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diff --git a/Microelectronic_Circuits_by_A.S._Sedra_and_K.C._Smith/Chapter14.ipynb b/Microelectronic_Circuits_by_A.S._Sedra_and_K.C._Smith/Chapter14.ipynb new file mode 100755 index 00000000..5bdfcf5d --- /dev/null +++ b/Microelectronic_Circuits_by_A.S._Sedra_and_K.C._Smith/Chapter14.ipynb @@ -0,0 +1,269 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:04c770610947ad7b99d743d99cd805c99779dc1a6616f379e3e115323e61d9f6"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter14:Output Stages and Power Amplifiers"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex14.1:pg-1239"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Example 14.1 To design a Class B Output Amplifier\n",
+ "\n",
+ "P_L=20; # Average power (W) \n",
+ "R_L=8; # Load resistance (ohm)\n",
+ "V_o=math.sqrt(2*P_L*R_L); \n",
+ "print round(V_o,1),\"= Supply voltage required (V)\"\n",
+ "V_CC=23; # We select this voltage (V)\n",
+ "I_o=V_o/R_L;\n",
+ "print round(I_o,2),\"= Peak current drawn from each supply (A)\"\n",
+ "P_Sav=V_CC*I_o/math.pi; # P_S+ = P_S- = P_Sav\n",
+ "P_S=P_Sav+P_Sav; # Total supply power\n",
+ "print round(P_S,1),\"= The total power supply (W)\"\n",
+ "n=P_L/P_S; # n is power conversion efficiency\n",
+ "print round(n*100),\" = Power conversion efficiency %\"\n",
+ "P_DPmax=V_CC**2/(math.pi**2*R_L);\n",
+ "P_DNmax=P_DPmax;\n",
+ "print round(P_DPmax,1),\"= Maximun power dissipated in each transistor (W)\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "17.9 = Supply voltage required (V)\n",
+ "2.24 = Peak current drawn from each supply (A)\n",
+ "32.7 = The total power supply (W)\n",
+ "61.0 = Power conversion efficiency %\n",
+ "6.7 = Maximun power dissipated in each transistor (W)\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex14.2:pg-1245"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Example 14.2 To determine quiescent current and power\n",
+ "# Consider Class AB Amplifier\n",
+ "V_CC=15; # (V)\n",
+ "R_L=100; # (ohm)\n",
+ "v_O=-10; # Amplitude of sinusoidal output voltage (V)\n",
+ "I_S=10**-13; # (A)\n",
+ "V_T=25*10**-3; # (V)\n",
+ "B=50; # Beta value\n",
+ "i_Lmax=10/(0.1*10**3); # Maximum current through Q_N (A)\n",
+ "# Implies max base curent in Q_N is approximately 2mA\n",
+ "I_BIAS=3*10**-3; # We select I_BIAS=3mA in order to maintain a minimum of 1mA through the diodes\n",
+ "I_Q=9*10**-3; # The area ratio of 3 yeilds quiescent current of 9mA\n",
+ "P_DQ=2*V_CC*I_Q;\n",
+ "print round(P_DQ*1000),\"= Quiescent power dissipation (mW)\"\n",
+ "#For v_O=0V base current of Q_N is 9/51=0.18 mA\n",
+ "# Leaves a current of 3-0.18=2.83mA to flow through the diodes\n",
+ "I_S= (10**-13)/3; # Diodes have I_S = (1*10**-13)/3 \n",
+ "V_BB=2*V_T*math.log((2.83*10**-3)/I_S);\n",
+ "print round(V_BB,2),\"= V_BB (V) for v_O = 0V\"\n",
+ "# For v_O=+10V, current through the diodes will decrease to 1mA\n",
+ "V_BB=2*V_T*math.log((1*10**-3)/I_S);\n",
+ "print round(V_BB,2),\"= V_BB (V) for v_O = +10V\"\n",
+ "# For v_O=-10V , Q_N will conduct very small current thus base current is negligible\n",
+ "# All of the I_BIAS(3mA) flows through the diodes\n",
+ "V_BB=2*V_T*math.log((3*10**-3)/I_S);\n",
+ "print round(V_BB,2),\"= V_BB (V) for v_O = -10V\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "270.0 = Quiescent power dissipation (mW)\n",
+ "1.26 = V_BB (V) for v_O = 0V\n",
+ "1.21 = V_BB (V) for v_O = +10V\n",
+ "1.26 = V_BB (V) for v_O = -10V\n"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex14.3:pg-1248"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Example 14.3 Redesign the output stage of Example 14.2\n",
+ "V_T=25*10**-3; # (V)\n",
+ "I_S=10**-14; # (A)\n",
+ "I_Q=2*10**-3; # Required quiescent current (A)\n",
+ "# We select I_BIAS=3mA which is divided between I_R and I_C1\n",
+ "# Thus we select I_R=0.5mA and I_C1=2.5mA\n",
+ "V_BB=2*V_T*math.log(I_Q/10**-13);\n",
