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+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:32762f08f8decdcb2472567b8bb56aa30546cb37837b4beaf1c667dc49e7e0c1"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter11:Memory and Advanced\n",
+      "Digital Circuits"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Ex11.1:pg-1017"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "# The problem is solved using Hit and Trial as well as approximation thus no programming is needed hence the example is skipped"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [],
+     "prompt_number": 2
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Ex11.2:pg-1032"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "# Example 11.2 Design of two-stage CMOS op-amp \n",
+      "\n",
+      "uC_n=50*10**-6; # u_n*C_ox (A/V**2)\n",
+      "uC_p=20.0*10**-6; # u_p*C_ox (A/V**2)\n",
+      "V_tn0=1.0; # (V)\n",
+      "V_tp0=-1; # (V)\n",
+      "fie_f=0.6/2; # (V)\n",
+      "y=0.5; # (V**1/2)\n",
+      "V_DD=5; # (V)\n",
+      "W_n=4*10.0**-6; # (m)\n",
+      "L_n=2*10.0**-6; # (m)\n",
+      "W_p=10*10**-6; # (m)\n",
+      "L_p=2*10.0**-6; # (m)\n",
+      "W=10*10**-6; # (m)\n",
+      "L=10*10.0**-6; # (m)\n",
+      "C_B=1*10.0**-12; # bit line capacitance (F)\n",
+      "deltaV=0.2; # 0.2 V decrement\n",
+      "WbyL_eq=1/(L_p/W_p+L_n/W_n); # WbyL_eq=(W/L)_eq\n",
+      "# Equivalent transistor will operate in saturation\n",
+      "I=(uC_n*WbyL_eq*(V_DD-V_tn0)**2)/2\n",
+      "r_DS=1/(uC_n*(W_n/L_n)*(V_DD-V_tn0));\n",
+      "v_Q=r_DS*I; # v_Q=r_DS*I\n",
+      "I_5=0.5*10.0**-3; # (A) \n",
+      "deltat=C_B*deltaV/I_5;\n",
+      "print deltat*1e9, \"is The time (ns) required to develop an output voltage of 0.2V\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "0.4 is The time (ns) required to develop an output voltage of 0.2V\n"
+       ]
+      }
+     ],
+     "prompt_number": 15
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Ex11.3:pg-1041"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "# Example 11.3 : Time required for v_B to reach 4.5V\n",
+      "# Consider sense-amplifier circuit\n",
+      "uC_n=50*10**-6; #uC_n=u_n*C_ox (A/V**2)\n",
+      "uC_p=20*10**-6; #uC_p=u_p*C_ox (A/V**2)\n",
+      "W_n=12*10**-6; # (m)\n",
+      "L_n=4*10**-6; # (m)\n",
+      "W_p=30*10**-6; # (m)\n",
+      "L_p=4*10**-6; # (m)\n",
+      "v_B=4.5; # (V)\n",
+      "C_B=1*10**-12; # (F)\n",
+      "V_GS=2.5; # (V)\n",
+      "V_t=1; # (V)\n",
+      "deltaV=0.1; # (V)\n",
+      "g_mn=uC_n*(W_n/L_n)*(V_GS-V_t); # (A/V)\n",
+      "g_mp=uC_p*(W_p/L_p)*(V_GS-V_t); # (A/V)\n",
+      "G_m=g_mn+g_mp; # (A/V)\n",
+      "T=C_B/G_m; # (s)\n",
+      "deltat=T*(math.log(v_B/V_GS)-math.log(deltaV));\n",
+      "print round(deltat*1e9,1),\" is The time for v_B to reach 4.5V (s)\"\n",
+      "# The answer in the textbook is slightly different due to approximation"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "6.4  is The time for v_B to reach 4.5V (s)\n"
+       ]
+      }
+     ],
+     "prompt_number": 18
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file