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Diffstat (limited to 'Principles_Of_Electronic_Instrumentation/Pinciples_of_electronic_Instrumentation_Ch5.ipynb')
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diff --git a/Principles_Of_Electronic_Instrumentation/Pinciples_of_electronic_Instrumentation_Ch5.ipynb b/Principles_Of_Electronic_Instrumentation/Pinciples_of_electronic_Instrumentation_Ch5.ipynb deleted file mode 100755 index c194e95b..00000000 --- a/Principles_Of_Electronic_Instrumentation/Pinciples_of_electronic_Instrumentation_Ch5.ipynb +++ /dev/null @@ -1,446 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 5: ADC and DAC"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example5_1,pg 491"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# output voltage\n",
- "\n",
- "import math\n",
- "# Variable declaration\n",
- "Vref=12.0 #ref. voltage\n",
- "n =4.0 #no. of binary weighted resistors\n",
- "n1=3.0 #input-1\n",
- "n2=1.0 #input-2\n",
- "\n",
- "#Calculations\n",
- "Vo=-(Vref/2**n)*(2**n1+2**n2)\n",
- "\n",
- "#Result \n",
- "print(\"output voltage:\")\n",
- "print(\"Vo = %.1f V\"%Vo) "
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "output voltage:\n",
- "Vo = -7.5 V\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example5_2,pg 491"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# voltage division ratio and feedback resistor\n",
- "\n",
- "import math\n",
- "# Variabe declaration \n",
- "# serie arm resistance = 10k, since the divider arm resistance Rsh=2Rse \n",
- "# therefore for straight binary code, one should have section voltage ratio as Vos/Vis=0.5\n",
- "\n",
- "#Vo/Vref=0.5\n",
- "Rse=10*10**3 #series resistance(Rsh/2)\n",
- "\n",
- "#Calculation\n",
- "Rf=0.5*(16*Rse)/15 #feedback resistor\n",
- "\n",
- "#Result\n",
- "print(\"voltage section ratio = 0.5\")\n",
- "print(\"\\nfeedback resistor:\")\n",
- "print(\"Rf = %.2f k-ohm\"%(Rf/1000)) "
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "voltage section ratio = 0.5\n",
- "\n",
- "feedback resistor:\n",
- "Rf = 5.33 k-ohm\n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example5_3,pg 492"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# output voltage\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Rse = 1*10**3 #series resistance\n",
- "Rsh = 2*10**3 #shunt resistance\n",
- "Vref= 5.0 #ref. voltage\n",
- "n1 = 0 #input-1\n",
- "n2 = 3 #input-2\n",
- "Ro=0.22*10**3 #load resistance\n",
- "\n",
- "#Calculations\n",
- "Vo=(Vref*(2**n1+2**n2)/16)*(Ro/(Ro+Rsh))\n",
- "\n",
- "#Result\n",
- "print(\"output voltage:\")\n",
- "print(\"Vo = %.3f V\"%(math.floor(Vo*1000)/1000)) "
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "output voltage:\n",
- "Vo = 0.278 V\n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example5_4,pg 492"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# find count\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Vref=5.0 #ref. voltage\n",
- "t=1*10**-3 #sawtooth wave time\n",
- "f=100*10**3 #clock frequency\n",
- "Vi=1 #input voltage\n",
- "\n",
- "#Calculations\n",
- "N=((t*f*Vi)/Vref) #count\n",
- "\n",
- "#Result\n",
- "print(\"count = %d\"%N)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "count = 20\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example5_5,pg 492"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# find integrator output voltage\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Tu=1*10**-3 #wave time\n",
- "Vi=0.2 #input voltage\n",
- "t=4*10**-3 #integration time constant(1/RC)\n",
- "\n",
- "\n",
- "#Calculation\n",
- "V1=((Vi*Tu)/t) #integrator output voltage\n",
- "\n",
- "#Result\n",
- "print(\"integrator output voltage:\")\n",
- "print(\"V1 = %.2f V\"%V1) "
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "integrator output voltage:\n",
- "V1 = 0.05 V\n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example5_6,pg 493"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# find rise in output voltage and charging time\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Tz=0.6*10**-3 #discharge time\n",
- "Vref=1 #ref. voltage\n",
- "t=4*10**-3 #integrator time const.\n",
- "Vi=0.2 #input voltage\n",
- "#Calculations\n",
- "Vk=((Vref*Tz)/t) #rise in output integrator\n",
- "Tu=Vref*(Tz/Vi) #charging time\n",
- "\n",
- "#Result\n",
- "print(\"Rise in integrator output:\")\n",
- "print(\"Vk = %.2f V\\n\"%Vk)\n",
- "print(\"charging time:\")\n",
- "print(\"Tu = %.0f msec\"%(Tu*1000)) "
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Rise in integrator output:\n",
- "Vk = 0.15 V\n",
- "\n",
- "charging time:\n",
- "Tu = 3 msec\n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example5_7,pg 493"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# find count of counter\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Vref=1 #ref. voltage\n",
- "Vi=0.2 #input voltage\n",
- "n=15 #no. of counts before reset(n+1)\n",
- "\n",
- "#Calculations\n",
- "N=((n+1)*Vi)/Vref #no.of counts over charging time\n",
- "\n",
- "print(\"No of counts over charging time:\")\n",
- "print(\"N = %.1f = %d(approx.) \"%(N,N)) "
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "No of counts over charging time:\n",
- "N = 3.2 = 3(approx.) \n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example5_8,pg 493"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# find input voltage\n",
- "\n",
- "import math\n",
- "Nx=2**6 #6 bit counteer register\n",
- "Vref=2.2 #ref. voltage\n",
- "N=32.0 #SAR output\n",
- "\n",
- "#Calculations\n",
- "Vi=(N/(Nx+1)*Vref) #input voltage\n",
- "\n",
- "#Result\n",
- "print(\"Input Voltage:\")\n",
- "print(\"Vi = %.2f V\"%Vi) "
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Input Voltage:\n",
- "Vi = 1.08 V\n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example5_9,pg 493"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# conversion number\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "n=3 #3-bit ADC\n",
- "Vref=2.2 #ref.voltage\n",
- "Vi=1 #input voltage\n",
- "\n",
- "#Calculations\n",
- "N=(((2**n)-1)*Vi)/Vref #SAR output\n",
- "\n",
- "#Result\n",
- "print(\"SAR conversion no.:\")\n",
- "print(\"N = %.2f \"%N) "
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "SAR conversion no.:\n",
- "N = 3.18 \n"
- ]
- }
- ],
- "prompt_number": 15
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example5_10,pg 493"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# signal to noise ratio\n",
- "\n",
- "import math\n",
- "#Variable declaaration\n",
- "n = 3.0 #3-bit ADC\n",
- "\n",
- "#Calculations\n",
- "SbyN=(((2**(n-1)*12**0.5)/2**0.5)) #S/N ratio\n",
- "\n",
- "#Result\n",
- "print(\"S/N ratio:\")\n",
- "print(\"SbyN = %.3f\\n\"%SbyN) \n",
- "print(\"This produces an error due to noise nearly 10%\")"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "S/N ratio:\n",
- "SbyN = 9.798\n",
- "\n",
- "This produces an error due to noise nearly 10%\n"
- ]
- }
- ],
- "prompt_number": 14
- }
- ],
- "metadata": {}
- }
- ]
-}
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