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-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:e7ff5ec8c26bca61ce95f7f9a6bfe9182508039293520fdb892a47c60afd9608"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter 8 - Quantum chemistry"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 1 - pg 460"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate the Wavelength\n",
-      "#initialisation of variables\n",
-      "v= 299.8 #V\n",
-      "e= 4.802*10**-10 #ev\n",
-      "h= 6.624*10**-27 #ergs sec\n",
-      "c= 3*10**10 #cm/sec\n",
-      "#CALCULATIONS\n",
-      "E= e/v\n",
-      "l= h*c*10**8/(2*E)\n",
-      "#RESULTS\n",
-      "print '%s %.1f %s' % (' Wavelength =',l,'A')\n",
-      "print 'The answers are a bit different due to rounding off error in textbook'"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " Wavelength = 6203.3 A\n",
-        "The answers are a bit different due to rounding off error in textbook\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 2 - pg 462"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate the value of numerical coefficient\n",
-      "#initialisation of variables\n",
-      "u= 109677.583 #cm**-1\n",
-      "#RESULTS\n",
-      "print '%s %.1f %s' % (' value of numerical coefficient =',u,' cm')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " value of numerical coefficient = 109677.6  cm\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 3 - pg 464"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate the wavelength in both cases\n",
-      "#initialisation of variables\n",
-      "import math\n",
-      "h= 6.6234*10**-27 #ergs sec\n",
-      "m= 2.59 #gms\n",
-      "v= 3.35*10**4 #cm sec **-1\n",
-      "e= 4.8*10**-10 #ev\n",
-      "V= 40000. #volts\n",
-      "M= 300. #gms\n",
-      "L= 1836. #A\n",
-      "N= 6*10**23 #molecules\n",
-      "#CALCULATIONS\n",
-      "p= m*v\n",
-      "l= h/p\n",
-      "E= V*e/M\n",
-      "P= math.sqrt(2*E*(1/(L*N)))\n",
-      "L1= h*10**8/P\n",
-      "#RESULTS\n",
-      "print '%s %.2e %s' % (' wavelength =',l,'cm')\n",
-      "print '%s %.4f %s' % (' \\n wavelength =',L1,'A')"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " wavelength = 7.63e-32 cm\n",
-        " \n",
-        " wavelength = 0.0614 A\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 4 - pg 471"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate the lifetime of this excited state\n",
-      "#initialisation of variables\n",
-      "import math\n",
-      "h= 6.624*10**-27 #ergs sec\n",
-      "c= 3*10**10 #cm/sec\n",
-      "u= 5 #cm**-1\n",
-      "#CALCULATIONS  \n",
-      "T= h/(h*2*math.pi*c*u)\n",
-      "#RESULTS\n",
-      "print '%s %.1e %s' % (' lifetime of this excited state =',T,'sec')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " lifetime of this excited state = 1.1e-12 sec\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 5 - pg 471"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate the lifetime\n",
-      "#initialisation of variables\n",
-      "import math\n",
-      "V= 2.5*10**4 #m/sec\n",
-      "m= 30 #gms\n",
-      "s= 10*10**-16 #cm**2\n",
-      "N= 6.023*10**23 #molecules\n",
-      "T= 300 #K\n",
-      "k= 8.3*10**7\n",
-      "#CALCULATIONS\n",
-      "t= math.sqrt((m/(math.pi*k*T)))*(V/(4*s*N))\n",
-      "#RESULTS\n",
-      "print '%s %.1e %s' % (' lifetime =',t,' sec')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " lifetime = 2.0e-10  sec\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 7 - pg 494"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate the internuclear distances\n",
-      "#initialisation of variables\n",
-      "import math\n",
-      "h= 6.6238*10**-27 #ergssec\n",
-      "N= 6.0254*10**23 #molecules\n",
-      "c= 2.9979*10**10\n",
-      "Be= 60.809\n",
-      "mh= 1.00812 #gms\n",
-      "#CALCULATIONS\n",
-      "u= mh/2.\n",
-      "Re= math.sqrt(h*N/(c*8*math.pi**2*Be*u))\n",
-      "#RESULTS\n",
-      "print '%s %.4e %s' % (' internuclear distances =',Re,'cm ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " internuclear distances = 7.4168e-09 cm \n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 8 - pg 497"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate the Resonance energy\n",
-      "#initialisation of variables\n",
-      "H= 19.8 #kcal\n",
-      "H1= -0.8 #kcal\n",
-      "H2= -29.4 #kcal\n",
-      "#CALCULATIONS\n",
-      "H3= -85.8\n",
-      "H4= -49.2\n",
-      "H5= -H3+H4\n",
-      "#RESULTS\n",
-      "print '%s %.1f %s' % (' Resonance energy =',H5,'cal')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " Resonance energy = 36.6 cal\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 9 - pg 500"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate the no of bonds\n",
-      "#initialisation of variables\n",
-      "import math\n",
-      "R= 1.69 #A\n",
-      "l= 1.49 #A\n",
-      "r= 0.706\n",
-      "#CALCULATIONS\n",
-      "n= 10**((R-l)/r)\n",
-      "#RESULTS\n",
-      "print '%s %.2f' % (' no of bonds = ',n)\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " no of bonds =  1.92\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 10 - pg 504"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate the lattice energy\n",
-      "#initialisation of variables\n",
-      "N= 6.*10**23 #molecules\n",
-      "R= 2.82 #A\n",
-      "e= 4.8*10**-10 #ev\n",
-      "n= 9.\n",
-      "z= 1.748\n",
-      "#CALCULATIONS\n",
-      "U= (N*z*e**2*(1-(1/n)))*182.2/(R*10**-8*7.63*10**12)\n",
-      "#RESULTS\n",
-      "print '%s %.1f %s' % (' lattice energy =',U,'kcal mole**-1')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " lattice energy = 181.9 kcal mole**-1\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 11 - pg 507"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate the least energy required for transfer\n",
-      "#initialisation of variables\n",
-      "import math\n",
-      "k= 13\n",
-      "e= 4.8*10**-10 #ev\n",
-      "h= 6.624*10**-27 #ergs sec\n",
-      "N= 6.023*10**23 #molecules\n",
-      "l= 1836 #A\n",
-      "#CALCULATIONS\n",
-      "I= e**4*0.080/(l*N*1.28*10**-13*2*k**2*(h/(2*math.pi))**2)\n",
-      "#RESULTS\n",
-      "print '%s %.2f %s' % (' least energy required for transfer=',I,' ev')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " least energy required for transfer= 0.08  ev\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 12 - pg 509"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate the difference between potentials\n",
-      "#initialisation of variables\n",
-      "i= 54.4 #ev\n",
-      "i1= 24.6 #ev\n",
-      "k= 2.5 \n",
-      "#CALCULATIONS\n",
-      "I= i/(4*k**2)\n",
-      "I1= i1/(4*k**2)\n",
-      "d= I-I1\n",
-      "#RESULTS\n",
-      "print '%s %.1f %s' % (' difference between first and second potential=',d,'ev')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " difference between first and second potential= 1.2 ev\n"
-       ]
-      }
-     ],
-     "prompt_number": 11
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file