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diff --git a/Operational_Amplifiers_and_Linear_Integrated_Circuit/C10_1.ipynb b/Operational_Amplifiers_and_Linear_Integrated_Circuit/C10_1.ipynb new file mode 100644 index 00000000..1b13f377 --- /dev/null +++ b/Operational_Amplifiers_and_Linear_Integrated_Circuit/C10_1.ipynb @@ -0,0 +1,430 @@ +{
+ "metadata": {
+ "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 10: AC Performance : Bandwidth, Slew rate and Noise"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 10.1 Page No 277"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "t=0.35 #rise time\n",
+ "\n",
+ "#calculation\n",
+ "B=0.35/t #Bandwidth\n",
+ "\n",
+ "#result\n",
+ "print\"Bandwidth is\",B,\"MHz\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Bandwidth is 1.0 MHz\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 10.2 Page No 277"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "t=0.35 #rise time\n",
+ "\n",
+ "#calculation\n",
+ "B=0.35/t #Bandwidth\n",
+ "gain=B\n",
+ "\n",
+ "#result\n",
+ "print\"Openloop Voltage gain is\",gain\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Openloop Voltage gain is 1.0\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 10.3 Page No 277"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "B1=10**6 #Hz\n",
+ "B2=100*10**3 #Hz\n",
+ "\n",
+ "#calculation\n",
+ "gain=B1/B2\n",
+ "\n",
+ "#Result\n",
+ "print\"As frenquency goes down by a factor 10, Gain rise sby same which is\",gain\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "As frenquency goes down by a factor 10, Gain rise sby same which is 10\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 10.4 Page No 278"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "B=1.5 #Mhz\n",
+ "f=1 #KHz\n",
+ "\n",
+ "#Calculation\n",
+ "gain=B*1000/f\n",
+ "\n",
+ "#Result\n",
+ "print\"Open loop Voltage gain is\",gain\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Open loop Voltage gain is 1500.0\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 10.5 Page No 279"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Find the actual gain\n",
+ "\n",
+ "#Given\n",
+ "Acl=100.0 #Ideal Dc cloesd loop gain\n",
+ "Aol1=10000.0\n",
+ "Aol2=1000.0\n",
+ "Aol3=100.0\n",
+ "Aol4=10.0\n",
+ "Aol5=1.0\n",
+ "\n",
+ "#Calculation (a)\n",
+ "#For a noninverting amplifier\n",
+ "a1=Acl #ideal gain, a=(Rf+Ri)/Ri\n",
+ "actualAcl1=a1/((1+1*a1/Aol1))\n",
+ "#For the inverting amplifier\n",
+ "a2=101 #gain\n",
+ "actualAcl1_=-a1/(1+1*a2/Aol1)\n",
+ "\n",
+ "# (b)\n",
+ "#For a noninverting amplifier\n",
+ "a1=Acl #ideal gain, a=(Rf+Ri)/Ri\n",
+ "actualAcl2=a1/(1+1*a1/Aol2)\n",
+ "#For the inverting amplifier\n",
+ "a2=101 #gain\n",
+ "actualAcl2_=-a1/(1+1*a2/Aol2)\n",
+ "\n",
+ "#(c)\n",
+ "#For a noninverting amplifier\n",
+ "a1=Acl #ideal gain, a=(Rf+Ri)/Ri\n",
+ "actualAcl3=a1/(1+1*a1/Aol3)\n",
+ "#For the inverting amplifier\n",
+ "a2=101 #gain\n",
+ "actualAcl3_=-a1/(1+1*a2/Aol3)\n",
+ "\n",
+ "#(d)\n",
+ "#For a noninverting amplifier\n",
+ "a1=Acl #ideal gain, a=(Rf+Ri)/Ri\n",
+ "actualAcl4=a1/(1+1*a1/Aol4)\n",
+ "#For the inverting amplifier\n",
+ "a2=101 #gain\n",
+ "actualAcl4_=-a1/(1+1*a2/Aol4)\n",
+ "\n",
+ "#(e)\n",
+ "#For a noninverting amplifier\n",
+ "a1=Acl #ideal gain, a=(Rf+Ri)/Ri\n",
+ "actualAcl5=a1/(1+1*a1/Aol5)\n",
+ "#For the inverting amplifier\n",
+ "a2=101 #gain\n",
+ "actualAcl5_=-a1/(1+1*a2/Aol5)\n",
+ "\n",
+ "#Result\n",
+ "print\"(a)Actual gain in noninverting amplifier is\",round(actualAcl5,2)\n",
+ "print\"Actual gain in inverting amplifier is\",round(actualAcl5_,2)\n",
+ "print\"(b)Actual gain in noninverting amplifier is\",round(actualAcl4,2)\n",
+ "print\"Actual gain in inverting amplifier is\",round(actualAcl4_,2)\n",
