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-{
- "metadata": {
- "name": "",
- "signature": "sha256:3f5444f542f0d6a3b857b61fbecdc4e8047247ed8828d4cea5a34f91ccdf5eb3"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 1:Geotechnical Properties of Soil"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex1.1:Pg-10"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#example 1.1\n",
- "\n",
- "V=0.25; # ft^3\n",
- "W=30.8; #lb\n",
- "Wd=28.2; # weight dried lb\n",
- "Gs=2.7;\n",
- "Gammaw=62.4; #lb/ft^3\n",
- "Gamma=W/V;\n",
- "print Gamma,\" is moist unit weight in lb/ft^3\"\n",
- "w=(W-Wd)/W;\n",
- "print round(w*100,2),\"is moisture content in %\"\n",
- "Gammad=Wd/V;\n",
- "print Gammad, \"is dry unit weight in lb/ft^3\"\n",
- "Vs=Wd/Gs/Gammaw;\n",
- "Vv=V-Vs;\n",
- "e=Vv/Vs;\n",
- "print round(e,3),\" is void ratio\"\n",
- "n=e/(1+e);\n",
- "print round(n,2),\"is porosity\"\n",
- "Vw=(W-Wd)/Gammaw;\n",
- "S=Vw/Vv;\n",
- "print round(S*100,2),\"is saturation in %\"\n",
- "\n",
- "# The answers in the book are different due to approximation while here calculations are precise\n",
- "\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "123.2 is moist unit weight in lb/ft^3\n",
- "8.44 is moisture content in %\n",
- "112.8 is dry unit weight in lb/ft^3\n",
- "0.494 is void ratio\n",
- "0.33 is porosity\n",
- "50.43 is saturation in %\n"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex1.2:Pg-11"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#example 1.2\n",
- "\n",
- "e=0.72;\n",
- "w=12.0/100; #moisture content\n",
- "Gs=2.72;\n",
- "Gammaw=9.81;#kN/m^3\n",
- "Gammad=Gs*Gammaw/(1+e);\n",
- "print round(Gammad,2),\"= dry unit weight in kN/m^3\"\n",
- "Gamma=Gs*Gammaw*(1+w)/(1+e);\n",
- "print round(Gamma,2),\" = moist unit weight in kN/m^3\"\n",
- "Gammasat=(Gs+e)*Gammaw/(1+e);\n",
- "wa=Gammasat-Gamma;#water added\n",
- "print round(wa,2),\" = water added in kN/m^3\"\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "15.51 = dry unit weight in kN/m^3\n",
- "17.38 = moist unit weight in kN/m^3\n",
- "2.24 = water added in kN/m^3\n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex1.3:Pg-12"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#example 1.3\n",
- "from scipy.optimize import fsolve\n",
- "gmax=17.1; # Gammadmax\n",
- "Dr=0.7;\n",
- "w=8.0/100;#moisture content\n",
- "gmin=14.2; #Gammadmin\n",
- "def f(x):\n",
- " return (x-14.2)/(17.1-14.2)*17.1/x-0.7 \n",
- "x=fsolve(f,16);#solving for gammad\n",
- "Gamma=x[0]*(1+w);\n",
- "print round(Gamma,2),\"moist unit weight in kN/m^3\"\n",
- "\n",
- "\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "17.4 moist unit weight in kN/m^3\n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex1.7:Pg-38"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#example 1.7\n",
- "import math\n",
- "#part (a)\n",
- "e1=0.92;\n",
- "e2=0.86;\n",
- "Hc=2.8; # in m\n",
- "s2=212.0;#sigma2dash Load in kN/m2\n",
- "s1=140.0;#sigma1dash Load in kN/m2\n",
- "Cc=(e1-e2)/math.log10(s2/s1);\n",
- "Sc=Cc*Hc/(1+e1)*math.log10(s2/s1);\n",
- "print Sc*1000,\"consolidated depth in mm\"\n",
- "#part (b)\n",
- "# from Figure (1.21):\n",
- "Sct=40.0;# in mm\n",
- "T50=0.197;\n",
- "t=4.5; # in MIN\n",
- "Cr=T50*12.7**2.0/t;\n",
- "U=Sct/Sc*100.0/1000;\n",
- "H=Hc/2;\n",
- "Tv=math.pi/4*U**2.0/100**2;\n",
- "t=Tv*H**2.0/Cr*1000.0**2/60.0/24;\n",
- "print round(t,1),\" is time required in days\"\n",
- "\n",
- "\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "87.5 consolidated depth in mm\n",
- "31.6 is time required in days\n"
- ]
- }
- ],
- "prompt_number": 27
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex1.8:Pg-42"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#example 1.8\n",
- "\n",
- "Cv=7.061; # in mm^2/min\n",
- "tc=15*24*60.0;\n",
- "H=2.8/2*1000.0;\n",
- "Scmax=87.5; # consolidation\n",
- "Tc=Cv*tc/H**2;\n",
- "tv=31.6*24*60;\n",
- "Tv=Cv*tv/H**2;\n",
- "#from figure 1.28\n",
- "Sct=Scmax*0.36;\n",
- "print Sct,\"is consolidation in 31.6 days in mm\"\n",
- "\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "31.5 is consolidation in 31.6 days in mm\n"
- ]
- }
- ],
- "prompt_number": 28
- }
- ],
- "metadata": {}
- }
- ]
-} \ No newline at end of file