Threshold frequency \",round(v0*10**-15,2),\"*10**15 HZ\"\n",
- "print\"(b) Maximum energy of photoelectron \",round(E1,2),\"eV\"\n",
- "print\"(c) Stopping potential \",round(V0,2),\"V\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) Threshold frequency 0.72 *10**15 HZ\n",
- "(b) Maximum energy of photoelectron 1.14 eV\n",
- "(c) Stopping potential 1.14 V\n"
- ]
- }
- ],
- "prompt_number": 197
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.6 Page no-13"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "v0=6*10**14 #s**-1\n",
- "h=6.63*10**-34\n",
- "e=1.6*10**-19\n",
- "V0=3\n",
- "\n",
- "#Calculaton\n",
- "W=h*v0\n",
- "W0=(h*v0)/e\n",
- "V=(e*V0+h*v0)/h\n",
- "\n",
- "#Result \n",
- "print\"work function is given by \",round(W0,3),\"ev\"\n",
- "print\"frequency is given by \",round(V*10**-15,2),\"*10**15 s-1\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "work function is given by 2.486 ev\n",
- "frequency is given by 1.32 *10**15 s-1\n"
- ]
- }
- ],
- "prompt_number": 88
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.7 Page no 13"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "lembda=6800.0*10**-10 #m\n",
- "h=6.6*10**-34\n",
- "W=2.3 #ev\n",
- "c=3*10**8 #m/s\n",
- "\n",
- "#Calculation\n",
- "E=((h*c)/lembda)/1.6*10**-19\n",
- "\n",
- "#Result\n",
- "print\"Energy is \",round(E*10**38,2),\"ev\"\n",
- "print\"since the energy of incident photon is less then the work function of Na, photoelecrticemession is not possible with the given light.\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Energy is 1.82 ev\n",
- "since the energy of incident photon is less then the work function of Na, photoelecrticemession is not possible with the given light.\n"
- ]
- }
- ],
- "prompt_number": 200
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.8 Page no 14"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "lembda=3500*10**-10 #m\n",
- "h=6.6*10**-34\n",
- "c=3*10**8 #m/s\n",
- "\n",
- "#calculation \n",
- "E=((h*c)/lembda)/1.6*10**-19\n",
- "\n",
- "#Result\n",
- "print\"Energy is \" ,round(E*10**38,2),\"ev\"\n",
- "print\"1.9 ev < E < 4.2 ev,only metal B will yield photoelectrons\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Energy is 3.54 ev\n",
- "1.9 ev < E < 4.2 ev,only metal B will yield photoelectrons\n"
- ]
- }
- ],
- "prompt_number": 201
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.9 Page no 14"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "lembda=6.2*10**-6\n",
- "W=0.1 #ev\n",
- "h=6.6*10**-34 #Js\n",
- "c=3*10**8 #m/s\n",
- "e=1.6*10**-19\n",
- "\n",
- "#Calculation\n",
- "E=((h*c)/(lembda*e))-W\n",
- "\n",
- "#Result\n",
- "print\"Maximum kinetic energy of photoelectron \",round(E,1),\"ev\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Maximum kinetic energy of photoelectron 0.1 ev\n"
- ]
- }
- ],
- "prompt_number": 112
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.10 Page no 14"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#given\n",
- "e=1.60*10**-19 #C\n",
- "slope=4.12*10**-15 #Vs\n",
- "\n",
- "#Calculation\n",
- "h=slope*e\n",
- "\n",
- "#Result\n",
- "print\"Value of plank's constant \",h,\"Js\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Value of plank's constant 6.592e-34 Js\n"
- ]
- }
- ],
- "prompt_number": 114
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.11 Page no 15"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "W=2.26*1.6*10**-19 #ev\n",
- "v=10**6 #m/s\n",
- "m=9*10**-31\n",
- "\n",
- "#Calculation\n",
- "V=((1/2.0)*m*v**2+W)/h\n",
- "\n",
- "#Result\n",
- "print\"frequency of incident radiation \",round(V*10**-15,2),\"*10**15 HZ\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "frequency of incident radiation 1.23 *10**15 HZ\n"
- ]
- }
- ],
- "prompt_number": 118
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.12 Page no 15"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#given\n",
- "V1=.82 #volts\n",
- "V2=1.85 #volts\n",
- "lembda1=4.0*10**-7 #m\n",
- "lembda2=3.0*10**-7\n",
- "e=1.6*10**-19\n",
- "c=3.0*10**8 #m/s\n",
- "\n",
- "#Calculation\n",
- "lembda=(1/lembda2)-(1/lembda1)\n",
- "h=(e*(V2-V1))/(c*lembda)\n",
- "\n",
- "#Result\n",
- "print\"(a) plank's constant \",h,\"Js\"\n",
- "print\"(b) no, because the stopping potentialdepends only on the wavelength of light and not on its intensity.\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) plank's constant 6.592e-34 Js\n",
- "(b) no, because the stopping potentialdepends only on the wavelength of light and not on its intensity.\n"
