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+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:60e1b4f69268bf5ef981c421da464c3f2155bd9dcb0f2936b64236297523b2ca"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 10 Nuclear Fission and Fusion"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 10.1 Page no 351"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "c=3*10**8                       #m/s\n",
+      "m=3.6*10**-3                   #Kg\n",
+      "a=36000\n",
+      "\n",
+      "#Calculation\n",
+      "E=m*c**2\n",
+      "E1=E/(a*10**3)\n",
+      "\n",
+      "#Result\n",
+      "print\"Energy is\", E1*10**-6,\"*10**7 Kilo watt-hrs\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Energy is 9.0 *10**7 Kilo watt-hrs\n"
+       ]
+      }
+     ],
+     "prompt_number": 7
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 10.2 Page no 352"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "mn=1.6747*10**-27\n",
+      "mp=1.6725*10**-27\n",
+      "me=9*10**-31\n",
+      "c=3*10**8\n",
+      "e=1.6*10**-19\n",
+      "\n",
+      "#Calculation\n",
+      "m=mn-(mp+me)\n",
+      "E=(m*c**2)/e\n",
+      "\n",
+      "#Result\n",
+      "print\"Energy produced is\", round(E*10**-6,2),\"Mev\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Energy produced is 0.73 Mev\n"
+       ]
+      }
+     ],
+     "prompt_number": 16
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 10.3 Page no 352"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given\n",
+      "P=3.2*10**7                   #Watts\n",
+      "e=1.6*10**-13\n",
+      "E1=200.0\n",
+      "a=1000\n",
+      "N=6.0*10**23\n",
+      "A=235\n",
+      "\n",
+      "#Calculation\n",
+      "E=P/e\n",
+      "n=E/E1\n",
+      "n1=n*a*3600\n",
+      "m=n1*A/N\n",
+      "\n",
+      "#Result\n",
+      "print\"Number of fission occuring in the reactor/sec is\", n\n",
+      "print\"Mass of U235 used in 1000 hrs is\",m*10**-3,\"Kg\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Number of fission occuring in the reactor/sec is 1e+18\n",
+        "Mass of U235 used in 1000 hrs is 1.41 Kg\n"
+       ]
+      }
+     ],
+     "prompt_number": 28
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file