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diff --git a/Principles_Of_Foundation_Engineering/Chapter04.ipynb b/Principles_Of_Foundation_Engineering/Chapter04.ipynb new file mode 100755 index 00000000..da8b3fb8 --- /dev/null +++ b/Principles_Of_Foundation_Engineering/Chapter04.ipynb @@ -0,0 +1,365 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:84b2322c895fb47191307e7a54e3a6dc70036edd44f1781ba096e1e048c5f743"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 04:Ultimate Bearing Capacity of Shallow Foundations: Special Cases"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex4.1:Pg-176"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#example 4.1\n",
+ "\n",
+ "FS=4.0; # FOS\n",
+ "q=110*2.0; # in 1b/ft^2\n",
+ "Nq=90.0;\n",
+ "Ny=50.0;\n",
+ "Gamma=110.0; # in 1b/ft^3\n",
+ "m1=0.34; # From Figure 4.6(a)\n",
+ "B=2.5; # in ft\n",
+ "L=2.5; # in ft\n",
+ "H=1.5; # in ft\n",
+ "phi=35; # in degree\n",
+ "m2=0.45; # From Figure 4.6(b)\n",
+ "Fqs=1-0.34*B/L;\n",
+ "Fys=1-0.45*B/L;\n",
+ "qu=q*Nq*Fqs+1/2.0*Gamma*Ny*Fys*B;\n",
+ "Qall=qu*B**2/FS;\n",
+ "print round(Qall,2),\"bearing load in lb\"\n",
+ "\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "26326.95 bearing load in lb\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex4.2:Pg-177"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#example 4.2\n",
+ "\n",
+ "FS=3.0; # FOS\n",
+ "cu=72.0;\n",
+ "q=18.0; # in kN/m^3\n",
+ "B=1.0;# in m\n",
+ "H=0.25;# in m\n",
+ "qu=5.14*(1+(0.5*B/H-0.707)/5.14)*cu+q;\n",
+ "qall=qu/FS;\n",
+ "print round(qall,1),\"bearing capacity of soil in kN/m**2\" \n",
+ "\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "160.4 bearing capacity of soil in kN/m**2\n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex4.3:Pg-183"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#example 4.3\n",
+ "import math\n",
+ "k=0; #B/L;\n",
+ "c2=30;\n",
+ "Gamma=17.5; # in kN/m^3\n",
+ "H=1.5; # in m\n",
+ "Df=1.2; # in m\n",
+ "B=2.0; # in m\n",
+ "Ks=2.5;\n",
+ "phi=40; # in degree\n",
+ "pi=math.pi;\n",
+ "qu=(1+0.2*k)*5.14*c2+(1+k)*Gamma*H**2*(1+2*Df/H)*Ks*math.tan(phi*pi/180)/B+Gamma*H;\n",
+ "Qu=qu*B;\n",
+ "print round(Qu,2),\"is bearing capacity in kN/m\"\n",
+ "print \"there is slight variation due to rounding off error\"\n",
+ "#soil 2\n",
+ "Ny=109.4;\n",
+ "Nq=64.2;\n",
+ "Fqs=1;\n",
+ "Fys=1;\n",
+ "qt=Gamma*Df*Nq*Fqs+1/2.0*Gamma*Ny*Fys*B;\n",
+ "print qt,\"bearing capacity in kN/m**2\"\n",
+ "\n",
+ "# answer in book is different due to approximation"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "575.66 is bearing capacity in kN/m\n",
+ "there is slight variation due to rounding off error\n",
+ "3262.7 bearing capacity in kN/m**2\n"
+ ]
+ }
+ ],
+ "prompt_number": 9
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex4.4:Pg-184"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#example 4.4\n",
+ "\n",
+ "B=1.0; # in m\n",
+ "L=1.5;# in m\n",
+ "c2=48;# in m\n",
+ "ca=108; # in KN/m^2\n",
+ "D=1.0;# in m\n",
+ "H=1.0;# in m\n",
+ "Gamma=16.8; # in KN/m^3\n",