- ]
- }
- ],
- "prompt_number": 202
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.13 Page no 16"
- ]
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "\n"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#given\n",
- "h=6.62*10**-34 #Js\n",
- "c=3*10**8 #m/s\n",
- "lembda=4560.0*10**-10 #m\n",
- "p=1*10**-3 #W\n",
- "a=0.5/100\n",
- "e=1.6*10**-19\n",
- "\n",
- "#calculation\n",
- "E=(h*c)/lembda\n",
- "N=p/E #Number of photons incedent on the surface\n",
- "n=N*a\n",
- "I=n*e\n",
- "\n",
- "#result\n",
- "print\"Photoelectric current \",round(I*10**6,2),\"*10**-6 A\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Photoelectric current 1.84 *10**-6 A\n"
- ]
- }
- ],
- "prompt_number": 131
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.14 Page no 22"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#given\n",
- "m0=9.1*10**-31 #Kg\n",
- "c=3*10**8 #m/s\n",
- "h=6.6*10**-34 #Js\n",
- "v1=2.0*10**-10 #m\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "v= (h/(m0*c))*(1-(math.cos(90))*3.14/180.0)\n",
- "v2=v+v1\n",
- "v0=v2-v1\n",
- "E=(h*c*(v0))/(v1*v2)\n",
- "b=(1/(math.sin(90)*3.14/180.0))*((v2*10**-10/v1)-math.cos(90)*3.14/180.0)\n",
- "angle=3.14/2.0-math.atan(b)\n",
- "\n",
- "#Result\n",
- "print \"(a) the wavelength of scattered photon is \",round(v2*10**10,3),\"A\"\n",
- "print\"(b) The energy of recoil electron is \",round(E*10**17,2),\"*10**-17 J\"\n",
- "print\"(c) angle at which the recoil electron appears \",round(angle,2),\"degree\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) the wavelength of scattered photon is 2.024 A\n",
- "(b) The energy of recoil electron is 1.19 *10**-17 J\n",
- "(c) angle at which the recoil electron appears 1.11 degree\n"
- ]
- }
- ],
- "prompt_number": 278
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.15 Page no 23"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given \n",
- "E=0.9 #Mev\n",
- "a=120 #degree\n",
- "m=9.1*10**-31 #Kg\n",
- "c=3*10**8 #m/s\n",
- "\n",
- "#calculation\n",
- "b=((m*c**2)/1.6*10**-19)*10**32\n",
- "energy=E/(1+2*(E/b)*(3/4.0))\n",
- "\n",
- "#Result\n",
- "print \"energy of scattered photon \",round(energy,3),\"Mev\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "energy of scattered photon 0.247 Mev\n"
- ]
- }
- ],
- "prompt_number": 142
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.16 Page no 24"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "v1=2.000*10**-10 #m\n",
- "v2=2.048*10**-10 #m\n",
- "a=180 #degree\n",
- "a1=60 #degree\n",
- "h=6.6*10**-34\n",
- "c=3*10**8\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "b=(v2-v1)/(1-math.cos(a*3.14/180.0))\n",
- "V=v1+b*(1-math.cos(60*3.14/180.0))\n",
- "E=(h*c*(V-v1))/(V*v1)\n",
- "\n",
- "#Result\n",
- "print\"(a) wavelength of radiation scattered at an angle of 60 degree \",round(V*10**10,3),\"A\"\n",
- "print \"(b) Energy of the recoiul electron is \",round(E*10**18,2),\"*10**-18 J\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) wavelength of radiation scattered at an angle of 60 degree 2.012 A\n",
- "(b) Energy of the recoiul electron is 5.9 *10**-18 J\n"
- ]
- }
- ],
- "prompt_number": 277
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.17 Page no 24"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "E=4*10**3*1.6*10**-19\n",
- "m0=9.1*10**-31\n",
- "b=6.4*10**-16\n",
- "d=102.39*10**-16\n",
- "h=6.3*10**-34\n",
- "c=3*10**8\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "p=math.sqrt(2*m0*E)\n",
- "d=b+d\n",
- "lembda=(2*h*c)/d\n",
- "\n",
- "#Result\n",
- "print\"Wavelength of incident photon is \", round(lembda*10**10,2),\"A\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Wavelength of incident photon is 0.35 A\n"
- ]
- }
- ],
- "prompt_number": 233
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.19 Page no 26"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "E=1.02 #Mev\n",
- "b=0.51\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "alpha=E/b\n",
- "a=1/(math.sqrt(2*(alpha+2)))\n",
- "angle=2*(math.asin(a)*180/3.14)\n",
- "e=E/(1.0+alpha*(1-(math.cos(angle*3.14/180.0))))\n",
- "\n",
- "#Result\n",
- "print\"(a) Angle for symmetric scattering is \", round(angle,1),\"degree\"\n",
- "print \"(b) energy of the scattered photon is \",round(e,2),\"Mev\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) Angle for symmetric scattering is 41.4 degree\n",
- "(b) energy of the scattered photon is 0.68 Mev\n"
- ]
- }
- ],
- "prompt_number": 263
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file |