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diff --git a/Principles_Of_Electronic_Instrumentation/Pinciples_of_electronic_Instrumentation_Ch11.ipynb b/Principles_Of_Electronic_Instrumentation/Pinciples_of_electronic_Instrumentation_Ch11.ipynb deleted file mode 100755 index ad09fffb..00000000 --- a/Principles_Of_Electronic_Instrumentation/Pinciples_of_electronic_Instrumentation_Ch11.ipynb +++ /dev/null @@ -1,518 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 11 : Test Signal Generation"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example11_1,pg 343\n"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# limits of duty cycle\n",
- "\n",
- "import math\n",
- "#Variable decl;aration\n",
- "R1=1.0*10**3 #input resistance\n",
- "R2=1.0*10**3 #feedback resistor\n",
- "R3=1.0*10**3 #non inverting ter. resistor\n",
- "R8=1.0*10**3 #potentiometer\n",
- "R4=1.0*10**3\n",
- "\n",
- "#Calculations\n",
- "DF1=(R1/((2*R1)+R8)) #duty factor lim.-1\n",
- "DF2=(R1+R4)/((2*R1)+R8) #duty factor lim.-2\n",
- "#T=(((2*R4*C*((2*R1)+R8)))/R1)*(Vt/Vi)=((6*R4*C*Vt)/Vi)\n",
- "\n",
- "#Result\n",
- "print(\"range of duty factor is DF1 to DF2 i.e.\")\n",
- "print(\"%.2f to %.2f \"%(DF1,DF2))\n",
- "print(\"\\nlimits of t1 and t2:\")\n",
- "print(\"(T/3) to (2T/3)\")"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "range of duty factor is DF1 to DF2 i.e.\n",
- "0.33 to 0.67 \n",
- "\n",
- "limits of t1 and t2:\n",
- "(T/3) to (2T/3)\n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example11_2,pg 344"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# determine sinewave amplitude and segment slopes\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Vtx=5.0 #triangular peak(+/-)5\n",
- "Vsx=(2/math.pi)*Vtx #sinewave peak\n",
- "#if n=3 then there are 2*3=6 break points these are at o/p voltages\n",
- "n=3.0 #break point parameter\n",
- "\n",
- "#Calculations\n",
- "Vs1=(2/math.pi)*Vtx*math.sin((1*math.pi)/((2*n)+1))\n",
- "Vs2=(2/math.pi)*Vtx*math.sin((2*math.pi)/((2*n)+1))\n",
- "Vs3=(2/math.pi)*Vtx*math.sin((3*math.pi)/((2*n)+1))\n",
- "#calculating slopes\n",
- "ms1=(((2*n)+1)/math.pi)*(math.sin((math.pi*(1+1))/((2*n)+1))-math.sin((math.pi*1)/((2*n)+1)))\n",
- "ms2=(((2*n)+1)/math.pi)*(math.sin((math.pi*(2+1))/((2*n)+1))-math.sin((math.pi*2)/((2*n)+1)))\n",
- "ms3=(((2*n)+1)/math.pi)*(math.sin((math.pi*(3+1))/((2*n)+1))-math.sin((math.pi*3)/((2*n)+1)))\n",
- "\n",
- "#Result\n",
- "print(\"break points:\")\n",
- "print(\"output voltages:\")\n",
- "print(\"Vs1 = %.2f V \"%Vs1)\n",
- "print(\"Vs2 = %.2f V \"%Vs2)\n",
- "print(\"Vs3 = %.2f V\\n\"%Vs3)\n",
- "print(\"segment slopes:\")\n",
- "print(\"ms1 = %.2f \"%ms1)\n",
- "print(\"ms2 = %.2f \"%ms2)\n",
- "print(\"ms3 = %.2f \"%ms3)\n",
- "#Answers are slightly different than book"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "break points:\n",
- "output voltages:\n",
- "Vs1 = 1.38 V \n",
- "Vs2 = 2.49 V \n",
- "Vs3 = 3.10 V\n",
- "\n",
- "segment slopes:\n",
- "ms1 = 0.78 \n",
- "ms2 = 0.43 \n",
- "ms3 = 0.00 \n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example11_3,pg 505"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# find inductance\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "R1=0.0 #resistance\n",
- "C=0.1*10**-6 #capacitance\n",
