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Diffstat (limited to 'Principles_Of_Foundation_Engineering/Chapter10_2.ipynb')
| -rwxr-xr-x | Principles_Of_Foundation_Engineering/Chapter10_2.ipynb | 211 |
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diff --git a/Principles_Of_Foundation_Engineering/Chapter10_2.ipynb b/Principles_Of_Foundation_Engineering/Chapter10_2.ipynb deleted file mode 100755 index 3af11efd..00000000 --- a/Principles_Of_Foundation_Engineering/Chapter10_2.ipynb +++ /dev/null @@ -1,211 +0,0 @@ -{
- "metadata": {
- "name": "",
- "signature": "sha256:54ddb8c76d55d78e9f237ddb7f5823ac10a3585adf1b3932a3b8cc9352fd8e76"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 10:Braced Cuts"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex10.1: pg-511"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#example 10.1 : \n",
- "\n",
- "Gamma=18.0;\n",
- "H=7.0;\n",
- "sigmaa=0.3*Gamma*H;\n",
- "print\"maximum pressure intensity in kN/m^2 is\",sigmaa ;\n",
- "#partb\n",
- "A=54.02;\n",
- "B1=1.0/2*1.75*37.8+37.8*1.75-A;\n",
- "B2=45.2;\n",
- "C=54.02;\n",
- "s=3.0; #spacing\n",
- "Pa=C*s;\n",
- "print \"strut loads in kN is\",Pa\n",
- "Pb=(B1+B2)*s;\n",
- "print \"strut loads in kN is\",Pb\n",
- "Pc=C*s;\n",
- "print \"strut loads in kN is\", Pc\n",
- "#partc\n",
- "Me=45.2*1.196-37.8*1.196*1.196/2;#Me=Mmax\n",
- "Sall=170e3;#sigmaall\n",
- "S=Me/Sall;\n",
- "print \"section modulus in m^3/m is \",round(S,7)\n",
- "#partd\n",
- "Mmax=(B1+B2)*s**2.0/8;\n",
- "S=Mmax/Sall;\n",
- "print\"section modulus in m^3/m is\",round(S,6)\n",
- "\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "maximum pressure intensity in kN/m^2 is 37.8\n",
- "strut loads in kN is 162.06\n",
- "strut loads in kN is 271.215\n",
- "strut loads in kN is 162.06\n",
- "section modulus in m^3/m is 0.000159\n",
- "section modulus in m^3/m is 0.000598\n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex10.2:pg-514"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#example 10.2\n",
- "\n",
- "import math\n",
- "phi=35.0;\n",
- "Gamma=17.0; # kN/m^3\n",
- "s=4; #spacing in m\n",
- "H=9;\n",
- "Ka=(math.tan(45*(math.pi/180)-35*(math.pi/(180.0*2))))**2\n",
- "sigma=0.65*Gamma*Ka*H\n",
- "A=sigma*5*5.0/6;\n",
- "B1=sigma*5-A;\n",
- "C=sigma*4*4/6.0; \n",
- "B2=sigma*s-C;\n",
- "Pa=A*s;\n",
- "Pb=(B1+B2)*s;\n",
- "Pc=C*s;\n",
- "print \"strut loads at A in kN is\",round(Pa,2)\n",
- "\n",
- "print \"strut loads at B in kN is\",round(Pb,2)\n",
- "\n",
- "print \"strut loads at C in kN is\",round(Pc,2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "strut loads at A in kN is 449.17\n",
- "strut loads at B in kN is 233.57\n",
- "strut loads at C in kN is 287.47\n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex10.3:pg-523"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#example 10.3\n",
- "\n",
- "import math\n",
- "q=0;\n",
- "Gamma=17; # in KN/m^3\n",
- "B=3.0 # in meter\n",
- "L=20; # in meter\n",
- "c=30;# in KN/m^3\n",
- "T=1.5;# in meter\n",
- "H=5.5;# in meter\n",
- "B1=B/2;#B'\n",
- "B11=T*math.sqrt(2);#B''\n",
- "FS=(5.14*c*(1+B11*0.2/L)+c*H/B1)/(Gamma*H+q) # from equation of factor of safety\n",
- "print\"factor of safety is\",round(FS,2)\n",
- "\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "factor of safety is 2.86\n"
- ]
- }
- ],
- "prompt_number": 18
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex10.4:pg-529"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#example 10.4\n",
- "\n",
- "\n",
- "L1=5; # in meter\n",
- "L2=4;# in meter\n",
- "B=5;# in meter\n",
- "h=4.5;# in meter\n",
- "icr=1 #\n",
- "iexit= 0.54*h/L2\n",
- "FOS=icr/iexit # Factor of safety\n",
- "print \"The Factory of safety is\",round(FOS,3)\n",
- "\n",
- "\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The Factory of safety is 1.646\n"
- ]
- }
- ],
- "prompt_number": 23
- }
- ],
- "metadata": {}
- }
- ]
-}
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