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Diffstat (limited to 'Principles_of_Power_System/chapter26_1.ipynb')
| -rw-r--r-- | Principles_of_Power_System/chapter26_1.ipynb | 224 |
1 files changed, 0 insertions, 224 deletions
diff --git a/Principles_of_Power_System/chapter26_1.ipynb b/Principles_of_Power_System/chapter26_1.ipynb deleted file mode 100644 index d4334600..00000000 --- a/Principles_of_Power_System/chapter26_1.ipynb +++ /dev/null @@ -1,224 +0,0 @@ -{
- "metadata": {
- "name": "",
- "signature": "sha256:260bb8beffe2e4d2155fdaec0c7462f8cf5127d60c79f0bddb469ea9aad62673"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 26: Neutral Grounding"
- ]
- },
- {
- "cell_type": "heading",
- "level": 3,
- "metadata": {},
- "source": [
- "Example 26.1, Page Number: 599"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "from __future__ import division\n",
- "import math\n",
- "\n",
- "#Variable declaration:\n",
- "f = 50 #Supply frequency(Hz)\n",
- "C = 4.5*10**-6 #Line to earth capacitance(F)\n",
- "\n",
- "\n",
- "#Calculation:\n",
- "XL = 1/(3*2*math.pi*f*C) #ohm\n",
- "\n",
- "\n",
- "#Result:\n",
- "print \"The reactance of Peterson coil is\",round(XL,1),\"ohm\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The reactance of Peterson coil is 235.8 ohm\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 3,
- "metadata": {},
- "source": [
- "Example 26.2, Page Number: 599"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "from __future__ import division\n",
- "import math\n",
- "\n",
- "#Variable declaration:\n",
- "l = 200 #length of transmission line(km)\n",
- "f = 50 #Supply frequency(Hz)\n",
- "c = 0.02*10**-6 #Line to earth capacitance(F/km)\n",
- "V = 230 #voltage rating of line(kV)\n",
- "\n",
- "\n",
- "#Calculation:\n",
- "C = c*l #capacitance of coil(F)\n",
- "L = round(1/(3*(2*3.14*f)**2*C),2) #Required inductance of Peterson coil(H)\n",
- "Vph = round(V*1000/1.732) #Voltage across Peterson coil(kV)\n",
- "IF = math.ceil(Vph/(2*3.13*f*L)) #Current through Peterson coil(A)\n",
- "kVA = Vph*IF/1000 #Rating of Peterson coil\n",
- "\n",
- "\n",
- "\n",
- "#Calculation:\n",
- "print \"Inductance of Peterson coil is\",L,\"H\"\n",
- "print \"Rating of Peterson coil is\",round(kVA),\"kVA\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Inductance of Peterson coil is 0.85 H\n",
- "Rating of Peterson coil is 66397.0 kVA\n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 3,
- "metadata": {},
- "source": [
- "Example 26.3, Page Number: 600"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "from __future__ import division\n",
- "import math\n",
- "\n",
- "#Variable declaration:\n",
- "f = 50 #fequency of supply(Hz)\n",
- "C = 1.2*10**-6 #line-to-earth capacitance(F)\n",
- "\n",
- "\n",
- "#Calculation:\n",
- "#(i) To neutralize capacitance of 100% of the length of the line,\n",
- "#Inductive reactance of the coilis given by\n",
- "XL1 = 1/(3*2*math.pi*f*C) #ohm\n",
- "\n",
- "#(ii) To neutralize capacitance of 90% of the length of the line,\n",
- "#Inductive reactance of the coilis given by\n",
- "XL2 = 1/(3*2*math.pi*f*0.9*C) #ohm\n",
- "\n",
- "\n",
- "#(iii) To neutralize capacitance of 80% of the length of the line,\n",
- "#Inductive reactance of the coilis given by\n",
- "XL3 = 1/(3*2*math.pi*f*0.8*C) #ohm\n",
- "\n",
- "\n",
- "#Result:\n",
- "print \"(i) Inductive reactance of the coil to neutralize capacitance\"\n",
- "print \" of 100% of the length of the line is\",round(XL1,2),\"ohm\"\n",
- "print \"\\n(ii) Inductive reactance of the coil to neutralize capacitance\"\n",
- "print \" of 100% of the length of 90% of the line is\",round(XL2,2),\"ohm\"\n",
- "print \"\\n(iii)Inductive reactance of the coil to neutralize capacitance\"\n",
- "print \" of 100% of the length of 80% of the line is\",round(XL3,2),\"ohm\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(i) Inductive reactance of the coil to neutralize capacitance\n",
- " of 100% of the length of the line is 884.19 ohm\n",
- "\n",
- "(ii) Inductive reactance of the coil to neutralize capacitance\n",
- " of 100% of the length of 90% of the line is 982.44 ohm\n",
- "\n",
- "(iii)Inductive reactance of the coil to neutralize capacitance\n",
- " of 100% of the length of 80% of the line is 1105.24 ohm\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 3,
- "metadata": {},
- "source": [
- "Example 26.4, Page Number: 600"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "from __future__ import division\n",
- "import math\n",
- "\n",
- "#Variable declaration:\n",
- "r = 0.01 #radius of conductor(m)\n",
- "d = 4 #conductor spacing(m)\n",
- "V = 132 #voltage of the line(kV)\n",
- "f = 50 #supply frequency(Hz)\n",
- "l = 200 #line length(km)\n",
- "\n",
- "\n",
- "#Calculation:\n",
- "c = round(2*math.pi*8.885/math.log(d/r),1)*10**-12 #capacitance per unit length(F/m)\n",
- "C = c*l*1000 #Capacitance between phase and earth for 200 km line(F)\n",
- "L = round(1/(3*(2*math.pi*f)**2*C),2) #required inductance L of the arc suppression coil(H)\n",
- "IF = V*1000/(10*math.ceil(3**0.5*2*math.pi*f*L/10)) #Current through the coil(A)\n",
- "kVA = V/3**0.5*IF #kVA\n",
- "\n",
- "\n",
- "#Result:\n",
- "print \"The inductance of the coil is\",L,\"H\"\n",
- "print \"Rating of the coil is\",round(kVA),\"kVA\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The inductance of the coil is 1.82 H\n",
- "Rating of the coil is 10060.0 kVA\n"
- ]
- }
- ],
- "prompt_number": 6
- }
- ],
- "metadata": {}
- }
- ]
-}
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