+ "print\"(c)Actual gain in noninverting amplifier is\",round(actualAcl3,2)\n",
+ "print\"Actual gain in inverting amplifier is\",round(actualAcl3_,2)\n",
+ "print\"(d)Actual gain in noninverting amplifier is\",round(actualAcl2,2)\n",
+ "print\"Actual gain in inverting amplifier is\",round(actualAcl2_,2)\n",
+ "print\"(e)Actual gain in noninverting amplifier is\",round(actualAcl1,0)\n",
+ "print\"Actual gain in inverting amplifier is\",round(actualAcl1_,2)\n",
+ "\n",
+ "\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a)Actual gain in noninverting amplifier is 0.99\n",
+ "Actual gain in inverting amplifier is -0.98\n",
+ "(b)Actual gain in noninverting amplifier is 9.09\n",
+ "Actual gain in inverting amplifier is -9.01\n",
+ "(c)Actual gain in noninverting amplifier is 50.0\n",
+ "Actual gain in inverting amplifier is -49.75\n",
+ "(d)Actual gain in noninverting amplifier is 90.91\n",
+ "Actual gain in inverting amplifier is -90.83\n",
+ "(e)Actual gain in noninverting amplifier is 99.0\n",
+ "Actual gain in inverting amplifier is -99.0\n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 10.6 Page No 283"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "Ri=10.0 #Kohm\n",
+ "Rf=Ri\n",
+ "B=10**6 #Hz\n",
+ "\n",
+ "#Calculation\n",
+ "#(a)\n",
+ "Acl1=-Rf/Ri\n",
+ "fh1=B/((Ri+Rf)/Ri)\n",
+ "\n",
+ "#(b)\n",
+ "ACl2=(Ri+Rf)/Ri\n",
+ "\n",
+ "#(c)\n",
+ "Acl3=1 #Voltage follower gain\n",
+ "Rf2=0\n",
+ "Ri2=1\n",
+ "fh2=B/((Ri2+Rf2)/Ri2)\n",
+ "\n",
+ "#Resilt\n",
+ "print\"(a)The voltage gain is\",Acl1\n",
+ "print\"bandwidth is\",fh1/1000,\"khz\"\n",
+ "print\"(b)The voltage gain is\",ACl2\n",
+ "print\"(c)The voltage gain is\",Acl3\n",
+ "print\"bandwidth is\",fh2/1000000,\"Mhz\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a)The voltage gain is -1.0\n",
+ "bandwidth is 500.0 khz\n",
+ "(b)The voltage gain is 2.0\n",
+ "(c)The voltage gain is 1\n",
+ "bandwidth is 1 Mhz\n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 10.7 Page No 285"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "V=10 #V\n",
+ "slewrate=0.5 #per microsecond\n",
+ "\n",
+ "#Calculation\n",
+ "t=V/slewrate\n",
+ "\n",
+ "#Result\n",
+ "print\"The time taken is\",t,\"microsecond\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ " The time taken is 20.0 microsecond\n"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 10.8 Page No 286"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "slewrate=0.5 #per microsecond\n",
+ "V1=10.0 #Peak voltage\n",
+ "V2=1\n",
+ "\n",
+ "\n",
+ "#Calculation\n",
+ "fmax1=slewrate*1000/(6.28*V1)\n",
+ "fmax2=slewrate*1000/(6.28*V2)\n",
+ "\n",
+ "#Result\n",
+ "print\"(a)maximum frenquency is\",round(fmax1,1),\"KHz\"\n",
+ "print\"(b)maximum frenquency is\",round(fmax2,0),\"KHz\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a)maximum frenquency is 8.0 KHz\n",
+ "(b)maximum frenquency is 80.0 KHz\n"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 10.9 Page No 287"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "B1=500 #Khz, bandwidth\n",
+ "gain1=-1 #Gain for inverting amplifier\n",
+ "gain2=2 #Gain for non-inverting amplifier\n",
+ "slewrate=0.5 #per micros\n",
+ "V=10 #V\n",
+ "\n",
+ "#Calculation\n",
+ "Vopmax=slewrate*10**6/(6.28*B1*10**3)\n",
+ "fmax=slewrate*1000/(6.28*V)\n",
+ "\n",
+ "#Result\n",
+ "print\"Maximum operating voltage is\",round(Vopmax*1000,1),\"mV\"\n",
+ "print\"maximum frenquency is\",round(fmax,0),\"Khz\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Maximum operating voltage is 159.2 mV\n",
+ "maximum frenquency is 8.0 Khz\n"
+ ]
+ }
+ ],
+ "prompt_number": 11
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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