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diff --git a/Non_Conventional_Energy_Resources/Chapter11.ipynb b/Non_Conventional_Energy_Resources/Chapter11.ipynb
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+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:131e5807eda8c30572547a9b8e6ec8831945c814f15b621bc05038f1dbaad1ff"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter11:Small Hydro Resources"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Ex11.1:pg-355"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math\n",
+      "# given data\n",
+      "rho=996 # density in kg/m^3\n",
+      "effi=0.55 # oveall efficiency\n",
+      "Q=100/1000.0 # discharge in m^3/sec\n",
+      "h=30 # gross head in m\n",
+      "g=9.81 # gravitational acceleration in m/sec^2\n",
+      "\n",
+      "\n",
+      "Pnet=effi*rho*Q*g*h/1000 # net power in watts\n",
+      "print \"Power available is\",round(Pnet,3),\"kilowatts\"\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Power available is 16.122 kilowatts\n"
+       ]
+      }
+     ],
+     "prompt_number": 7
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Ex11.2:pg-356"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math\n",
+      "# given data\n",
+      "pf=0.8 # power factor\n",
+      "Load=3 # load in kW\n",
+      "V=230 # voltage of kettle in V\n",
+      "P=500 # power of kettle in W\n",
+      "VA=pf*Load # VA load in kVA\n",
+      "C=4200 # specific heat of water in j/kg-K\n",
+      "T=45-20 # temperature difference in degree celsius\n",
+      "\n",
+      "VAR=VA*1.6 # net required VAR rating thus 60% extra capacity\n",
+      "\n",
+      "R=(V**2)/P # resistance by kettle in ohms\n",
+      "\n",
+      "Po=7*(V**2)/R # power dissipation in W for 7 elements\n",
+      "\n",
+      "print \"7 elements are connected in parallel\"\n",
+      "\n",
+      "Q=Load*1000.0/(C*T) # flow rate in kg/sec\n",
+      "\n",
+      "print\"The required flow rate is \",round(Q,5),\"litre/sec\"\n",
+      "\n",
+      "\n",
+      "\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "7 elements are connected in parallel\n",
+        "The required flow rate is  0.02857 litre/sec\n"
+       ]
+      }
+     ],
+     "prompt_number": 11
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file