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Diffstat (limited to 'Physical_Chemsitry/Chapter15.ipynb')
| -rwxr-xr-x | Physical_Chemsitry/Chapter15.ipynb | 322 |
1 files changed, 0 insertions, 322 deletions
diff --git a/Physical_Chemsitry/Chapter15.ipynb b/Physical_Chemsitry/Chapter15.ipynb deleted file mode 100755 index 8ce44ac5..00000000 --- a/Physical_Chemsitry/Chapter15.ipynb +++ /dev/null @@ -1,322 +0,0 @@ -{
- "metadata": {
- "name": "",
- "signature": "sha256:633d2351722f70bcb5591bec1c39746dd272ca892962c335e9bfb247bc80518a"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 15 - Electrochemistry"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1 - pg 384"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the Weight of copper leaving\n",
- "#Initialization of variables\n",
- "I=0.5 #amp\n",
- "t=55 #min\n",
- "we=31.77\n",
- "#calculations\n",
- "Q=I*t*60\n",
- "n=Q/96496.\n",
- "w=n*we\n",
- "#results\n",
- "print '%s %.3f %s' %(\"Weight of copper leaving =\",w,\" g\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Weight of copper leaving = 0.543 g\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2 - pg 386"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the values of tplus and tminus\n",
- "#Initialization of variables\n",
- "w1=0.7532 #g\n",
- "w2=0.9972 #g\n",
- "wdep=0.4 #g\n",
- "we=31.77 #g\n",
- "#calculations\n",
- "dn=w2/we - w1/we\n",
- "t=dn/(wdep/we)\n",
- "dne=wdep/we\n",
- "dnmig=dn-dne\n",
- "tplus=-dnmig/dne\n",
- "tminus=1-tplus\n",
- "#results\n",
- "print '%s %.3f' %(\"tplus =\",tplus)\n",
- "print '%s %.3f' %(\"\\n tminus=\",tminus)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "tplus = 0.390\n",
- "\n",
- " tminus= 0.610\n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3 - pg 393"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the Equivalent conductance\n",
- "#Initialization of variables\n",
- "R1=312 #ohms\n",
- "R2=1043 #ohms\n",
- "c=0.01 #N\n",
- "kdash=0.002768 #ohm^-1cm^-1\n",
- "#calculations\n",
- "k=kdash*R1\n",
- "kdash2=k/R2\n",
- "ambda=kdash2/(c/1000.)\n",
- "#results\n",
- "print '%s %.1f %s' %(\"Equivalent conductance =\",ambda,\"ohm^-1 cm^2 equiv^-1\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Equivalent conductance = 82.8 ohm^-1 cm^2 equiv^-1\n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4 - pg 393"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the Conductance for acetic acid\n",
- "#Initialization of variables\n",
- "l1=349.8 \n",
- "l2=40.9\n",
- "#calculations\n",
- "l=l1+l2\n",
- "#results\n",
- "print '%s %.1f %s' %(\"Conductance for acetic acid =\",l,\" ohm^-1 cm^2\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Conductance for acetic acid = 390.7 ohm^-1 cm^2\n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5 - pg 395"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the Specific conductanc\n",
- "#Initialization of variables\n",
- "l1=63.6\n",
- "l2=79.8\n",
- "n=1 #mg/lt\n",
- "we=116.7 #g/equiv\n",
- "#calculations\n",
- "l=l1+l2\n",
- "c=n*10**-3 /we\n",
- "k=c*l/1000.\n",
- "#results\n",
- "print '%s %.2e %s' %(\"Specific conductance =\",k,\" ohm^-1 cm^-1\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Specific conductance = 1.23e-06 ohm^-1 cm^-1\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6 - pg 402"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the SEP of the cell\n",
- "#Initialization of variables\n",
- "e1=0.763 #volt\n",
- "e2=0.337 #volt\n",
- "#calculations\n",
- "e0=e1+e2\n",
- "#results\n",
- "print '%s %.3f %s' %(\"Standard electrode potential of the cell =\",e0,\"volts\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Standard electrode potential of the cell = 1.100 volts\n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 7 - pg 403"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the Emf of the cell\n",
- "#Initialization of variables\n",
- "import math\n",
- "aZn=0.1\n",
- "aCu=0.01\n",
- "e1=0.763 #volt\n",
- "e2=0.337 #volt\n",
- "#calculations\n",
- "e0=e1+e2\n",
- "Q=aZn/aCu\n",
- "E=e0- 0.05915*math.log10(Q) /2\n",
- "#results\n",
- "print '%s %.3f %s' %(\"Emf of the cell =\",E,\" volts\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Emf of the cell = 1.070 volts\n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 8 - pg 410"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the Decomposition potential\n",
- "#Initialization of variables\n",
- "e1=1.2 #volts\n",
- "e2=0.15 #volts\n",
- "e3=0.45 #volts\n",
- "#calculations\n",
- "E=e1+e2+e3\n",
- "#results\n",
- "print '%s %.1f %s' %(\"Decomposition potential =\",E,\" volt\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Decomposition potential = 1.8 volt\n"
- ]
- }
- ],
- "prompt_number": 8
- }
- ],
- "metadata": {}
- }
- ]
-}
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