+ "FS=4;\n",
+ "qu=(1+0.2*B/L)*5.14*c2+(1+B/L)*2*ca*H/B+Gamma*D; # in KN/m^2\n",
+ "c1=120.0;\n",
+ "gamma1=16.8; # in kN/m^3\n",
+ "Df=1.0;\n",
+ "qt=(1+0.2*B/L)*5.14*c1+gamma1*Df;\n",
+ "print qt,\"is qt in kN/m**2\"\n",
+ "print \"no need to calculate qt since it is not useful for calculation\"\n",
+ "print qu/FS,\"is allowable shear stress in kN/m**2\"\n",
+ "print qu/FS*1*1.5,\" is allowable load in kN\"\n",
+ "\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "715.84 is qt in kN/m**2\n",
+ "no need to calculate qt since it is not useful for calculation\n",
+ "164.104 is allowable shear stress in kN/m**2\n",
+ "246.156 is allowable load in kN\n"
+ ]
+ }
+ ],
+ "prompt_number": 12
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex4.5:Pg-190"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#example 4.5\n",
+ "\n",
+ "c=50; # in KN/m^2\n",
+ "#from table\n",
+ "Ncq=6.3;\n",
+ "FS=4.0;# FOS\n",
+ "qu=c*Ncq; # in KN/m^2\n",
+ "qall=qu/4;\n",
+ "print qall,\"allowed shear stress in kN/m**2\"\n",
+ "\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "78.75 allowed shear stress in kN/m**2\n"
+ ]
+ }
+ ],
+ "prompt_number": 13
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex4.6:Pg-191"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#example 4.6\n",
+ "\n",
+ "Gamma=16.8; # in kN/m^3\n",
+ "B=1.5;# in m\n",
+ "#from table\n",
+ "Nyq=120.0;\n",
+ "qu=1/2.0*Gamma*B*Nyq; # in KN/m^2\n",
+ "print qu,\" is shear stress in kN/m**2\"\n",
+ "\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "1512.0 shear stress in kN/m**2\n"
+ ]
+ }
+ ],
+ "prompt_number": 14
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex4.7:Pg-198"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#example 4.7\n",
+ "import math\n",
+ "phi=35; # in degree\n",
+ "Df=1.5; # in m\n",
+ "B=1.5; # in m\n",
+ "Gamma=17.4; # in kN/m^3\n",
+ "A=math.pi/4*Df**2; # in m^2\n",
+ "m=0.25;\n",
+ "Ku=0.936;\n",
+ "Fq=1+2*(1+m*Df/B)*Df/B*Ku*math.tan(phi*math.pi/180);\n",
+ "Qu=Fq*Gamma*A*Df; # in KN/m^2\n",
+ "print round(Qu,1),\" is bearing capacity in kN\"\n",
+ "\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "121.7 is bearing capacity in kN\n"
+ ]
+ }
+ ],
+ "prompt_number": 17
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "\n",
+ "#example 4.8\n",
+ "\n",
+ "\n",
+ "\n",
+ "cu=52; # in kN/m^2\n",
+ "\n",
+ "B=1.5; # in m\n",
+ "\n",
+ "L=3; # in m\n",
+ "\n",
+ "k=0.107*cu+2.5;\n",
+ "\n",
+ "print round(k,2),\" is Df/B of square\" \n",
+ "\n",
+ "A=L*B; # in m^2\n",
+ "\n",
+ "Beta=0.2;\n",
+ "\n",
+ "Gamma=18.9; # in kN/m^3\n",
+ "\n",
+ "Df=1.8; # in m\n",
+ "\n",
+ "Qu=A*(Beta*(7.56+1.44*B/L)*cu+Gamma*Df); # in kN/m^2\n",
+ "\n",
+ "print round(Qu,1),\" is ultimate shear force in kN\"\n",
+ "\n",
+ " \n",
+ "\n",
+ " "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "8.06 is Df/B of square\n",
+ "540.6 is ultimate shear force in kN\n"
+ ]
+ }
+ ],
+ "prompt_number": 20
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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