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diff --git a/Principles_Of_Foundation_Engineering/Chapter04_1.ipynb b/Principles_Of_Foundation_Engineering/Chapter04_1.ipynb deleted file mode 100755 index 1d75ed9f..00000000 --- a/Principles_Of_Foundation_Engineering/Chapter04_1.ipynb +++ /dev/null @@ -1,373 +0,0 @@ -{
- "metadata": {
- "name": "",
- "signature": "sha256:7e16b5ec29439d0d7eaa54a0826b64a36c559ed79f17d130c42f4478805c682f"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 04:Ultimate Bearing Capacity of Shallow Foundations: Special Cases"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex4.1:Pg-176"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#example 4.1\n",
- "\n",
- "FS=4.0; # FOS\n",
- "q=110*2.0; # in 1b/ft^2\n",
- "Nq=90.0;\n",
- "Ny=50.0;\n",
- "Gamma=110.0; # in 1b/ft^3\n",
- "m1=0.34; # From Figure 4.6(a)\n",
- "B=2.5; # in ft\n",
- "L=2.5; # in ft\n",
- "H=1.5; # in ft\n",
- "phi=35; # in degree\n",
- "m2=0.45; # From Figure 4.6(b)\n",
- "Fqs=1-0.34*B/L;\n",
- "Fys=1-0.45*B/L;\n",
- "qu=q*Nq*Fqs+1/2.0*Gamma*Ny*Fys*B;\n",
- "Qall=qu*B**2/FS;\n",
- "print round(Qall,2),\"bearing load in lb\"\n",
- "\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "26326.95 bearing load in lb\n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex4.2:Pg-177"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#example 4.2\n",
- "\n",
- "FS=3.0; # FOS\n",
- "cu=72.0;\n",
- "q=18.0; # in kN/m^3\n",
- "B=1.0;# in m\n",
- "H=0.25;# in m\n",
- "qu=5.14*(1+(0.5*B/H-0.707)/5.14)*cu+q;\n",
- "qall=qu/FS;\n",
- "print round(qall,1),\"bearing capacity of soil in kN/m**2\" \n",
- "\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "160.4 bearing capacity of soil in kN/m**2\n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex4.3:Pg-183"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#example 4.3\n",
- "import math\n",
- "k=0; #B/L;\n",
- "c2=30;\n",
- "Gamma=17.5; # in kN/m^3\n",
- "H=1.5; # in m\n",
- "Df=1.2; # in m\n",
- "B=2.0; # in m\n",
- "Ks=2.5;\n",
- "phi=40; # in degree\n",
- "pi=math.pi;\n",
- "qu=(1+0.2*k)*5.14*c2+(1+k)*Gamma*H**2*(1+2*Df/H)*Ks*math.tan(phi*pi/180)/B+Gamma*H;\n",
- "Qu=qu*B;\n",
- "print round(Qu,2),\"is bearing capacity in kN/m\"\n",
- "print \"there is slight variation due to rounding off error\"\n",
- "#soil 2\n",
- "Ny=109.4;\n",
- "Nq=64.2;\n",
- "Fqs=1;\n",
- "Fys=1;\n",
- "qt=Gamma*Df*Nq*Fqs+1/2.0*Gamma*Ny*Fys*B;\n",
- "print qt,\"bearing capacity in kN/m**2\"\n",
- "\n",
- "# answer in book is different due to approximation"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "575.66 is bearing capacity in kN/m\n",
- "there is slight variation due to rounding off error\n",
- "3262.7 bearing capacity in kN/m**2\n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex4.4:Pg-184"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#example 4.4\n",
- "\n",
- "B=1.0; # in m\n",
- "L=1.5;# in m\n",
- "c2=48;# in m\n",
- "ca=108; # in KN/m^2\n",
- "D=1.0;# in m\n",
- "H=1.0;# in m\n",
- "Gamma=16.8; # in KN/m^3\n",
- "FS=4;\n",
- "qu=(1+0.2*B/L)*5.14*c2+(1+B/L)*2*ca*H/B+Gamma*D; # in KN/m^2\n",
- "c1=120.0;\n",
- "gamma1=16.8; # in kN/m^3\n",
- "Df=1.0;\n",
- "qt=(1+0.2*B/L)*5.14*c1+gamma1*Df;\n",
- "print qt,\"is qt in kN/m**2\"\n",
- "print \"no need to calculate qt since it is not useful for calculation\"\n",
- "print qu/FS,\"is allowable shear stress in kN/m**2\"\n",
- "print qu/FS*1*1.5,\" is allowable load in kN\"\n",
- "\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "715.84 is qt in kN/m**2\n",
- "no need to calculate qt since it is not useful for calculation\n",
- "164.104 is allowable shear stress in kN/m**2\n",
- "246.156 is allowable load in kN\n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex4.5:Pg-190"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#example 4.5\n",
- "\n",
- "c=50; # in KN/m^2\n",
- "#from table\n",
- "Ncq=6.3;\n",
- "FS=4.0;# FOS\n",
- "qu=c*Ncq; # in KN/m^2\n",
- "qall=qu/4;\n",
- "print qall,\"allowed shear stress in kN/m**2\"\n",
- "\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "78.75 allowed shear stress in kN/m**2\n"
- ]
- }
- ],
- "prompt_number": 13
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex4.6:Pg-191"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#example 4.6\n",
- "\n",
- "Gamma=16.8; # in kN/m^3\n",
- "B=1.5;# in m\n",
- "#from table\n",
- "Nyq=120.0;\n",
- "qu=1/2.0*Gamma*B*Nyq; # in KN/m^2\n",
- "print qu,\" is shear stress in kN/m**2\"\n",
- "\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "1512.0 shear stress in kN/m**2\n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex4.7:Pg-198"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#example 4.7\n",
- "import math\n",
- "phi=35; # in degree\n",
- "Df=1.5; # in m\n",
- "B=1.5; # in m\n",
- "Gamma=17.4; # in kN/m^3\n",
- "A=math.pi/4*Df**2; # in m^2\n",
- "m=0.25;\n",
- "Ku=0.936;\n",
- "Fq=1+2*(1+m*Df/B)*Df/B*Ku*math.tan(phi*math.pi/180);\n",
- "Qu=Fq*Gamma*A*Df; # in KN/m^2\n",
- "print round(Qu,1),\" is bearing capacity in kN\"\n",
- "\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "121.7 is bearing capacity in kN\n"
- ]
- }
- ],
- "prompt_number": 17
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex4.8:pg-198"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "#example 4.8\n",
- "\n",
- "\n",
- "\n",
- "cu=52; # in kN/m^2\n",
- "\n",
- "B=1.5; # in m\n",
- "\n",
- "L=3; # in m\n",
- "\n",
- "k=0.107*cu+2.5;\n",
- "\n",
- "print round(k,2),\" is Df/B of square\" \n",
- "\n",
- "A=L*B; # in m^2\n",
- "\n",
- "Beta=0.2;\n",
- "\n",
- "Gamma=18.9; # in kN/m^3\n",
- "\n",
- "Df=1.8; # in m\n",
- "\n",
- "Qu=A*(Beta*(7.56+1.44*B/L)*cu+Gamma*Df); # in kN/m^2\n",
- "\n",
- "print round(Qu,1),\" is ultimate shear force in kN\"\n",
- "\n",
- " \n",
- "\n",
- " "
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "8.06 is Df/B of square\n",
- "540.6 is ultimate shear force in kN\n"
- ]
- }
- ],
- "prompt_number": 20
- }
- ],
- "metadata": {}
- }
- ]
-}
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