- "f=1.0*10**3 #frequency\n",
- "\n",
- "#Calculations\n",
- "L=(1.0/(((2*math.pi*f)**2)*C))\n",
- "\n",
- "\n",
- "#Result\n",
- "print(\"Inductance of circuit:\")\n",
- "print(\"L = %.6f H \"%(L))\n",
- "#Answer do not matche with book"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Inductance of circuit:\n",
- "L = 0.253303 H \n"
- ]
- }
- ],
- "prompt_number": 20
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example11_4,pg 506"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# resonance frequency of crystal\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "C1=4*10**-12 #Capacitance\n",
- "L=94*10**-3 #inductance \n",
- "C=13*10**-9 #capacitance\n",
- "R=91.3 #resistance\n",
- "\n",
- "#Calculations\n",
- "f1=(1/(2*math.pi))*((L*C)**(-1.0/2)) #resonance frequency-1\n",
- "f2=(math.sqrt(1+(C/C1))/(2*math.pi*math.sqrt(L*C))) #resonance frequency-2\n",
- "\n",
- "#Result\n",
- "print(\"resonance frequency-1:\")\n",
- "print(\"f1 = %.2f kHz\\n\"%(f1/1000))\n",
- "print(\"resonance frequency-2:\")\n",
- "print(\"f2 = %.2f kHz\"%(f2/1000))\n",
- "#Answer for f2 is slightly different"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "resonance frequency-1:\n",
- "f1 = 4.55 kHz\n",
- "\n",
- "resonance frequency-2:\n",
- "f2 = 259.59 kHz\n"
- ]
- }
- ],
- "prompt_number": 23
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example11_5,pg 506\n"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# find R in CR section\n",
- "\n",
- "import math\n",
- "#Result\n",
- "f=1.0*10**3 #frequency\n",
- "C=0.01*10**-6 #capacitance\n",
- "\n",
- "#Calculations\n",
- "#f=(1/(2*%pi))*(1/(6^(1/2)*RC))\n",
- "R=(1/(2*math.pi*(6**(0.5)*C*f)))\n",
- "\n",
- "#Result\n",
- "print(\"resistance of circuit\\n\")\n",
- "print(\"R = %.1f k-ohm\"%(R/1000))"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "resistance of circuit\n",
- "\n",
- "R = 6.5 k-ohm\n"
- ]
- }
- ],
- "prompt_number": 24
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example11_6,pg 506"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# find phase difference in wein network\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "epsi=0.01 #detuning parameter\n",
- "eta1=1.0 #(f/fo)=1\n",
- "eta2=2.2 #(f/fo)=2.2\n",
- "\n",
- "#Calculations\n",
- "#case-1\n",
- "phi1=math.atan((3*eta1*((eta1**2)-1)*(3+(2*epsi)))/((((eta1**2)-1)**2)*(3+epsi)-(9*epsi*(eta1**2))))\n",
- "#case-2\n",
- "phi2=math.atan((3*eta2*((eta2**2)-1)*(3+(2*epsi)))/((((eta2**2)-1)**2)*(3+epsi)-(9*epsi*(eta2**2))))\n",
- "\n",
- "#Result\n",
- "print(\"phase difference for case-1:\")\n",
- "print(\"phi1 = %d rad\\n\"%phi1)\n",
- "print(\"phase difference for case-2:\")\n",
- "print(\"phi2 = %.2f rad\"%phi2)\n",
- "#Answer for phi2 is not matching with book"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "phase difference for case-1:\n",
- "phi1 = 0 rad\n",
- "\n",
- "phase difference for case-2:\n",
- "phi2 = 1.05 rad\n"
- ]
- }
- ],
- "prompt_number": 30
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example11_7,pg 507"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# digital frequency synthesizer\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "N=12.0 #12-bit synthesizer\n",
- "k1=1.0 #sampling rate at sampler's rate\n",
- "k2=4.0 #sampling rate at 4 times sampler's rate\n",