+ "print round(V_BB,2),\"=V_BB (V)\"\n",
+ "I_R=0.5*10**-3;\n",
+ "R1plusR2=V_BB/I_R; # R1plusR2 = R_1+R_2\n",
+ "I_C1=2.5*10**-3;\n",
+ "V_BE1=V_T*math.log(I_C1/I_S);\n",
+ "print round(V_BE1,2),\"= V_BE1 (V)\"\n",
+ "R_1=V_BE1/I_R;\n",
+ "print round(R_1/1000,2),\"R_1 (Kohm)\"\n",
+ "R_2=R1plusR2-R_1;\n",
+ "print round(R_2/1000,2),\"R_2 (Kohm)\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "1.19 =V_BB (V)\n",
+ "0.66 = V_BE1 (V)\n",
+ "1.31 R_1 (Kohm)\n",
+ "1.06 R_2 (Kohm)\n"
+ ]
+ }
+ ],
+ "prompt_number": 10
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex14.4:pg-1251"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Example 14.4 To determine thermal resistance, junction temperature \n",
+ "# Consider BJT with following specifications\n",
+ "P_D0=2; # Maximum power dissipation (W)\n",
+ "T_A0=25.0; # Ambient temperature (degree celcius)\n",
+ "T_Jmax=150.0; # maximum junction temperature (degree celcius) \n",
+ "\n",
+ "# 14.4a \n",
+ "theta_JA=(T_Jmax-T_A0)/P_D0; # Thermal resistance\n",
+ "print theta_JA,\"is The thermal resistance (degree celsius/W)\"\n",
+ "\n",
+ "# 14.4b\n",
+ "T_A=50.0; # (degree celcius)\n",
+ "P_Dmax=(T_Jmax-T_A)/theta_JA; \n",
+ "print P_Dmax,\"is Maximum power that can be dissipated at an ambient temperature of 50 degree celsius (W)\"\n",
+ "\n",
+ "# 14.4c\n",
+ "T_A=25.0; # (degree celcius) \n",
+ "P_D=1; # (W)\n",
+ "T_J=T_A+theta_JA*P_D;\n",
+ "print T_J,\"is Junction temperature (degree celcius) if the device is operating at T_A=25 degree celsius and is dissipating 1W\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "62.5 is The thermal resistance (degree celsius/W)\n",
+ "1.6 is Maximum power that can be dissipated at an ambient temperature of 50 degree celsius (W)\n",
+ "87.5 is Junction temperature (degree celcius) if the device is operating at T_A=25 degree celsius and is dissipating 1W\n"
+ ]
+ }
+ ],
+ "prompt_number": 11
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex14.5:pg-1253"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Example 14.5 To determine the maximum power dissipated \n",
+ "# Consider a BJT with following specifications\n",
+ "T_Jmax=150; # (degree celcius)\n",
+ "T_A=50; # (degree celcius)\n",
+ "\n",
+ "# 14.5a\n",
+ "theta_JA=62.5; # (degree celcius/W)\n",
+ "P_Dmax=(T_Jmax-T_A)/theta_JA;\n",
+ "print round(P_Dmax,2),\"is The maximum power (W) that can be dissipated safely by the transistor when operated in free air\"\n",
+ "\n",
+ "#14.5b\n",
+ "theta_CS=0.5; # (degree celcius/W)\n",
+ "theta_SA=4; # (degree celcius/W)\n",
+ "theta_JC=3.12; # (degree celcius/W)\n",
+ "theta_JA=theta_JC+theta_CS+theta_SA;\n",
+ "P_Dmax=(T_Jmax-T_A)/theta_JA\n",
+ "print round(P_Dmax,1),\"is The maximum power (W) that can be dissipated safely by the transistor when operated at an ambient temperature of 50 degree celcius but with a heat sink for which theta_CS= 0.5 (degree celcius/W) and theta_SA = 4 (degree celcius/W) (W)\"\n",
+ "\n",
+ "# 14.5c\n",
+ "theta_CA=0 # since infinite heat sink\n",
+ "P_Dmax=(T_Jmax-T_A)/theta_JC;\n",
+ "print round(P_Dmax),\"is The maximum power (W) that can be dissipated safely if an infinite heat sink is used and T_A=50 (degree celcius)\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "1.6 is The maximum power (W) that can be dissipated safely by the transistor when operated in free air\n",
+ "13.1 is The maximum power (W) that can be dissipated safely by the transistor when operated at an ambient temperature of 50 degree celcius but with a heat sink for which theta_CS= 0.5 (degree celcius/W) and theta_SA = 4 (degree celcius/W) (W)\n",
+ "32.0 is The maximum power (W) that can be dissipated safely if an infinite heat sink is used and T_A=50 (degree celcius)\n"
+ ]
+ }
+ ],
+ "prompt_number": 16
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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