- "\n",
- "\n",
- "#Calculations\n",
- "#case-1\n",
- "adv1=(360/(2**N)) #advancement of o/p register \n",
- "#2pi rad=360 deg.\n",
- "#case-2\n",
- "adv2=(4.0*(360)/(2**N)) #advancement of o/p register \n",
- "\n",
- "#Result\n",
- "print(\"advancement of o/p register for case-1:\")\n",
- "print(\"adv1 = %.4f\u00b0 \\n\"%adv1)\n",
- "print(\"advancement of o/p register for case-2:\")\n",
- "print(\"adv2 = %.4f\u00b0\"%adv2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "advancement of o/p register for case-1:\n",
- "adv1 = 0.0879\u00b0 \n",
- "\n",
- "advancement of o/p register for case-2:\n",
- "adv2 = 0.3516\u00b0\n"
- ]
- }
- ],
- "prompt_number": 31
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example11_8,pg 507"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# find controlling voltage\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "f=1.0*10**3 #frequency\n",
- "R6=10.0*10**3 #feed-back resistor\n",
- "R5=22.0*10**3 #feed-in resistor\n",
- "R4=10.0*10**3 #integrator resistor\n",
- "C=0.1*10**-6 #integrator capacitor\n",
- "Vsx=2.0 #comparator pulse amplitude\n",
- "\n",
- "#Calculations\n",
- "Vi=((f*R4*R5*C)/(R6*4*Vsx)) #controlling voltage\n",
- "\n",
- "#Result\n",
- "print(\"controlling voltage:\")\n",
- "print(\"Vi = %.3f V\"%Vi)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "controlling voltage:\n",
- "Vi = 0.275 V\n"
- ]
- }
- ],
- "prompt_number": 33
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example11_9,pg 507"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# find limits of duty factor\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "R1=10.0*10**3\n",
- "R8=10.0*10**3\n",
- "R4=10.0*10**3\n",
- "\n",
- "#Calculations\n",
- "lim1=(R1/((2*R1)+R8)) #limit-1 of duty factor\n",
- "lim2=((R1+R4)/((2*R1)+R8)) #limit-2 of duty factor\n",
- "\n",
- "#Result\n",
- "print(\"duty factors are given by (t1/T) and (t2/T). the limits are giiven by\\n\")\n",
- "print(\"lim1 = %.2f\"%lim1)\n",
- "print(\"lim2 = %.2f\"%lim2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "duty factors are given by (t1/T) and (t2/T). the limits are giiven by\n",
- "\n",
- "lim1 = 0.33\n",
- "lim2 = 0.67\n"
- ]
- }
- ],
- "prompt_number": 19
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example11_10,pg 507"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# find output voltage V1 and V2\n",
- "\n",
- "import math\n",
- "#Variable declaration\n",
- "Vi=1.3 #input voltage\n",
- "R2=10.0*10**3\n",
- "R3=10.0*10**3\n",
- "R8=10.0*10**3 #potentiometer\n",
- "B=1.0/3 #wiper distance\n",
- "\n",
- "\n",
- "#Calculations\n",
- "V1=((R3*Vi)/(R3+(B*R8))) #output voltage-1\n",
- "V2=-((R2*Vi)/(R3+((1-B)*R8)))#output voltage-2\n",
- "\n",
- "#Result\n",
- "print(\"ouput voltage-1:\")\n",
- "print(\"V1 = %.4f V\"%V1)\n",
- "print(\"ouput voltage-2:\")\n",
- "print(\"V2 = %.4f V\"%V2)\n",
- "#Answers are slightly different than book"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "ouput voltage-1:\n",
- "V1 = 0.9750 V\n",
- "ouput voltage-2:\n",
- "V2 = -0.7800 V\n"
- ]
- }
- ],
- "prompt_number": 36
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [],
- "language": "python",
- "metadata": {},
- "outputs": []
- }
- ],
- "metadata": {}
- }
- ]
-}
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